/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Sketch a graph with the given pr... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch a graph with the given properties. $$\begin{aligned} &f(0)=2, f^{\prime}(x) > 0 \text { for all } x, f^{\prime}(0)=1, f^{\prime \prime}(x) > 0 \text { for } x<0\\\ &f^{\prime \prime}(x) < 0 \text { for } x > 0 \end{aligned}$$

Short Answer

Expert verified
The graph of the function should resemble the letter 'S', originating from the point (0,2), ascending on both sides, bending upwards to the left of (0,2) and downwards to the right of (0,2).

Step by step solution

01

Interpret the Function Value

The function value at x=0, f(0)=2, tells us that the point (0,2) lies on the function. Mark this point on the graph.
02

Interpret the First Derivative

The first derivative, \(f^{\prime}(x) > 0\) for all x and \(f^{\prime}(0)=1\), tells us that the function is increasing for every x and that the slope of the function at x=0 is 1. As the first derivative is positive for all x, the function curve will be ascending to the right and to the left of the point (0,2). The slope of the tangent line at (0,2) would be equal to 1.
03

Interpret the Second Derivative

The second derivative \(f^{\prime \prime}(x) > 0\) for \(x<0\) and \(f^{\prime \prime}(x) < 0\) for \(x > 0\) give us information about the concavity of the function graph. For \(x<0\), the function is concave upward, as the second derivative is positive. This means the function graph bends upwards to the left of the point (0,2). On the contrary, for \(x>0\), where the second derivative is negative, the function is concave downward, so it bends downwards to the right of the point (0,2).
04

Sketch the Graph

Now, combining all this information, sketch the graph. Starting from the point (0,2), the graph should go up on both sides, should bend upwards to the left of (0,2) and downwards to the right of (0,2). This shape resembles the letter 'S.'

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First Derivative
Understanding the first derivative is crucial when sketching graphs in calculus. The first derivative of a function, often denoted as \( f'(x) \), provides us with the rate of change of the function at any given point. When \( f'(x) > 0 \), it signifies that the function is increasing at those values of \( x \). In other words, as \( x \) gets larger, the function's output also gets larger.

For example, in the exercise provided, we are told that \( f'(x) > 0 \) for all \( x \). This means that the graph of the function will always be rising, regardless of whether \( x \) is positive or negative. Additionally, since \( f'(0) = 1 \), we know that at \( x = 0 \), the slope of the tangent to the graph is 1, indicating a steady upward inclination at this specific point. This concept is essential for predicting the shape of the function's graph across its domain.
Second Derivative
The second derivative, represented as \( f''(x) \), tells us about the curvature or concavity of the graph of the function. If the second derivative is positive, \( f''(x) > 0 \), the graph is concave upward; visualize this as a smiley face, where any tangent line lies below the graph. Conversely, if the second derivative is negative, \( f''(x) < 0 \), the graph is concave downward, resembling a frown, with tangent lines above the graph.

In the given exercise, we have different signs for the second derivative depending on the value of \( x \). For \( x < 0 \), \( f''(x) > 0 \), indicating the graph is concave upward to the left of the y-axis. For \( x > 0 \), \( f''(x) < 0 \), and the graph turns concave downward to the right of the y-axis. The second derivative helps us understand how the function's slope changes with \( x \) and is a powerful tool in graph sketching.
Concavity of a Function
Concavity refers to the direction in which a function curves. It's an important concept in calculus as it reveals the behavior and nature of the function. A function with a concave upward shape indicates that the rate of increase of the function's slope is positive. In more simplistic terms, the graph is getting steeper as you move along it from left to right. On the other hand, a concave downward shape implies a negative rate of change of the function’s slope, meaning the graph is getting less steep.

The exercise showcases the significance of concavity. It demonstrates that by knowing the concavity of a function on either side of a point, such as (0,2), we can depict the 'S' shape of the graph. To the left of (0,2), it curves like the bottom of an 'S', and to the right, it curves like the top of an 'S'. This understanding of concavity allows us to create a more accurate depiction of the function’s graph.

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Most popular questions from this chapter

An advertisement consists of a rectangular printed region plus 1-in. margins on the sides and 2 -in. margins at top and bottom. If the area of the printed region is to be 92 in. \(^{2}\), find the dimensions of the printed region and overall advertisement that minimize the total area.

Suppose that the charge at a particular location in an electrical circuit is \(Q(t)=e^{-3 t} \cos 2 t+4 \sin 3 t\) coulombs. What happens to this function as \(t \rightarrow \infty ?\) Explain why the term \(e^{-3 t} \cos 2 t\) is called a transient term and \(4 \sin 3 t\) is known as the steady-state or asymptotic value of the charge function. Find the transient and steady-state values of the current function.

Determine whether the following statement is true or false. If \(f(0)=1, f^{\prime \prime}(x)\) exists for all \(x\) and the graph of \(y=f(x)\) is concave down for all \(x\), the equation \(f(x)=0\) has at least one solution.

The rate \(R\) of an enzymatic reaction as a function of the substrate concentration \([S]\) is given by \(R=\frac{[S] R_{m}}{K_{m}+[S]},\) where \(R_{m}\) and \(K_{m}\) are constants. \(K_{m}\) is called the Michaelis constant and \(R_{m}\) is referred to as the maximum reaction rate. Show that \(R_{m}\) is not a proper maximum in that the reaction rate can never be equal to \(R_{m}\)

Suppose a wire \(2 \mathrm{ft}\) long is to be cut into two pieces, each of which will be formed into a square. Find the size of each piece to maximize the total area of the two squares.

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