Chapter 3: Problem 4
Find the linear approximation to \(f(x)\) at \(x=x_{0}\) Graph the function and its linear approximation. $$f(x)=2 / x, x_{0}=1$$
Short Answer
Expert verified
The linear approximation to \(f(x) = \frac{2}{x}\) at \(x = 1\) is \(L(x) = 2 - 2(x - 1)\).
Step by step solution
01
Determine the derivative
First, calculate the derivative of the function \(f(x) = \frac{2}{x}\). Using the rule for the derivative of a quotient, it is \(f'(x) = -\frac{2}{x^{2}}\). Then plug \(x_{0} = 1\) into \(f'(x)\) to get the derivative of \(f(x)\) at the point \(x_{0}\): \(f'(1) = -\frac{2}{(1)^{2}} = -2\).
02
Calculate the linear approximation
The formula for linear approximation is \(L(x) = f(x_0) + f'(x_0)(x-x_0)\). Substitute \(x_0 = 1\), \(f(x_0) = f(1) = 2\) and \(f'(x_0) = f'(1) = -2\) into the formula to get \(L(x) = 2 - 2(x - 1)\). This function represents the linear approximation to \(f(x) = \frac{2}{x}\) at \(x = x_{0} = 1\).
03
Graph the function and its linear approximation
The function \(f(x) = \frac{2}{x}\) will generate a hyperbola and the linear approximation \(L(x) = 2 - 2(x - 1)\) will generate a straight line. The line should be tangent to the curve at the point \(x = 1\), \(y = 2\). You can use graphing software or graphing calculator to achieve this.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative Calculation
To find the linear approximation of a function, understanding how to calculate the derivative is crucial.
The derivative provides information on how a function changes at a specific point and is key to determining the slope of the tangent line.
For the function given, \[ f(x) = \frac{2}{x} \],we apply the quotient rule to compute its derivative. The quotient rule states that for a function expressed as \( \frac{u}{v} \), its derivative is given by \( \frac{u'v - uv'}{v^2} \).
For our function, this means differentiating \( 2 \) with respect to \( x \) and dividing by \( x^2 \), resulting in \( f'(x) = -\frac{2}{x^2} \).
The derivative provides information on how a function changes at a specific point and is key to determining the slope of the tangent line.
For the function given, \[ f(x) = \frac{2}{x} \],we apply the quotient rule to compute its derivative. The quotient rule states that for a function expressed as \( \frac{u}{v} \), its derivative is given by \( \frac{u'v - uv'}{v^2} \).
For our function, this means differentiating \( 2 \) with respect to \( x \) and dividing by \( x^2 \), resulting in \( f'(x) = -\frac{2}{x^2} \).
- This derivative \( f'(x) = -\frac{2}{x^2} \) tells us how the function \( f(x) \) changes at any given point \( x \).
- At \( x = 1 \), plugging this value into the derivative gives us \( f'(1) = -2 \).
Graphing Techniques
Graphing functions and their linear approximations helps visualize how closely the linear model matches the actual function near the point of interest.
The original function, \( f(x) = \frac{2}{x} \), displays a hyperbolic shape. When graphing, remember:
To accurately graph:
The original function, \( f(x) = \frac{2}{x} \), displays a hyperbolic shape. When graphing, remember:
- The function's curve approaches zero as \( x \) becomes large or very small.
- The function is undefined at \( x = 0 \).Because of this, the graph will show two branches: one in the positive \( x \) region and one in the negative \( x \) region.
To accurately graph:
- Start by plotting the point of tangency: \( (1, 2) \) where the function and its linear approximation intersect.
- Draw the curve of \( f(x) \) in both positive and negative \( x \) directions.
Tangent Line
In calculus, the tangent line at any point on a function is the straight line that "touches" the curve at that point.
For \( f(x) = \frac{2}{x} \), the tangent line at \( x = 1 \) provides the best linear estimate of the function near this value.
To find the equation of the tangent line:
For \( f(x) = \frac{2}{x} \), the tangent line at \( x = 1 \) provides the best linear estimate of the function near this value.
To find the equation of the tangent line:
- Use the \( x_0 \) value where you want the tangent, \( x_0 = 1 \).
- Using the calculated derivative, \( f'(1) = -2 \), the slope of the tangent is \(-2\).
- The equation of the tangent line can be written using point-slope form: \( y = f(x_0) + f'(x_0)(x-x_0) \).
- With \( f(x_0) = 2, f'(x_0) = -2, \) and \( x_0 = 1 \),the equation becomes \( y = 2 - 2(x-1) \).