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One of the two antiderivatives can be determined using basic algebra and the derivative formulas we have presented. Find the antiderivative of this one and label the other \(^{\text {*. }} \mathbf{N} / \mathbf{A}^{\mathbf{\prime}}\) $$\text { (a) } \int 2 \sec x \, d x$$ $$\text { (b) } \int \sec ^{2} x d x$$

Short Answer

Expert verified
The antiderivative of \(2 \sec x\) is \(2 \ln | \sec x + \tan x | + C\), and the antiderivative of \(\sec^2 x\) is \(\tan x + C\).

Step by step solution

01

Find the antiderivative of \(2 \sec x\)

To find the indefinite integral/antiderivative, we use the formula for the integral of \(\sec x\), i.e., \(\ln | \sec x + \tan x | + C\). Furthermore, given the integral is \(2 \sec x\), the integration is straightforward, i.e., \(2 \int \sec x dx\). So, \(\int 2 \sec x dx = 2 \ln | \sec x + \tan x | + C\).
02

Find the antiderivative of \(\sec^2 x\)

We know that the integral of \(\sec^2 x\) is \(\tan x + C\). Hence the antiderivative of \(\sec^2 x\) is \(\tan x + C\).
03

Labeling the antiderivatives

Now that we have computed the antiderivatives, we label them. We call \(2 \ln | \sec x + \tan x | + C\) as \(N/A'\) and \(\tan x + C\) as <*>.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite Integral
The indefinite integral, often symbolized by the integral sign \(\int\) followed by a function and the differential of a variable (such as \(dx\)), represents the collection of all antiderivatives of that function. It's crucial in calculus because it helps reverse the process of differentiation. If you have the derivative of a function, the indefinite integral allows you to find the original function (up to an added constant). The 'C' that appears in the solution represents a constant of integration, and it's needed because when you take the derivative of the antiderivalent, the constant disappears.

In the given exercise:\[\int 2 \sec x \, dx\] and \[\int \sec^2 x \, dx\], we're looking to find the original function before differentiation took place. The solutions provided follow established integration rules. For \(2 \sec x\), we use the known integral of \(\sec x\), and for \(\sec^2 x\), we capitalize on the fact that its antiderivative is a basic trigonometric function.
Trigonometric Integration
Trigonometric integration involves finding the antiderivative of trigonometric functions. This is a key area within calculus, especially when dealing with wave functions and periodic phenomena. The integration rules for trigonometric functions are derived from the derivatives of sine, cosine, secant, and other trigonometric functions.

In our specific case, we've used the formula for the integration of \(\sec x\), which is \(\ln | \sec x + \tan x | + C\). The technique often requires algebraic manipulation, and sometimes even parts and substitution methods, to express the function in a form that we can integrate directly.
Integration Formulas
Integration formulas are the backbone of solving calculus problems involving integrals. These formulas provide the set rules to directly integrate basic functions, including polynomials, trigonometric functions, exponentials, and more. Without memorizing or knowing where to find these formulas, solving integrals can be quite challenging.

For instance, the integral of \(2\sec x\) used the formula for \(\sec x\), and we simply multiplied the result by 2. Understanding and applying these formulas correctly is crucial for finding accurate solutions to indefinite integrals and is a powerful tool in the mathematician's arsenal.
Calculus
Calculus is a field of mathematics that studies how things change. It provides a framework for modeling systems in which there is change and a way to deduce the predictions of such models. Two major branches of calculus are differential calculus and integral calculus, which are connected by the fundamental theorem of calculus. Differential calculus concerns the concept of the derivative, which shows how a function changes at any given point. Integral calculus, on the other hand, is about the accumulation of quantities, such as areas under a curve, and is used to find antiderivatives represented as indefinite integrals.

Understanding calculus is essential, not just in mathematics, but in numerous fields including physics, engineering, economics, and beyond. It helps us understand and describe the world around us, from the motion of planets to the growth of investments.

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