/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 For Activities 5 through \(16,\)... [FREE SOLUTION] | 91Ó°ÊÓ

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For Activities 5 through \(16,\) evaluate the improper integral. $$ \int_{5}^{\infty}\left[5\left(0.36^{x}\right)+5\right] d x $$

Short Answer

Expert verified
The improper integral diverges because one part of the integral is infinite.

Step by step solution

01

Simplify the Integral Expression

Rewrite the given integral by separating the terms within the integrand. The integral becomes:\[\int_{5}^{\infty} \left[5(0.36^{x}) + 5\right] dx = \int_{5}^{\infty} 5(0.36^{x}) dx + \int_{5}^{\infty} 5 dx\]
02

Evaluate Each Term Separately

Separate the two integrals from the previous step and evaluate each.The integral becomes two separate expressions:\[5 \int_{5}^{\infty} 0.36^{x} dx + 5 \int_{5}^{\infty} 1 dx\]
03

Recognize Convergence and Divergence

Before solving, identify the convergence of each integral. The first term involves an exponential decay which might converge, while the second term, being a constant, will diverge.
04

Evaluate the Convergent Integral

Evaluate \(5 \int_{5}^{\infty} 0.36^{x} dx\).The indefinite integral of the exponential decay part \(0.36^{x}\) is \(\frac{0.36^{x}}{\ln(0.36)}\). Thus:\[\int 0.36^{x} dx = \frac{0.36^{x}}{\ln(0.36)}\]Applying the limits of integration to the convergent part:\[5 \left[\frac{0.36^{x}}{\ln(0.36)}\right]_{5}^{\infty} \]Evaluate the limit as \(x\) approaches infinity, and at \(x = 5\).
05

Evaluate the Divergent Integral

Since the integral \(5 \int_{5}^{\infty} 1 dx\) represents a constant function over an infinite interval, it diverges. Thus:\[5 \int_{5}^{\infty} 1 dx = 5[\infty - 5] = \infty\]
06

Conclude the Integral Result

Since a part of the integral diverges, the original integral is said to be divergent. Therefore, the improper integral cannot be evaluated to a finite value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics focused on the study of change and motion. It introduces powerful tools and techniques for analyzing complex systems. In calculus, we primarily investigate functions, limits, derivatives, and integrals. Integrals are essential for understanding the total accumulation of quantities, such as area under curves or accumulated changes over intervals.

There are two main types of integrals: definite and indefinite. A definite integral calculates the net area between a function and the x-axis over a specified interval. An indefinite integral, on the other hand, represents a family of functions and includes a constant of integration. Improper integrals, like our example, differ slightly as they involve infinite limits of integration or unbounded intervals. Analyzing and solving improper integrals requires a good grasp of the behavior of functions over such infinite intervals.
Convergence and Divergence
Understanding convergence and divergence is crucial when dealing with improper integrals. In simpler terms, convergence occurs when an integral sums to a finite value over an interval, despite having infinite bounds. Conversely, divergence implies that the integral cannot be contained within any finite limit.

For the given integral, we separate it into two parts: the exponential term and the constant term. This approach helps us assess their individual behavior over infinite intervals. The first part, involving the exponential term \(0.36^x\), tends to converge to zero as \(x\) moves towards infinity, due to the exponential decay (as \(0 < 0.36 < 1\)). The second part is a constant, and integrals of constant functions over infinite intervals inherently diverge. Therefore, if any part of a separated improper integral has a divergent behavior, the entire integral is labeled divergent.
Exponential Functions
Exponential functions are a special category of mathematical expressions characterized by a constant base raised to a variable power. In our integral, the function \(0.36^x\) represents an exponential decay function. Exponential decay functions are notable for their rapid decrease as the variable increases, especially when the base is between 0 and 1.

When integrated over infinite intervals, such functions may lead to convergence. For instance, the integral of \(0.36^x\) utilizes the natural logarithm in its evaluation: \(\int 0.36^x \, dx = \frac{0.36^x}{\ln(0.36)}\). The logarithm provides a mechanism to relate exponential growth or decay to a linear correlation. Evaluating this over the interval from 5 to infinity shows that as \(x\) trends towards infinity, the value approaches zero, indicating convergence for this term of the integral.

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