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Find all critical numbers by hand. Use your knowledge of the type of graph (i.e., parabola or cubic) to determine whether the critical number represents a local maximum, local minimum or neither. $$f(x)=-x^{3}+6 x^{2}+2$$

Short Answer

Expert verified
The critical numbers are \(x = 0\) and \(x = 4\). \(x = 0\) is a local minimum and \(x = 4\) is a local maximum.

Step by step solution

01

Find the Derivative of the Function

Start off by obtaining the derivative of the function, \(f'(x)\), which shows the rate of change of the function at any given \(x\). Given the function \(f(x)=-x^{3}+6 x^{2}+2\), the derivative can be found by applying the power rule for differentiation which states if \(f(x) = x^n\), then \(f'(x) = n*x^{n-1}\). So, \(f'(x) = -3x^{2} + 12x\)
02

Find the Critical Numbers

Set the derivative equal to zero and solve for \(x\) to find the critical numbers. We have \(0 = -3x^{2} + 12x\). This can be simplified by factoring out an \(x\) to get \(0 = x(-3x + 12)\). So, the critical numbers are \(x = 0\) and \(x = 4\)
03

Classify the critical points

To determine whether the critical numbers represent a local maximum, local minimum or neither, take the second derivative of the function, \(f''(x)\), and substitute the critical numbers. The second derivative is obtained by differentiating \(f'(x)\) to give \(f''(x) = -6x + 12\). Substituting \(x = 0\) gives \(f''(0) = 12\) which is greater than 0, so \(x = 0\) is a local minimum. Substituting \(x = 4\) gives \(f''(4) = 12 - 24 = -12\) which is less than 0, so \(x = 4\) is a local maximum.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Numbers
Critical numbers are vital points in a function where the derivative is either zero or undefined. Think of these numbers as potential spots where a function can change its behavior, such as going from increasing to decreasing or vice versa.

To find critical numbers, locate where the derivative equals zero or is undefined. These points could be where local maxima or minima occur, though not always. Consider a function like a roaming roller coaster.
  • The peaks and valleys are the critical numbers.
  • Where it flattens out at the top or bottom can be crucial for deducing maximum or minimum points.
Knowing critical numbers is like having a map to see where these roller coaster rides become most thrilling.

In calculus exercises, identifying these points helps us further study changes or describe the graph's behavior.
Derivative
Derivatives are the heart of calculus. They measure how a function changes at any given point, like checking the speed of a car at a particular instant. When you take the derivative of a function, you're calculating its rate of change.

For example, with the function given as \[f(x) = -x^{3} + 6x^{2} + 2\],its derivative, \[f'(x) = -3x^{2} + 12x,\]reveals crucial details about its slope. Taking derivatives boils down to using rules like the power rule: if you have \[x^n,\]its derivative is \[n*x^{n-1}.\]
  • This applies swiftly to polynomials, guiding us to the necessary calculations.
A derivative switches from determining the static heights to gauging the dynamic change.

In calculus, this serves as a practical tool in discerning how quickly or slowly a function evolves, providing insights into the curve's shape and behavior.
Local Maximum
When a function reaches a 'crest,' it sometimes hits a local maximum. Imagine standing atop a hill; it's the highest point for miles around, but not necessarily the world's tallest peak. That's a local maximum.

To spot this in a function, if a critical point yields a negative second derivative, it suggests a local maximum. At our specific point, \[x = 4,\] with \[f''(4) = -12,\]it implies the crest of the curve before it dips down again.

When identifying these crests:
  • Check the derivative first, ensuring it's zero or nonexistent at the point.
  • Then use the second derivative test: if it's negative, the function is peaking there before descending.
Understanding local maxima in calculus empowers us to predict outcomes like profit peaks or optimal conditions for various scenarios.

These tell-tale points are about discerning the where, not the sharpness of a peak.
Local Minimum
Think about valleys in a landscape; this represents a local minimum on a graph. A local minimum is the lowest point the function hits over a small, localized domain. It's like standing in a dip reclaimed by its gentle neighbors.

Testing for a local minimum entails having a positive second derivative at the critical point. For example, with \[x = 0,\]we have a second derivative, \[f''(0) = 12,\]which is positive. This tells us the curve bottoms out before rising again.

When assessing a local minimum:
  • First ensure the derivative equals zero or is indeterminate.
  • Use the second derivative test, where a positive result means the function curves upward.
Valleys can reflect states like minimum costs or lowest energy levels in physical systems.Finding a local minimum means identifying these valleys on a graph, showing crucial insight into a function’s potential behavior.

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