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a. Write the formula for \(\frac{d f}{d x}\). b. Write the formula for \(\int \frac{d f}{d x} d x\). $$ f(x)=22 x^{-3}-22 x^{3} $$

Short Answer

Expert verified
The derivative formula is \(\frac{df}{dx} = -66x^{-4} - 66x^2\) and the integral is \(\int \frac{df}{dx} \, dx = 22x^{-3} - 22x^3 + C\).

Step by step solution

01

Calculate the derivative of each term

Given the function \[f(x) = 22x^{-3} - 22x^3\]we need to find its derivative with respect to \(x\). Use the power rule for derivatives, which states that if \(f(x) = ax^n\), then \(f'(x) = anx^{n-1}\).- For the first term \(22x^{-3}\), the derivative is:\[\frac{d}{dx}(22x^{-3}) = 22 \cdot (-3)x^{-4} = -66x^{-4}\]- For the second term \(-22x^3\), the derivative is:\[\frac{d}{dx}(-22x^3) = -22 \cdot 3x^2 = -66x^2\]
02

Write the full derivative formula

Combine the derivatives of the individual terms to get the full derivative:\[\frac{df}{dx} = -66x^{-4} - 66x^2\]
03

Integrate the derivative function

Given the derivative function \(\frac{df}{dx} = -66x^{-4} - 66x^2\), we need to find the indefinite integral:Use the power rule for integration, which states that to integrate \(ax^n\), the result is \(\frac{a}{n+1}x^{n+1} + C\), where \(C\) is the constant of integration.- Integrating \(-66x^{-4}\):\[\int -66x^{-4} \, dx = -66 \cdot \frac{x^{-3}}{-3} = 22x^{-3}\]- Integrating \(-66x^2\):\[\int -66x^2 \, dx = -66 \cdot \frac{x^3}{3} = -22x^3\]
04

Write the full integral formula

Combine the integral results to get the full integral of the derivative:\[\int \left(-66x^{-4} - 66x^2\right) \, dx = 22x^{-3} - 22x^3 + C\]Note that this matches the original function \(f(x)\) up to the constant of integration \(C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Formula
The derivative of a function represents how the function changes as its input changes. It provides the rate of change or the slope of the function at any given point. In calculus, this is a foundational concept used to understand the behavior of functions.

The derivative formula, especially for polynomial functions, uses the *power rule*. For a term in the form of \(ax^n\), the derivative is obtained by multiplying the exponent \(n\) by the coefficient \(a\) and decreasing the exponent by 1. Therefore, the derivative is expressed as \(f'(x) = anx^{n-1}\).

For example, if we have \(f(x) = 22x^{-3}\) and \(f(x) = -22x^3\), the derivatives are calculated as follows:
  • For \(22x^{-3}\), derivative is \(-66x^{-4}\).
  • For \(-22x^3\), derivative is \(-66x^2\).
Combining these results gives the full derivative: \(\frac{df}{dx} = -66x^{-4} - 66x^2\). This derivative tells us how \(f(x)\) changes with \(x\), capturing increases or decreases at specific values.
Integral Formula
Integration is essentially the reverse process of differentiation. While a derivative gives us the rate of change, an integral allows us to determine the accumulated change, or area under a curve, over an interval.

The indefinite integral involves finding a function whose derivative is the integrand. We often use the *power rule* for integration, which is critical in solving polynomial integrals. For a function \(ax^n\), its indefinite integral is \(\frac{a}{n+1}x^{n+1} + C\), where \(C\) is the constant of integration.

For the derivative \(-66x^{-4} - 66x^2\), do the following integrations:
  • Integrating \(-66x^{-4}\) gives \(22x^{-3}\).
  • Integrating \(-66x^2\) gives \(-22x^3\).
Thus, the integral is \(22x^{-3} - 22x^3 + C\), which neatly ties back to the original function \(f(x)\). The presence of \(C\) reminds us that there are infinitely many antiderivatives that differ by a constant.
Power Rule
The power rule is a fundamental tool in both differentiation and integration, especially in handling polynomials. It simplifies the process of finding derivatives and integrals by providing a straightforward formula applicable to terms of the form \(ax^n\).

When using the power rule for differentiation, the rule is \(f'(x) = anx^{n-1}\). This means:
  • Multiply the term by the exponent \(n\).
  • Decrease the exponent by one to find the derivative.
For example, with \(22x^{-3}\) and \(-22x^3\), the power rule transforms them as indicated, yielding the derivatives \(-66x^{-4}\) and \(-66x^2\), respectively.

The power rule for integration is slightly different but equally important: \(\int ax^n \, dx = \frac{a}{n+1}x^{n+1} + C\). Here, you:
  • Increase the exponent by one.
  • Divide by the new exponent to find the integral.
Applying this to \(-66x^{-4}\) and \(-66x^2\) brings us back to \(22x^{-3} - 22x^3 + C\). Understanding the power rule helps simplify complex problems and is a core concept necessary to master calculus.

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