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91Ó°ÊÓ

Find the derivative of the given function. $$f(x)=\sin ^{-1}\left(x^{3}+1\right)$$

Short Answer

Expert verified
The derivative of the function \(f(x) = \sin^{-1}(x^3 + 1)\) is \(f'(x) = \frac{3x^2}{\sqrt{1-(x^3 +1)^2}}\).

Step by step solution

01

Identify Inner and Outer Functions

The given function is \(f(x) = \sin^{-1}(x^3 + 1)\). Here, the outer function is \(\sin^{-1}(x)\) and the inner function is \(x^3 + 1\).
02

Differentiate the Outer Function

The derivative of \(\sin^{-1}(x)\) is \(\frac{1}{\sqrt{1-x^2}}\). Let's leave the inner function as it is for now. So, the derivative of the outer function becomes \(\frac{1}{\sqrt{1-(x^3 +1)^2}}\).
03

Differentiate the Inner Function

The derivative of \(x^3+1\) is \(3x^2\).
04

Apply Chain Rule

Now, multiply the derivative of the outer function by the derivative of the inner function (according to Chain Rule). So, the derivative of the whole function becomes \(f'(x) = \frac{3x^2}{\sqrt{1-(x^3 +1)^2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
One of the most fundamental rules in calculus, especially when dealing with composite functions, is the chain rule. The chain rule helps us find the derivative of a composition of two or more functions. In simple terms, it states that if you have two functions, say \(g(x)\) and \(h(x)\), where one is nested inside the other such as \(f(x) = g(h(x))\), then the derivative \(f'(x)\) is found by multiplying the derivative of the outer function \(g'\) evaluated at \(h(x)\) by the derivative of the inner function \(h'(x)\). Here's a step-by-step breakdown of how to apply the chain rule:
  • Identify the outer and inner functions in your composite function.
  • Differentiate the outer function, leaving the inner function unchanged. This is often the part where beginners make mistakes, so watch out.
  • Differentiate the inner function separately.
  • Multiply the two derivatives together. This gives you the derivative of the whole composite function.
In our case, for \(f(x) = \sin^{-1}(x^3 + 1)\), you start by identifying \(\sin^{-1}\) as the outer function and \(x^3 + 1\) as the inner function. The chain rule guides you through deriving each part, leading to the final derivative.
Inverse Trigonometric Functions
Inverse trigonometric functions are essential for solving problems involving angles and triangles, especially when you need to find the degree measure or radian of an angle given a trigonometric ratio. The function \(\sin^{-1}(x)\), also known as arcsin, is the inverse of the sine function and returns an angle whose sine is \(x\). When differentiating inverse trigonometric functions, it's important to remember their specific derivative formulas. For the arcsine function \(\sin^{-1}(x)\), the derivative is:\[ \frac{d}{dx} [\sin^{-1}(x)] = \frac{1}{\sqrt{1-x^2}} \]This formula only holds true for \(-1 \leq x \leq 1\), the range where the function is defined. On applying this to expressions like \(x^3 + 1\) inside \(\sin^{-1}\), we substitute them accordingly while respecting the derivative formula. This step helps in determining how rapidly the angle is changing in response to changes in the input, giving an insight into the function's behavior.
Function Composition
Function composition is a way of combining two functions to form a new one. When we say one function is "inside" another, this is a classic case of composition. Essentially, in mathematics, if \(f(x)\) and \(g(x)\) are two functions, the composition \((f \circ g)(x)\) reads as \(f\) after \(g\), which means you evaluate \(g(x)\) first, and then \(f\) using the result of \(g\). For the exercise \(f(x) = \sin^{-1}(x^3 + 1)\), the composition is clear where \(x^3 + 1\) is fed into the arcsine function \(\sin^{-1}\). This nesting means the output of \(x^3 + 1\) becomes the input for \(\sin^{-1}(x)\), which is a typical setup for applying the chain rule.Understanding the order in which functions apply is crucial, as mixing up might produce incorrect results. Composition provides a blueprint for operations and thus aids in comprehending the underlying structure of the function involved.

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