/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Show that the indicated limit ex... [FREE SOLUTION] | 91Ó°ÊÓ

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Show that the indicated limit exists. $$\lim _{(x, y) \rightarrow(0,0)} \frac{x^{3} y+x^{2} y^{3}}{x^{2}+y^{2}}$$

Short Answer

Expert verified
The limit of the given function as (x, y) approach (0,0) is 0.

Step by step solution

01

Simplify The Expression

Firstly, factor out \(x^2\) from the numerator to simplify the expression:\[\frac{x^{3} y+x^{2} y^{3}}{x^{2}+y^{2}} = \frac{x^{2}(xy+y^{2}y)}{x^{2}+y^{2}}\]
02

Apply Limit Properties

Now, apply the limit properties to separate the terms:\[\lim_{(x,y) \rightarrow(0,0)} \frac{x^{2}(xy+y^{2}y)}{x^{2}+y^{2}} = \lim_{(x,y)\rightarrow(0,0)} (\frac{x^{2}}{x^{2}+y^{2}}) * (\lim_{(x,y)\rightarrow(0,0)} xy+y^{2}y)\]
03

Evaluate the Limit

Substituting (0,0) into the second part of the expression:\[\lim_{(x,y)\rightarrow(0,0)} xy+y^{2}y = 0\]So, the function becomes:\[\lim_{(x,y)\rightarrow(0,0)} (\frac{x^{2}}{x^{2}+y^{2}}) * 0 = 0\]
04

Interpret Result

Since multiplying any real number by zero yields zero, no matter the limit of first part of the function, the entire limit will be zero. Therefore, the limit as (x, y) tends to (0,0) exists and is equal to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits in Multiple Dimensions
In multivariable calculus, understanding limits in multiple dimensions is crucial for analyzing how functions behave near a point. Traditional single-variable limits only consider one direction, whereas multidimensional limits consider all paths leading to a point. Imagine standing at the center of a flat surface, and traces are drawn from any point around you toward this center. The limit is consistent only if every path traced along the surface leads to the same value. Limits in two or three dimensions evaluate points on planes or in space. The complexity increases because you must account for infinite directions approaching the point. In our example, the goal is to find the limit of a function as \((x,y) \to (0,0)\).Using algebra and calculus techniques, we determine the behavior of the function in this multidimensional setup. To confirm a limit exists, paths like \(x=0\), \(y=0\), or even polar coordinates can be used to validate uniformity. When paths yield consistent limit values, it strengthens the certainty of the limit's existence.
Limit Theorems
Limit theorems play a key role in simplifying and confidently evaluating limits, particularly in multivariable scenarios. These theorems help manage complex expressions by applying properties that make calculation easier. Key limit theorems include:
  • Limit Sum Rule: The limit of a sum is the sum of the limits, provided they both exist.
  • Limit Product Rule: The limit of a product equals the product of the limits.
  • Limit Quotient Rule: Similar to the product rule but applicable to division when the denominator's limit isn't zero.
In the given exercise, the Limit Product Rule aids by breaking down the function into manageable pieces. We separate the expression, allowing us to individually assess each part's limit. By using these rules, we can focus on components, confirming their limits, simplifying calculations, and ensuring accuracy.
Factorization in Algebra
Factorization simplifies complex algebraic expressions, breaking them into products of simpler terms. This method can reveal hidden behaviors within expressions, enabling easier calculation, especially in limit evaluation problems.In this exercise, factorization was used to simplify the numerator, extracting common factors: \(x^{3}y + x^{2}y^{3} = x^{2}(xy+y^{2}y)\).By factoring out \(x^2\), we reduce the expression's complexity, allowing a clearer path to substitute values when calculating limits. Simplification through factorization often highlights zeros or undefined aspects quickly, helping to process functions efficiently. Overall, mastering factorization aids not only in limit computations but in various algebraic manipulations, giving a strong foundation for tackling more advanced calculus problems.
Continuous Functions
Understanding continuous functions is essential in multivariable calculus and limit evaluation. A function is continuous at a point if small changes in input around that point result in small changes in output.The continuity implies no jumps or gaps in the graph of the function. Continuity in multivariable calculus broadens to accommodate functions of more than one variable, requiring that all paths towards a point result in the same function output.In our example, we examine the function as \((x,y)\to (0,0)\).If the limit exists and the function is defined, it suggests continuity at that point. Thus, as \( (x, y) \) tends to \((0,0)\), the function approaches zero, reinforcing the principle of continuity. This understanding helps predict the behavior of functions in multivariable spaces, simplifying complex problem-solving.

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Most popular questions from this chapter

Graph \(z=\sin (x+y) .\) Compute \(\nabla \sin (x+y)\) and explain why the gradient gives you the direction that the sine wave travels. In which direction would the sine wave travel for \(z=\sin (2 x-y) ?\)

Suppose that \(f(x, y)\) is a function with continuous secondorder partial derivatives. Consider the curve obtained by intersecting the surface \(z=f(x, y)\) with the plane \(y=y_{0}\) Explain how the slope of this curve at the point \(x=x_{0}\) relates to \(\frac{\partial f}{\partial x}\left(x_{0}, y_{0}\right) .\) Relate the concavity of this curve at the point \(x=x_{0}\) to \(\frac{\partial^{2} f}{\partial x^{2}}\left(x_{0}, y_{0}\right)\)

In exercise \(3,\) there is a saddle point at \((0,0) .\) This means that there is (at least) one trace of \(z=x^{3}-3 x y+y^{3}\) with a local minimum at (0,0) and (at least) one trace with a local maximum at \((0,0) .\) To analyze traces in the planes \(y=k x\) (for some constant \(k\) ), substitute \(y=k x\) and show that \(z=\left(1+k^{3}\right) x^{3}-3 k x^{2} .\) Show that \(f(x)=\left(1+k^{3}\right) x^{3}-3 k x^{2}\) has a local minimum at \(x=0\) if \(k<0\) and a local maximum at \(x=0\) if \(k>0 .\) (Hint: Use the Second Derivative Test from section \(3.5 .)\)

Find the maximum of \(x^{2}+y^{2}\) on the square with \(-1 \leq x \leq 1\) and \(-1 \leq y \leq 1 .\) Use your result to explain why a computer graph of \(z=x^{2}+y^{2}\) with the graphing window \(-1 \leq x \leq 1\) and \(-1 \leq y \leq 1\) does not show a circular cross section at the top.

In The Hidden Game of Football, Carroll, Palmer and Thorn give the following formula for the probability \(p\) that the team with the ball will win the game: $$\ln \left(\frac{p}{1-p}\right)=0.6 s+0.084 \frac{s}{\sqrt{t / 60}}-0.0073(y-74)$$ Here, \(s\) is the current score differential ( \(+\) if you're winning, \- if you're losing), \(t\) is the number of minutes remaining and \(y\) is the number of yards to the goal line. For the function \(p(s, t, y),\) compute \(p(2,10,40), p(3,10,40), p(3,10,80)\) and \(p(3,20,40),\) and interpret the differences in football terms.

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