Chapter 6: Problem 12
Evaluate the integral. $$\int_{0}^{\pi / 4} \sec ^{2} x e^{\tan x} d x$$
Short Answer
Expert verified
The value of the integral is \( e - 1 \)
Step by step solution
01
Define Substitution
Define the substitution \(u=\tan(x)\). Then compute the derivative of \(u\) with respect to \(x\), which is \(du/\sec^2(x)dx\). When re-arranged, the differential term in the integral transforms into \(dx=du/\sec^2(x)\). This changes the integral into \( \int e^u du\), which is easier to solve.
02
Replace the Integration Interval
Replace the interval of integration from [0, π/4] to [0, 1] due to the substitution \( u = \tan(x)\). Within this interval for \( x\), the tangent function increases from 0 to 1.
03
Perform the Integral
So the integral to be solved becomes \( \int_{0}^{1} e^u du \). The evaluation of this integral using standard rules results in \( [e^u]_{0}^{1} \), which simplifies down to \( e^1 - e^0 = e - 1 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
U-Substitution
The technique known as u-substitution is a method used in integral calculus to simplify the process of integration, especially when dealing with more complicated expressions. It is particularly useful when an integrand is the product of a function and its derivative or can be manipulated to resemble such a form. The basic idea is to substitute a part of the integral (call it u) with a new variable, making the integral easier to evaluate.
To perform u-substitution, we typically follow these steps:
To perform u-substitution, we typically follow these steps:
- Identify a section of the integral to replace with u, ideally so that du is also present in the integral.
- Compute du, the derivative of u with respect to x, and solve for dx.
- Replace all occurrences of the chosen section with u and dx with du, thus rewriting the integral in terms of u.
- Change the limits of integration if performing a definite integral to reflect the new variable u.
- Evaluate the new integral.
- Substitute back to the original variable if needed.
Definite Integral
The definite integral of a function provides us with the net area under the curve of that function between two points on the x-axis. These two points are referred to as the lower and upper limits of integration. The evaluation of a definite integral results in a real number that can represent physical quantities like area, volume, or other concepts depending on the context of the problem.
To evaluate a definite integral, we:
To evaluate a definite integral, we:
- Find an antiderivative (also called the indefinite integral) of the function being integrated.
- Apply the limits of integration to this antiderivative, which involves substituting these limits into the antiderivative.
- Calculate the difference between the upper limit's substitution result and the lower limit's substitution result.
Exponential Functions
An exponential function in mathematics can be recognized by its base raised to a variable exponent, typically represented as f(x) = a^x, where a is a constant base and x is the exponent. One of the most important and widely used exponential functions is e^x, where e is Euler’s number approximately equal to 2.71828. This function is unique because it is its own derivative, which makes it incredibly useful in various fields, including calculus and real-world applications like compounding interest and population growth.
When integrating an exponential function, the general form of the antiderivative of e^x is also e^x, plus a constant of integration in the case of an indefinite integral. For a definite integral, the result is the difference in the values of e^x evaluated at the upper and lower limits of integration. In our exercise, after u-substitution, we integrate e^u over the range 0 to 1, leading us to simply find the difference e^1 - e^0, which neatly evaluates to e - 1.
When integrating an exponential function, the general form of the antiderivative of e^x is also e^x, plus a constant of integration in the case of an indefinite integral. For a definite integral, the result is the difference in the values of e^x evaluated at the upper and lower limits of integration. In our exercise, after u-substitution, we integrate e^u over the range 0 to 1, leading us to simply find the difference e^1 - e^0, which neatly evaluates to e - 1.