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Sketch the appropriate traces, and then sketch and identify the surface. $$z^{2}=\frac{x^{2}}{4}+\frac{y^{2}}{9}$$

Short Answer

Expert verified
The given equation \( z^{2}=\frac{x^{2}}{4}+\frac{y^{2}}{9} \) represents an elliptic cone centered at the origin with semi-axes along the x and y-axis of lengths 2 and 3 respectively.

Step by step solution

01

Identify the traces in xy-plane

Set \( z = 0 \) in the given equation, we get \(\frac{x^{2}}{4}+\frac{y^{2}}{9} = 0\). This represents a point at the origin (0,0) in the xy-plane as both \(x^{2}\) and \(y^{2}\) can't be negative.
02

Identify the traces in xz-plane

Set \( y = 0 \) in the given equation to find the xz-trace. The equation becomes \( z^{2}=\frac{x^{2}}{4} \). This is a pair of lines \( z= \frac{x}{2} \) and \( z= -\frac{x}{2} \), which form a V-shape opening up and down on the xz-plane.
03

Identify traces in yz-plane

Setting \( x= 0 \) in the equation, we get the yz-trace as \( z^{2}=\frac{y^{2}}{9} \). This is a pair of lines \( z= \frac{y}{3} \) and \( z= -\frac{y}{3} \), which also form a V-shape opening up and down on the yz-plane. However, these lines are steeper than the xz traces because the coefficient with y is larger.
04

Draw the 3D surface

The traces give information about the shape of the surface in 3D. Combine the traces from all three planes to get the shape of the surface. Draw a 3D elliptical shape where x and y centred at the origin. The vertices of the ellipse are the points (2,0,0), (-2,0,0), (0,3,0) and (0,-3,0). The surface opens up and down forming the shape of an elliptical cone.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
In the realm of mathematics, calculus is a field that focuses on rates of change (differential calculus) and accumulation of quantities (integral calculus). It's the cornerstone for understanding and describing changes in the natural realm, making it an invaluable tool for analyzing patterns and systems in multiple dimensions.

Within this context, calculus plays a pivotal role when it comes to sketching 3D surfaces. It provides tools to understand geometric relationships and properties through functions and equations. In our exercise, the equation \(z^{2}=\frac{x^{2}}{4}+\frac{y^{2}}{9}\) is evaluated to represent a 3D surface. Through derivative concepts, we can analyze how the surface changes direction and curvature at any given point.
3D Graphs
3D graphs are visual representations of mathematical relationships between three variables, often labeled as x, y, and z. Creating these graphs help students to visualize complex surfaces that can be difficult to interpret through equations alone.

When sketching 3D graphs, identifying the traces, which are the intersections of the surface with planes parallel to the coordinate planes, is a fundamental step. This process is akin to slicing through the shape to uncover its inner structure, just like the four steps outlined in the problem solution provide a systematic approach to unraveling the 3D shape in question - the elliptical cone.
Conic Sections
Conic sections represent the curves obtained by intersecting a cone with a plane. These include circles, ellipses, parabolas, and hyperbolas. Each section reveals a unique shape based on the angle at which the plane cuts through the cone.

In practical terms, for our equation \(z^{2}=\frac{x^{2}}{4}+\frac{y^{2}}{9}\), by setting the values of z, x, or y to zero, we can obtain traces that represent various conic sections: ellipses, circles, or pairs of lines. These traces are then synthesized to render the entire 3D surface, providing an in-depth understanding of the shape and form of the object depicted by the given equation.
Elliptical Cone
An elliptical cone is a type of conic surface formed by a circle rotating around one axis while increasing in size along another axis. Unlike a circular cone, the base of an elliptical cone is an ellipse, not a circle.

The equation given in our exercise sketches out just such a shape. By recognizing that the traces form V-shapes, both in the xz-plane and yz-plane, we can infer the conical nature of the graph. Combining these traces draws out an elliptical cone - a cone whose cross-sections are ellipses, with the origin as the apex. This understanding allows one to visualize and depict a clear and accurate 3D representation of the surface defined by the given equation.

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Most popular questions from this chapter

Find the distance between the given objects. The point (1,3,0) and the plane \(3 x+y-5 z=2\)

Find the distance between the given objects. The planes \(x+3 y-2 z=3\) and \(x+3 y-2 z=1\)

You are asked to work with vectors of dimension higher than three. Use rules analogous to those introduced for two and three dimensions. $$\|\mathbf{a}+\mathbf{b}\| \text { for } \mathbf{a}=\langle 1,-2,4,1\rangle \text { and } \mathbf{b}=\langle-1,4,2,-4\rangle$$

Suppose that in a particular county, ice cream sales (in thousands of gallons) for a year is given by the vector \(\mathbf{s}=\langle 3,5,12,40,60,100,120,160,110,50,10,2\rangle .\) That is, 3000 gallons were sold in January, 5000 gallons were sold in February, and so on. In the same county, suppose that murders for the year are given by the vector \(\mathbf{m}=\langle 2,0,1,6,4,8,10,13,8,2,0,6\rangle .\) Show that the aver- age monthly ice cream sales is \(\bar{s}=56,000\) gallons and that the average monthly number of murders is \(\bar{m}=5 .\) Compute the vectors a and \(\mathbf{b},\) where the components of a equal the components of s with the mean 56 subtracted (so that \(\mathbf{a}=\langle-53,-51,-44, \ldots\rangle)\) and the components of \(\mathbf{b}\) equal the components of \(\mathrm{m}\) with the mean 5 subtracted. The correlation between ice cream sales and murders is defined as \(\rho=\frac{\mathbf{a} \cdot \mathbf{b}}{\|\mathbf{a}\|\|\mathbf{b}\|} .\) Often, a positive correlation is incorrectly interpreted as meaning that a "causes" b. (In fact, correlation should never be used to infer a cause-and-effect relationship.) Explain why such a conclusion would be invalid in this case.

Sketch the given traces on a single three-dimensional coordinate system. $$z=x^{2}-y^{2} ; x=0, x=1, x=2$$

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