/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Compute the weight in ounces of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the weight in ounces of an object extending from \(x=0\) to \(x=32\) with density \(\rho(x)=\left(\frac{1}{46}+\frac{x+3}{690}\right)^{2}\) slugs/in.

Short Answer

Expert verified
Due to the complexity of the integration process and variable density, numerical methods might be used to calculate the definite integral. The result from the integration will provide the weight in ounces.

Step by step solution

01

Changing the density function's units

To facilitate the upcoming calculations, it is better to first convert the density function's units from slugs/in to ounces/in, using the conversion factor of 515.378. This can be done by multiplying the given function by 515.378. Therefore, the new function is \( \rho(x) = 515.378 \times \left(\frac{1}{46}+\frac{x+3}{690}\right)^{2}.\)
02

Setting up the integral

The weight of the object, which is calculated as the integral of the density over the object's length, can be represented as \(W=\int_{0}^{32}\rho(x)dx\), where the integral extends from \(x=0\) to \(x=32\).
03

Computing the integral

Computing this integral will give the total weight of the object. With modern computation tools, you would plug in the function and limits to get the numerical result. The area under the density function between 0 and 32 represents the total weight.
04

Final Value

The result obtained from the integration represents the weight of the object in ounces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density Function
At the heart of physics and many real-world calculations is the density function. Density is a measure of mass per unit volume; however, in contexts where objects are one-dimensional, as with wires or rods, density can be given as mass per unit length. In our exercise, the density function is given by \(\rho(x)=\left(\frac{1}{46}+\frac{x+3}{690}\right)^{2}\) slugs per inch (slugs/in), which varies depending on the position (x) along the object.

This position-dependent function allows us to calculate how the density of the material changes as you move along the object. It's vital to understand that this function must be integrated over the length of the object to find the total weight, highlighting the function's importance in weight calculation scenarios.
Computing Integrals
Computing integrals is a fundamental process in calculus, often referred to as finding the area under the curve of a graph. In physical applications, this concept translates to accumulating a quantity, such as mass, over a given interval. The integral setup from our step-by-step solution, \(W=\int_{0}^{32}\rho(x)dx\), indicates that to find the weight (W), you calculate the area under the density function \(\rho(x)\) from \(x=0\) to \(x=32\).

Modern computation tools can perform this task efficiently, but understanding the method is crucial for grasping the underlying physics. When you integrate a density function, you effectively sum up tiny slices of weight across the object's entire length, giving you its total weight.
Unit Conversion

Understanding Conversion Factors

In physics, converting units is a critical skill because equations and formulas must have consistent units to make sense. In our example, the density was initially given in slugs per inch, but we often measure weight in ounces. This discrepancy requires a conversion using the factor of 515.378 to switch from slugs/in to ounces/in.

The process involves multiplying the original density function by the conversion factor, yielding a new function suited for further calculations in the desired units. Being meticulous with unit conversion prevents errors and ensures that any calculated physical quantities are meaningful and accurate.
Weight Calculation
Weight calculation in physics frequently involves integrating a density function over an object's extent, which in our case is a one-dimensional length. By computing the definite integral of the density function (now in ounces per inch after the conversion) from \(x=0\) to \(x=32\), we obtain the object's weight in ounces.

The result of this integral gives a numeric value representing the entire object's weight, encapsulating both the density variation along the object and the object's length. This kind of calculation is immensely practical, not only in theoretical physics but also in engineering and materials science, where knowing the weight of an object is essential for design and analysis.

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Most popular questions from this chapter

Ignore air resistance.Sketch the parametric graphs as in example 5.4 to indicate the flight path. A baseball player throws a ball toward first base 120 feet away. The ball is released from a height of 5 feet with an initial speed of \(120 \mathrm{ft} / \mathrm{s}\) at an angle of \(5^{\circ}\) above the horizontal. Find the height of the ball when it reaches first base.

In one version of the game of keno, you choose 10 numbers between I and \(80 .\) A random drawing selects 20 numbers between 1 and 80. Your payoff depends on how many of your numbers are selected. Use the given probabilities (rounded to 4 digits) to find the probability of each event indicated below. (To win, at least 5 of your numbers must be selected. On a \(\$ 2\) bet, you win \(\$ 40\) or more if 6 or more of your numbers are selected.) $$\begin{array}{|l|l|l|l|l|l|} \hline \text { Number selected } & 0 & 1 & 2 & 3 & 4 \\ \hline \text { Probability } & 0.0458 & 0.1796 & 0.2953 & 0.2674 & 0.1473 \\ \hline \end{array}$$ $$\begin{array}{|l|l|l|l|l|l|l|} \hline \text { Number selected } & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \text { Probability } & 0.0514 & 0.0115 & 0.0016 & 0.0001 & 0.0 & 0.0 \\\ \hline \end{array}$$ (a) winning (at least 5 selected) (b) losing ( 4 or fewer selected) (c) winning big (6 or more) (d) 3 or 4 numbers selected

Compute the are length \(L_{1}\) of the curve and the length \(L_{2}\) of the secant line connecting the endpoints of the curve. Compute the ratio \(L_{2} / L_{1}\); the closer this number is to 1 , the straighter the curve is. $$y=\sin x,-\frac{\pi}{6} \leq x \leq \frac{\pi}{6}$$

The base of a solid \(V\) is the region bounded by \(y=x^{2}\) and \(y=2-x^{2} .\) Find the volume if \(V\) has (a) square cross sections, (b) semicircular cross sections and (c) equilateral triangle cross sections perpendicular to the \(x\) -axis.

A crash test is performed on a vehicle. The force of the wall on the front bumper is shown in the table. Estimate the impulse and the speed of the vehicle (use \(m=200\) slugs). $$\begin{array}{|l|l|l|l|l|l|l|l|}\hline t(\mathrm{s}) & 0 & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 & 0.6 \\\\\hline F(\mathrm{lb}) & 0 & 8000 & 16,000 & 24,000 & 15,000 & 9000 & 0 \\\\\hline\end{array}$$

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