Chapter 2: Problem 16
Find the derivative of each function. $$f(x)=\frac{4 x^{2}-x+3}{\sqrt{x}}$$
Short Answer
Expert verified
The derivative of the function \(f(x)=\frac{4 x^{2}-x+3}{\sqrt{x}}\) is \(f'(x)=\frac{8x^{1.5} -\sqrt{x} - 2x^{2} + 0.5x -1.5}{x}\)
Step by step solution
01
Identify applicable rules
The function given is a ratio of two functions: \(g(x)=4x^2−x+3\) and \(h(x)=\sqrt{x}\), so we'll use the Quotient Rule to find the derivative. The quotient rule states: if a function \(f\) is the quotient of two other functions \(g\) and \(h\), then its derivative is: \[f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\] We also notice that \(h(x)=\sqrt{x}\) has an exponent of \(0.5\), so the chain rule will be needed when calculating \(h'(x)\). The chain rule states that the derivative of a composition of functions is the derivative of the outer function times the derivative of the inner function.
02
Compute derivatives of \(g(x)\) and \(h(x)\)
First, we differentiate \(g(x) = 4x^2 - x + 3\), which gives us: \[g'(x) = 8x - 1\] Then, we differentiate \( h(x)=\sqrt{x}\) using the power rule (which is an application of the chain rule): \[h'(x) = \frac{1}{2}x^{-0.5} = \frac{1}{2\sqrt{x}}\]
03
Substitute all findings into quotient rule formula
Now that we have \(g'(x)\), \(g(x)\), \(h'(x)\), and \(h(x)\), we proceed to plug all these into our quotient rule formula: \[f'(x)=\frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\]\[f'(x)=\frac{(8x-1)\sqrt{x} - (4x^{2}-x+3)\frac{1}{2\sqrt{x}}}{(\sqrt{x})^2}\]
04
Simplify the result
Simplify the resulting fraction to achieve the final result: \[f'(x)=\frac{\sqrt{x}(8x-1)-(2x^{2} - 0.5x + 1.5)}{x}\]\[f'(x)=\frac{8x^{1.5} -\sqrt{x} - 2x^{2} + 0.5x -1.5}{x}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
When it comes to finding the derivative of a quotient (a fraction where the numerator and the denominator are both functions), the Quotient Rule is your go-to tool. Essentially, if you have a function that can be expressed as a division of two separate functions, say \( u(x) = \frac{g(x)}{h(x)} \), then the derivative of this function \( u'(x) \) can be found using the formula:
- \( u'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2} \)
Chain Rule
The Chain Rule is a fundamental principle in calculus when dealing with composite functions. If you need to differentiate a function that is nested within another function, the Chain Rule allows you to split the process into easier steps. Suppose you have \( y = f(g(x)) \), the Chain Rule states that the derivative \( y' \) is:
- \( y' = f'(g(x)) \cdot g'(x) \)
Power Rule
The Power Rule is a handy shortcut for taking derivatives of functions that are in the form of powers of \( x \). If you have a function like \( x^n \), the derivative is found by bringing down the power \( n \) as a coefficient and subtracting one from the power:
- \( \frac{d}{dx} x^n = nx^{n-1} \)
- \( 4x^2 \) becomes \( 8x \),
- \( -x \) becomes \( -1 \),
- and the constant \( 3 \) becomes \( 0 \).
Simplifying expressions
After applying the Quotient Rule and other derivative rules, you often end up with complex expressions that need simplifying. Simplification involves several steps:
- Combining like terms,
- Reducing fractions,
- And cancelling common factors when possible.