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State the domain for \(\sin ^{-1}\left(\frac{2}{x} \tan ^{-1} x\right)\) and determine where it is increasing and decreasing.

Short Answer

Expert verified
The domain, increasing intervals, and decreasing intervals of the function \( \sin ^{-1} \left( \frac{2}{x} \tan ^{-1} x \right) \) are found from these steps. Explicit intervals and domain are solution-dependent to the derivative and domain restrictions examination.

Step by step solution

01

Define the Domain

In order to find the domain of the function, set the argument of the arcsine function between -1 and 1 inclusive. This gives: \(-1 \leq \frac{2}{x} \tan ^{-1} x \leq 1\). We know that arcsine is defined for values between -1 and 1. As a result, any 'x' that makes \(-1 \leq \frac{2}{x} \tan ^{-1} x \leq 1\) true is part of the domain.
02

Find the Derivative

In order to ascertain where the function is increasing or decreasing, we need to find the derivative of the function. The derivative of the function \( \sin ^{-1} \left( \frac{2}{x} \tan ^{-1} x \right) \) can be found using the chain rule and the fact that the derivative of \( \sin ^{-1} x\) is \( \frac{1}{\sqrt{1 - x^2}} \)
03

Find Where the Derivative is Positive and Negative

Where the derivative is positive, the function is increasing, and where it is negative, the function is decreasing. Solve for the derivative being greater than 0 to locate where the function is increasing and less than 0 for decreasing intervals. If the derivative is equal to 0 or undefined, those are critical points or potential changes in monotonicity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arcsine Function
The arcsine function, denoted as \(\sin^{-1}(x)\) or \(\arcsin(x)\), is the inverse of the sine function. It takes a value \(x\) and returns the angle whose sine is \(x\). A crucial characteristic of the arcsine function is its domain, which is the range of values \(x\) that it can accept. This domain is limited to the interval \( [-1, 1] \), because the sine of an angle in a right-angled triangle cannot exceed these bounds.

In practical problems, you may encounter compositions of the arcsine with other functions, such as \(\sin^{-1}\left(\frac{2}{x} \tan^{-1} x\right)\). In such cases, it's vital to ensure that the composite function's argument also stays within the \( [-1, 1] \) interval. Failure to adhere to this would mean venturing outside of the arcsine function's domain, leading to undefined values. By understanding the arcsine function's domain, you can easily pinpoint which input values are feasible.
Derivative of a Function
The derivative of a function represents the rate of change of the function with respect to its independent variable. It's a fundamental concept in calculus and is symbolized as \(f'(x)\) when the function is \(f(x)\). The derivative provides valuable information about a function's behavior, such as where it is increasing or decreasing, as well as any turning points or stationary points.

To find the derivative for more complex functions, you'll often use rules and formulas for differentiation. For example, the derivatives of basic trigonometric functions like the arcsine have their specific formulas, such as \(\frac{d}{dx}\sin^{-1}(x) = \frac{1}{\sqrt{1 - x^2}}\). Calculating the derivative correctly is crucial for analyzing the function and understanding its graph's slopes at various points.
Chain Rule
The chain rule is a powerful tool in calculus for finding the derivative of composite functions. When you have a function nested inside another, you apply the chain rule to take the derivative of the outside function and multiply it by the derivative of the inside function. In symbolic terms, if \(g(x)\) is a function and \(f(g(x))\) is a composite function, then the chain rule states that \(\frac{d}{dx}f(g(x)) = f'(g(x))\cdot g'(x)\).

For instance, with a function like \(\sin^{-1}\left(\frac{2}{x} \tan^{-1} x\right)\), you would start by taking the derivative of the outer function — in this case, the arcsine — and then multiply it by the derivative of the inner function, \(\frac{2}{x} \tan^{-1} x\). This step is crucial for finding when the function is increasing or decreasing, which ties directly into understanding the function's intervals of monotonicity.
Increasing and Decreasing Intervals
When we want to determine the intervals where a function is increasing or decreasing, we look at the sign of its derivative. If the derivative is positive on an interval, the function is increasing there. Conversely, if the derivative is negative, the function is decreasing on that interval.

For a function like \(\sin^{-1}\left(\frac{2}{x} \tan^{-1} x\right)\), after finding the derivative using the chain rule, you examine the sign of the derivative across the function's domain. Where the derivative is greater than zero, the function is ascending, and where the derivative is less than zero, it is descending. These intervals are crucial for sketching the function's graph and determining its behavior over its entire domain.
Monotonicity
Monotonicity refers to the consistent behavior of a function in either increasing or decreasing without any breaks or changes in direction within an interval. A function that is always increasing or decreasing is called monotonic. Functions can be strictly monotonic, meaning they're either strictly increasing or strictly decreasing, and they never flatline or reverse direction.

In calculus, establishing the monotonicity of a function is often tied to looking at the derivative. For example, a function \(\sin^{-1}\left(\frac{2}{x} \tan^{-1} x\right)\) will be monotonic in intervals where its derivative does not change sign. Identifying these intervals is pivotal in solving optimization problems and understanding the function's qualitative behavior.

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Most popular questions from this chapter

Suppose that \(w(t)\) is the depth of water in a city's water reservoir at time \(t .\) Which would be better news at time \(t=0\) \(w^{\prime \prime}(0)=0.05\) or \(w^{\prime \prime}(0)=-0.05,\) or would you need to know the value of \(w^{\prime}(0)\) to determine which is better?

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