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Identify the differential equation as one that can be solved using only antiderivatives or as one for which separation of variables is required. Then find a general solution for the differential equation. \(\frac{d y}{d x}=\frac{k x}{y}\)

Short Answer

Expert verified
The differential equation requires separation of variables; the general solution is \( y = \pm \sqrt{k x^2 + 2C} \).

Step by step solution

01

Identify the Type of Differential Equation

The given differential equation is \( \frac{d y}{d x} = \frac{k x}{y} \). We notice that it is in the form of a separable equation. This means we can rewrite it as two separate integrals, one involving only \( y \) and the other involving only \( x \). Thus, separation of variables is required.
02

Rearrange the Equation to Separate Variables

We start with the equation \( \frac{d y}{d x} = \frac{k x}{y} \). We can multiply both sides by \( y \, dx \) to get \( y \, dy = k x \, dx \). This separates the variables \( y \) and \( x \).
03

Integrate Both Sides

Now that we have \( y \, dy = k x \, dx \), we integrate both sides. The left side becomes \( \int y \, dy \) and the right side becomes \( \int k x \, dx \). Integrating, we find \( \frac{y^2}{2} = \frac{k x^2}{2} + C \), where \( C \) is the constant of integration.
04

Solve for \( y \) to Find the General Solution

We solve for \( y \) by multiplying both sides of \( \frac{y^2}{2} = \frac{k x^2}{2} + C \) by 2, resulting in \( y^2 = k x^2 + 2C \). Taking the square root of both sides gives us the general solution \( y = \pm \sqrt{k x^2 + 2C} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical equations that relate a function to its derivatives. These equations are used to describe how things change and are widely applicable in many fields ranging from physics to finance. A key feature of differential equations is that they involve derivatives, which symbolize rates of change.

For example, if you are modeling the growth of a population or the cooling of a hot object, you would use a differential equation. In general, the presence of derivatives makes them quite different from regular algebraic equations. Instead of finding specific values for variables, you often solve for functions that satisfy the given relationships.

There are many types of differential equations, such as ordinary differential equations (ODEs) and partial differential equations (PDEs). ODEs involve functions of a single variable and their derivatives. The equation given in the exercise, \( \frac{d y}{d x} = \frac{k x}{y} \), is an example of an ODE and more specifically, a separable equation. Separable equations allow you to separate variables on either side before integrating. We'll talk more about separation and integration in the following sections.
Antiderivatives
An antiderivative is essentially the reverse process of differentiation. If differentiation involves finding the derivative or the rate of change of a function, antiderivatives involve finding a function given its derivative. This leads us to the concept of integration, which is closely related to finding antiderivatives.

In the context of solving differential equations, finding an antiderivative is a key step. When we separate the variables, as in the equation \( \frac{y^2}{2} = \int y \, dy \) and \( \frac{kx^2}{2} = \int kx \, dx \), we apply the antiderivative concept to find a function whose derivative is the given expression.

The integral of \( y \, dy \) is \( \frac{y^2}{2} + C_1 \), and the integral of \( kx \, dx \) is \( \frac{kx^2}{2} + C_2 \), where \( C_1 \) and \( C_2 \) are constants of integration. In many cases, these constants are combined into a single constant \( C \) when expressing the final solution. Remember that integration can involve various techniques, such as substitution or integration by parts, but for separable equations, it's usually straightforward.
General Solution
The general solution to a differential equation provides us with a family of functions that satisfy the equation. In the case of our given equation, \( y = \pm \sqrt{k x^2 + 2C} \), this solution includes an arbitrary constant \( C \), which accounts for unknown initial conditions.

Every specific value of \( C \) represents a particular solution within the family of solutions. The concept of initial conditions is crucial when narrowing down this family to a single, unique solution. These conditions could be initial values of the function or its derivatives, depending on the problem's context.

Understanding the general solution also involves recognizing that "\( \pm \)" indicates both positive and negative square roots could be solutions, acknowledging the symmetry or possible directions of change. Essentially, the general solution not only solves the equation but encapsulates all possible scenarios the differential equation describes. This is why general solutions are fundamental to understanding the entire behavior of the system being modeled.

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