/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Let \(w\) with input \(x\) be a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(w\) with input \(x\) be a uniform density function with \(a=4\) and \(b=20\) a. Write \(W\), the corresponding cumulative distribution function. b. Use both \(w\) and \(W\) to calculate the probability that \(x \leq 5.8\) c. Use \(W\) to calculate the probability that \(15

Short Answer

Expert verified
a. \( W(x) = \frac{x-4}{16} \) for \( 4 \leq x \leq 20 \). b. \( P(x \leq 5.8) = 0.1125 \). c. \( P(15 < x \leq 18) = 0.1875 \).

Step by step solution

01

Write the Uniform Density Function

The uniform density function, denoted as \( w(x) \), is defined for a continuous random variable \( x \) over the interval \([a, b]\) as follows:\[ w(x) = \frac{1}{b-a} \text{ for } a \leq x \leq b \]For this exercise, \( a = 4 \) and \( b = 20 \). Hence, the function becomes:\[ w(x) = \frac{1}{20-4} = \frac{1}{16} \text{ for } 4 \leq x \leq 20 \]
02

Write the Cumulative Distribution Function W

The cumulative distribution function \( W(x) \) for a uniform distribution is: \[ W(x) = \begin{cases} 0, & x < a \ \frac{x-a}{b-a}, & a \leq x \leq b \ 1, & x > b \end{cases} \]Substitute \( a = 4 \) and \( b = 20 \) into the function:\[ W(x) = \begin{cases} 0, & x < 4 \ \frac{x-4}{16}, & 4 \leq x \leq 20 \ 1, & x > 20 \end{cases} \]
03

Calculate Probability P(x ≤ 5.8) Using w and W

To find the probability \( P(x \leq 5.8) \), use the cumulative distribution function:\[ W(5.8) = \frac{5.8 - 4}{16} = \frac{1.8}{16} = 0.1125 \]This means the probability \( P(x \leq 5.8) = 0.1125 \).
04

Calculate Probability P(15 < x ≤ 18) Using W

To find \( P(15 < x \leq 18) \), calculate:\[ P(15 < x \leq 18) = W(18) - W(15) \]Calculate \( W(18) \) and \( W(15) \):\[ W(18) = \frac{18 - 4}{16} = \frac{14}{16} = 0.875 \]\[ W(15) = \frac{15 - 4}{16} = \frac{11}{16} = 0.6875 \]Thus, \( P(15 < x \leq 18) = 0.875 - 0.6875 = 0.1875 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
When you're dealing with probability calculations in uniform distributions, you're exploring how often a certain event is expected to happen. For a uniform distribution, the probability across each interval is constant. For example, in our exercise, we were given the interval \([4, 20]\). Probability calculations can be performed using either the density function or the cumulative distribution function.

To calculate the probability that a variable, like \(x\), will take on a specific value or fall into an interval, utilize the cumulative distribution function (CDF). It provides the probability that a random variable is less than or equal to a particular value. For instance, when finding the probability that \(x \leq 5.8\), you simply plug 5.8 into the CDF, resulting in a probability of 0.1125.

Another example is finding the probability that \(x\) falls within a range, such as \(15 < x \leq 18\). By calculating the CDF for both endpoints and subtracting, you find the probability for the interval: \(0.875 - 0.6875 = 0.1875\). This straightforward approach makes it easy to work with uniform distributions.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF), denoted as \(W(x)\), gives the cumulative probability that a uniform random variable is less than or equal to a value \(x\). Based on the parameters of the distribution, it steps up from 0 to 1 across the interval.

For the uniform distribution over the interval \([a, b]\), the CDF is defined as:
  • 0, for \(x < a\)
  • \(\frac{x-a}{b-a}\), for \(a \leq x \leq b\)
  • 1, for \( x > b\)
In the given exercise with \(a = 4\) and \(b = 20\), the function becomes \(W(x) = \frac{x-4}{16}\) for any \(x\) within \([4, 20]\). Therefore, this function linearly increases over the interval from 4 to 20. For example, plugging in 18 gives \(0.875\), meaning there's an 87.5% chance that \(x\) is less than or equal to 18 in this uniform distribution.
Density Function
The density function, denoted as \(w(x)\), describes the probability of a uniform random variable taking on a particular value within a specific interval. It's represented by a flat line over the interval, reflecting the equal likelihood of the variable across the range.

For a continuous uniform distribution, the density function is defined as \(w(x) = \frac{1}{b-a}\) over the interval \([a, b]\).
In this exercise, with \(a = 4\) and \(b = 20\), the density function is \(w(x) = \frac{1}{16}\). This means every number within the interval from 4 to 20 has the same probability density. It's essential to note, however, that for continuous ranges, the probability of the variable taking any exact value is essentially zero. Instead, probability is considered over intervals, such as "between 15 and 18."

Uniform density functions are particularly straightforward because they don't change value within a given interval, making them an excellent tool for beginners to learn the basics of continuous probability distributions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write a differential equation expressing the information given and, when possible, find a general solution for the differential equation. The rate of change with respect to time \(t\) of the demand \(D\) for a product is decreasing in proportion to the demand at time \(t\).

Radon-232 Isotope Radon-232 is a colorless, odorless gas that undergoes radioactive decay with a half-life of 3.824 days. It is considered a health hazard, so new homebuyers often have their property tested for the presence of radon-232. Because radon- 232 is a radioisotope, it decays (over time) at a rate that is directly proportional to the amount of the radioisotope. a. Write a differential equation for the rate at which an amount of radon- 232 decays. b. Write a general solution for this differential equation. c. If 1 gram of radon- 232 is isolated, how much of it will remain after 12 hours; after 4 days, 9 days, and 30 days?

Plow Patents The number of patents issued for plow sulkies between 1865 and 1925 was increasing with respect to time at a rate jointly proportional to the number of patents already obtained and to the difference between the number of patents already obtained and the carrying capacity of the system. The carrying capacity was approximately 2700 patents, and the constant of proportionality was about \(7.52 \cdot 10^{-5} .\) By 1883,980 patents had been obtained. (Source: Hamblin, Jacobsen, and Miller, \(A\) Mathematical Theory of Social Change, New York: Wiley, 1973 ) a. Write a differential equation describing the rate of change in the number of patents with respect to the number of years since 1865 b. Write a general solution for the differential equation. c. Write the particular solution for the differential equation. d. Estimate the number of patents obtained by 1900 .

Technetium-99 is a radioisotope that has been used in humans to help doctors locate possible malignant tumors. Radioisotopes decay (over time) at a rate described by the differential equation $$ \frac{d s}{d t}=k s $$ where \(s\) is the amount of the radioisotope and \(t\) is time. Technetium-99 has a half-life of 210,000 years. Assume that 0.1 milligram of technetium-99 is injected into a person's bloodstream. a. Write a differential equation for the rate at which the amount of technetium-99 decays. b. Find a particular solution for this differential equation.

Write an equation or differential equation for the given information. Water flows into a reservoir at a rate that is inversely proportional to the square root of the depth of water in the reservoir, and water flows out of the reservoir at a rate that is proportional to the depth of the water in the reservoir.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.