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Identify the differential equation as one that can be solved using only antiderivatives or as one for which separation of variables is required. Then find a general solution for the differential equation. \(\frac{d y}{d x}=\frac{k y}{x}\)

Short Answer

Expert verified
The equation requires separation of variables, resulting in the solution: \(y = C x^k\).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is \(\frac{d y}{d x} = \frac{k y}{x}\). We can solve this equation by rearranging it so that all \(y\) terms are on one side and all \(x\) terms are on the other side. This means it can be solved via separation of variables.
02

Separate Variables

To separate the variables, rewrite the equation as \(\frac{dy}{y} = \frac{k}{x}dx\). Now, the variables \(y\) and \(x\) are separated on different sides of the equation.
03

Integrate Both Sides

Integrate both sides of the equation. The integral of \(\frac{1}{y}\) with respect to \(y\) is \(\ln|y|\), and the integral of \(\frac{k}{x}\) with respect to \(x\) is \(k \ln|x|\). So, we have \(\ln|y| = k \ln|x| + C\), where \(C\) is the constant of integration.
04

Solve for the General Solution

Exponentiate both sides to solve for \(y\). This gives \(|y| = e^{(k \ln|x| + C)} = |x|^k e^C\). Let \(C_1 = e^C\), so \(y = C_1 x^k\) or \(y = C x^k\), where \(C\) is a constant and can be positive or negative by absorbing the absolute value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
Separation of variables is a powerful technique used in solving differential equations. It works particularly well with equations that can be rearranged so that all terms involving one variable appear on one side of the equation, while all terms involving the other variable appear on the opposite side. This method is akin to sorting out different fruits into separate baskets, allowing you to handle each type independently.

In the given differential equation, \(\frac{dy}{dx} = \frac{ky}{x}\), our goal is to rearrange the terms to isolate the variables. By concentrating all \(y\) terms on one side and all \(x\) terms on the other, we achieve separation.

We can rewrite the equation as \(\frac{dy}{y} = \frac{k}{x}dx\). This spells out that while \(x\) affects the right-hand side, the left is solely impacted by \(y\). This neat separation paves the path for the next step: integration.
Integration
Integration comes into play once the variables are separated. It is like summing up small intervals to find the entire area under the curve, or more formally, finding the antiderivative. This step is crucial in finding an equation that expresses the relationship between \(y\) and \(x\).

With the separated equation \(\frac{dy}{y} = \frac{k}{x} dx\), we integrate both sides independently. The left-hand side becomes \(\int \frac{1}{y} \, dy = \ln|y|\), while the right-hand side becomes \(\int \frac{k}{x} \, dx = k \ln|x|\).
  • The natural logarithm \(\ln\) emerges because it is the antiderivative of the \(\frac{1}{u}\) function.
  • It is essential to add \(C\), the constant of integration, at this stage to reflect all possible solutions resulting from indefinite integration.
Together, these integrals give us the equation \(\ln|y| = k \ln|x| + C\).
General Solution
The general solution provides an expression that describes all possible solutions of the differential equation. It's like having a blueprint that covers every conceivable structure built within given parameters.

To solve \(\ln|y| = k \ln|x| + C\), you exponentiate both sides to eliminate the natural logarithms, resulting in \(|y| = e^{k \ln|x| + C}\). This turns the equation into a more manageable form, illustrating the relationship in a clearer way.

You can further simplify this to \(|y| = |x|^k e^C\). Letting \(C_1 = e^C\) simplifies even more: observe that because of the properties of exponents, you get \(y = C_1 x^k\). Here, \(C_1\) is a constant that can be adjusted to either positive or negative, offering a full spectrum of solutions.
  • This is called the general solution because it encompasses all the particular solutions for any initial condition.
  • This form, \(y = C x^k\), is the fundamental answer reflecting how \(y\) varies with \(x\) given the parameters \(k\) and \(C\).

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Most popular questions from this chapter

Test Scores Scores on a 100 -point final exam administered to all applied calculus classes at a large university are normally distributed with a mean of 72.3 and a standard deviation of \(28.65 .\) What percentage of students taking the test had a. Scores between 60 and \(80 ?\) b. Scores of at least \(90 ?\) c. Scores that were more than one standard deviation away from the mean? d. At what score was the rate of change of the probability density function for the scores a maximum?

Write an equation or differential equation for the given information. The marginal cost of producing window panes (that is, the rate of change of \(\operatorname{cost} c\) with respect to the number of units produced) is inversely proportional to the number of panes \(p\) produced.

Identify the differential equation as one that can be solved using only antiderivatives or as one for which separation of variables is required. Then find a general solution for the differential equation. \(\frac{d y}{d x}=k x y\)

Write a differential equation expressing the information given and, when possible, find a general solution for the differential equation. The rate of growth of the height \(h\) of a young child with respect to the age \(y\) of the child decreases in inverse proportion to the age of the child.

It is estimated that for the first 10 years of production, a certain oil well can be expected to produce oil at a rate of \(r(t)=3.9 t^{3.55} e^{-1.351}\) thousand barrels per year \(t\) years after production begins. a. Write a differential equation for the rate of change of the total amount of oil produced \(t\) years after production begins. b. Use Euler's method with ten intervals to estimate the yield from this oil well during the first 5 years of production. c. Graph the differential equation and the Euler estimates. Discuss how the shape of the graph of the differential equation is related to the shape of the graph of the Euler estimates.

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