/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Use graphing technology to sketc... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use graphing technology to sketch the curve traced out by the given vector- valued function. $$\mathbf{r}(t)=\langle 4 \cos 4 t-6 \cos t, 4 \sin 4 t-6 \sin t\rangle$$

Short Answer

Expert verified
The graph of the vector-valued function \(\mathbf{r}(t)=\langle 4 \cos 4 t-6 \cos t, 4 \sin 4 t-6 \sin t\rangle\) is a complex shape that represents the path traced by the particle over time. To see the actual graph, you would need to use a graphing calculator or software that can plot parametric equations.

Step by step solution

01

Understand the function

The function \(\mathbf{r}(t)\) is defined as \(\langle 4 \cos 4 t-6 \cos t, 4 \sin 4 t-6 \sin t\rangle\). It is a parametric function, where \(x(t) = 4 \cos 4 t-6 \cos t\) and \(y(t) = 4 \sin 4 t-6 \sin t\). \(t\) is the parameter, often representing time.
02

Use graphing technology

Use a graphing software or calculator that allows you to plot parametric equations. Enter the functions for \(x(t)\) and \(y(t)\) from Step 1 and set an appropriate interval for \(t\). A common interval could be from \(t = 0\) to \(t = 2\pi\) for a complete cycle.
03

Draw and Interpret the Graph

After plotting the graph, you will see a complex shape. This shape is the path that the particle would take over time as defined by the functions \(x(t)\) and \(y(t)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parametric Equations
Imagine you are trying to describe the flight path of a butterfly - it's erratic, unpredictable, and doesn't follow a straight line. This is where parametric equations come into play. In calculus, these equations allow us to define curves in the xy-plane using a third variable, typically t, which often represents time.

Parametric equations split a compound motion into two separate functions, one for each axis. In our example, \( x(t) = 4 \cos(4t) - 6 \cos(t) \) dictates the horizontal movement, and \( y(t) = 4 \sin(4t) - 6 \sin(t) \) describes the vertical. By varying t, you can predict the butterfly's location at any moment.

It's important to understand the boundlessness of parametric equations. While plotting x and y against each other gives a curve, changing t alters the whole behavior of the plotted path. Parametric equations are essential for animating objects in video games or predicting celestial movements in astronomy - their applications are virtually limitless.
Trigonometric Functions Graphing
Have you ever watched a sound wave travel through the air or a spring bounce up and down? These patterns are often cyclical, like the paths of planets and the gears of a clock. They can be described mathematically using trigonometric functions.

Graphing these functions, specifically sine and cosine, represents repetitive motion. With a pure sine or cosine function, you get a smooth, undulating wave. However, the functions for our vector-valued function, \( x(t) = 4 \cos(4t) - 6 \cos(t) \) and \( y(t) = 4 \sin(4t) - 6 \sin(t) \) — these are combinations of trigonometric functions with different frequencies, which create more complex patterns.

Diving Into the Waves

The first parts of our functions, \( 4 \cos(4t) \) and \( 4 \sin(4t) \) have higher frequencies, suggesting that they will oscillate faster. In contrast, \( -6 \cos(t) \) and \( -6 \sin(t) \) oscillate slower. When these mix, it's like listening to a duet with notes at different pitches played together—it's the combination that makes the complete tune or, in our case, the full graph.
Graphing Technology in Calculus
Picture trying to draw an intricate pattern with just a pencil and a ruler - it might be quite challenging, especially if the pattern is complex. This is where graphing technology steps in, serving as your advanced set of drawing tools.

In calculus, graphing technology ranges from simple graphing calculators to elaborate software. They help us visualize mathematical concepts, especially those not easily plotted by hand, like our vector-valued function \( \mathbf{r}(t) \). By inputting our parametric equations into a graphing tool, we can see the curve that they create. This tool can make complex calculations and display the results almost instantaneously, allowing us to observe the behavior of functions and their intersections, and to predict outcomes in mathematical modeling.

Technology at Our Service

When using graphing technology, setting the correct domain for t is crucial because it determines the portion of the curve we will see. It's much like setting the right boundaries for taking a picture - you want to capture the entirety of the scene in the frame. When instructing for a full cycle, the interval from \( t = 0 \) to \( t = 2\pi \) often works well, ensuring we don't miss any part of our mathematical 'performance'.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evaluate the given indefinite or definite integral. $$\int\left\langle t e^{t^{2}}, 3 t \sin t, \frac{3 t}{t^{2}+1}\right\rangle d t$$

In this exercise, we prove Kepler's second law. Denote the (two-dimensional) path of the planet in polar coordinates by \(\mathbf{r}=(r \cos \theta) \mathbf{i}+(r \sin \theta) \mathbf{j} .\) Show that \(\mathbf{r} \times \mathbf{v}=r^{2} \frac{d \theta}{d t} \mathbf{k} .\) Con- clude that \(r^{2} \frac{d \theta}{d t}=\|\mathbf{r} \times \mathbf{v}\| .\) Recall that in polar coordinates, the area swept out by the curve \(\mathbf{r}=r(\theta)\) is given by \(A=\int_{a}^{b} \frac{1}{2} r^{2} d \theta \quad\) and show that \(\quad \frac{d A}{d t}=\frac{1}{2} r^{2} \frac{d \theta}{d t} .\) From \(\frac{d A}{d t}=\frac{1}{2}\|\mathbf{r} \times \mathbf{v}\|,\) conclude that equal areas are swept out in equal times.

We have seen how we can find the trajectory of a projectile given its initial position and initial velocity. For military personnel tracking an incoming missile, the only data available correspond to various points on the trajectory, while the initial position (where the enemy gun is located) is unknown but very important. Assume that a projectile follows a parabolic path (after launch, the only force is gravity). If the projectile passes through points \(\left(x_{1}, y_{1}, z_{1}\right)\) at time \(t_{1}\) and \(\left(x_{2}, y_{2}, z_{2}\right)\) at time \(t_{2}\) find the initial position \(\left(x_{0}, y_{0}, 0\right).\)

Relate to parametric equations of a plane. Sketch the plane with parametric equations \(x=2+u+2 v\) \(y=-1+2 u-v\) and \(z=3-3 u+2 v .\) Show that the points (2,-1,3),(3,1,0) and (4,-2,5) are on the plane by finding the correct values of \(u\) and \(v .\) Sketch these points along with the plane and the displacement vectors \(\langle 1,2,-3\rangle\) and \(\langle 2,-1,2\rangle\)

Suppose an airplane is acted on by three forces: gravity, wind and engine thrust. Assume that the force vector for gravity is \(m g=m(0,0,-32),\) the force vector for wind is \(w=(0,1,0)\) for \(0 \leq t \leq 1\) and \(w=\langle 0,2,0\rangle\) for \(t>1,\) and the force vector for engine thrust is \(\mathbf{e}=\langle 2 t, 0,24\rangle .\) Newton's second law of motion gives us \(m \mathbf{a}=m \mathbf{g}+\mathbf{w}+\mathbf{e} .\) Assume that \(m=1\) and the initial velocity vector is \(\mathbf{v}(0)=(100.0 .10) .\) Show that the velocity vector for \(0 \leq t \leq 1\) is \(\mathbf{v}(t)=\left\langle t^{2}+100, t, 10-8 t\right\rangle\) For \(t>1,\) integrate the equation \(\mathbf{a}=\mathbf{g}+\mathbf{w}+\mathbf{e},\) to \(\mathrm{get}\) \(\mathbf{v}(t)=\left\langle t^{2}+a, 2 t+b,-8 t+c\right\rangle,\) for constants \(a, b\) and \(c . \mathrm{Ex}\) plain (on physical grounds) why the function \(v(t)\) should be continuous and find the values of the constants that make it so. Show that \(\mathbf{v}(t)\) is not differentiable. Given the nature of the force function, why does this make sense?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.