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Involve exponential growth. Suppose a bacterial culture doubles in population every 4 hours. If the population is initially \(100,\) find an equation for the population at any time. Determine when the population will reach 6000

Short Answer

Expert verified
The population at any time can be represented by the function \(P(t) = 100 * 2^{t/4}\). It will take approximately 22.46 hours for the population to reach 6000.

Step by step solution

01

Identify the initial conditions

The population of bacteria starts at 100. So, the initial size or P0 is 100. Additionally, it's given that the population doubles every 4 hours, which is the doubling time (td).
02

Formulate the exponential growth function

Using the formula for exponential growth, \(P(t) = P0 * 2^{(t/td)}\), the population at any time \(t\) can be calculated. Substitute the values \(P0 = 100\) and \(td = 4\) into this formula to obtain the exponential growth function. This gives \(P(t) = 100 * 2^{(t/4)}\)
03

Calculate the time when the population becomes 6000

Set the equation \(P(t) = 6000\), and solve for \(t\). \(6000 = 100 * 2^{t/4}\).
04

Solve the exponential equation

First, divide both sides of the equation by 100, leading to 60 = \(2^{t/4}\). Taking the logarithm base 2 on both sides gives \(log_2(60) = t/4\). Solve for \(t\) to get \(t = 4 * log_2(60)\), which means it will take approximately 22.46 hours for the population to reach 6000.
05

Interpret the results

The population growth of the bacteria can be represented by the function \(P(t) = 100 * 2^{t/4}\), and it will take around 22.46 hours for the population to increase to 6000.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bacterial Population Growth
Understanding how bacterial populations increase is vital in fields such as microbiology and environmental science. The key characteristic of bacterial population growth is that it typically follows an exponential pattern, whereby the number of bacteria doubles after a certain period called the 'doubling time'.

Considering a specific example from a textbook exercise can shed light on this. In a scenario where a bacterial culture starts with an initial population of 100 and doubles every 4 hours, the population at any time can be represented using an exponential growth model. This model casts a clear picture on how fast bacteria can multiply under ideal conditions, and it's a fundamental concept in forecasting the growth of bacterial colonies over time.

It's not just about the numbers increasing; it's about the rate at which they increase. This exponential pattern is why bacterial infections can become serious so quickly if left untreated, and it's also why managing the growth of bacteria in environmental systems is so crucial to maintaining balance.
Exponential Growth Function
Exponential growth functions are mathematical representations of phenomena that grow by a constant rate in relation to their current value. This type of growth is identified with the formula \( P(t) = P_0 \cdot 2^{(t/td)} \), where \( P(t) \) represents the population at time \( t \), \( P_0 \) is the initial population, and \( td \) is the doubling time.

The exercise we consider illustrates a bacterial population starting with 100 individuals and doubling every 4 hours, leading to an exponential growth function of \( P(t) = 100 \cdot 2^{(t/4)} \).

Visualizing Exponential Growth

Imagine plotting this on a graph, with time on the x-axis and population size on the y-axis; the line would curve upwards sharply, demonstrating how the population size explodes over time. This steep increasing curve is a hallmark of exponential growth, and it highlights how initial small populations can grow to large numbers very rapidly, emphasizing the power of exponential factors in real-world applications such as finance, population studies, and biological processes.
Solving Exponential Equations
Solving exponential equations is essential for predicting when a population, like our bacterial colony, will hit a certain number. In our exercise, we are given that the population will reach 6000, and we are asked to find when that will happen, which involves solving the equation for \( t \).

This calculation is achieved by setting \( P(t) = 6000 \) and isolating \( t \) in the equation \( 6000 = 100 \cdot 2^{t/4} \), eventually leading to \( t = 4 \cdot \log_2(60) \).

Navigating the Logarithmic Step

It may seem daunting, but logarithms are just another function, like squaring or taking a square root, but they specifically 'undo' exponentiation. To solve for \( t \), we use the properties of logarithms, which allow us to compare the exponents and find the time required for the bacterial population to reach 6000. This step tells us that approximately 22.46 hours are needed for such an increase, showcasing the practical application of solving exponential equations in determining the time frames of exponential growth processes.

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