Chapter 4: Problem 71
Derive the formulas \(\int e^{x} d x=e^{x}+c\) and \(\int e^{-x} d x=-e^{-x}+c\)
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Chapter 4: Problem 71
Derive the formulas \(\int e^{x} d x=e^{x}+c\) and \(\int e^{-x} d x=-e^{-x}+c\)
These are the key concepts you need to understand to accurately answer the question.
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Evaluate the definite integral. $$\int_{1}^{4} \frac{x-1}{\sqrt{x}} d x$$
Evaluate the integral exactly, if possible. Otherwise, estimate it numerically. (a) \(\int_{0}^{\pi} \sin x^{2} d x\) (b) \(\int_{0}^{\pi} x \sin x^{2} d x\)
In this exercise, we guide you through a different proof of \(\lim _{h \rightarrow 0} \frac{e^{h}-1}{h}=1 .\) Start with \(f(x)=\ln x\) and the fact that \(f^{\prime}(1)=1 .\) Using the alternative definition of derivative, we write this as \(f^{\prime}(1)=\lim _{x \rightarrow 1} \frac{\ln x-\ln 1}{x-1}=1 .\) Explain why this implies that \(\lim _{x \rightarrow 1} \frac{x-1}{\ln x}=1 .\) Finally, substitute \(x=e^{h}.\)
Let \(f(x)=\left\\{\begin{array}{cl}x & \text { if } x<2 \\ x+1 & \text { if } x \geq 2\end{array} \text { and define } F(x)=\int_{0}^{x} f(t) d t\right.\) Show that \(F(x)\) is continuous but that it is not true that \(F^{\prime}(x)=f(x)\) for all \(x .\) Explain why this does not contradict the Fundamental Theorem of Calculus.
In most of the calculations that you have done, it is true that the Trapezoidal Rule and Midpoint Rule are on opposite sides of the exact integral (i.e., one is too large, the other too small). Also, you may have noticed that the Trapezoidal Rule tends to be about twice as far from the exact value as the Midpoint Rule.Given this, explain why the linear combination \(\frac{1}{3} T_{n}+\frac{2}{3} M_{n}\) should give a good estimate of the integral. (Here, \(T_{n}\) represents the Trapezoidal Rule approximation using \(n\) partitions and \(M_{n}\) the corresponding Midpoint Rule approximation.)
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