/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 a. Sketch graphs of the function... [FREE SOLUTION] | 91Ó°ÊÓ

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a. Sketch graphs of the functions \(f\) and \(g\) on the same axes, and shade the region between the graphs of \(f\) and \(g\) from \(a\) to \(b\). b. Calculate the area of the shaded region. $$ \begin{array}{l} f(x)=x^{2}-4 x+10 ; g(x)=2 x^{2}-12 x+14 \\ a=1 ; b=7 \end{array} $$

Short Answer

Expert verified
The area between the graphs from \( x=1 \) to \( x=7 \) is approximately 171.33 square units.

Step by step solution

01

Identifying the Functions

We have two functions to work with: \( f(x) = x^{2} - 4x + 10 \) and \( g(x) = 2x^{2} - 12x + 14 \). These are quadratic functions represented as parabolas when plotted on a graph.
02

Sketching the Graphs

Plot the graphs of \( f(x) \) and \( g(x) \) to visualize their shapes and intersections. Calculate a few points for each function by substituting values of \( x \), especially around critical points like intersections. Plot these points and draw the curves.
03

Finding the Intersection Points

Set the functions equal to find intersection points: \( f(x) = g(x) \). Solve \( x^{2} - 4x + 10 = 2x^{2} - 12x + 14 \). Rearrange to form \( x^{2} - 8x + 4 = 0 \) and apply the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). This yields intersection points \( x = 6 \pm 2\sqrt{2} \).
04

Shading the Region

The points of intersection are approximately \( x \approx 3.17 \) and \( x \approx 8.83 \), so the shading in practice is between these points. However, as we're asked to find the area from \( a = 1 \) to \( b = 7 \), we focus shading between \( x=1 \) and \( x=7 \).
05

Setting Up the Integral for Area

Find the area between the curves by setting up the integral of the difference \( |f(x) - g(x)| \) from \( a = 1 \) to \( b = 7 \). The integrand \( |f(x) - g(x)| = |-(x^2 - 8x + 4)| = x^2 - 8x + 4 \) because it remains positive over this interval.
06

Calculating the Integral

Compute \( \int_{1}^{7} (x^{2} - 8x + 4) \, dx \). This integral breaks down to: \( \frac{x^3}{3} - 4x^2 + 4x \) evaluated from \( 1 \) to \( 7 \).
07

Evaluating the Integral

Substitute \( x = 7 \) into the antiderivative: \[ \frac{7^3}{3} - 4\times7^2 + 4\times7 = \frac{343}{3} - 196 + 28 = \frac{343}{3} - 168 \]. Then substitute \( x = 1 \): \[ \frac{1}{3} - 4 + 4 = \frac{1}{3} \]. Calculate the difference: \[ \frac{343}{3} - 168 - \frac{1}{3} = \frac{171.5}{3} \]. Therefore, the exact area is \( \frac{514}{3} \approx 171.33 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Functions
A quadratic function is represented by the formula \( f(x) = ax^2 + bx + c \). These functions graph as parabolas that open either upwards or downwards. The sign of the coefficient \( a \) determines the direction of the parabola:
  • If \( a > 0 \), the parabola opens upwards.
  • If \( a < 0 \), the parabola opens downwards.
In the given exercise, we have two quadratic functions: \( f(x) = x^2 - 4x + 10 \) and \( g(x) = 2x^2 - 12x + 14 \). These functions create two distinct parabolas when plotted. Understanding the characteristics of quadratic functions helps predict their shape and behavior on a graph.
Intersection Points
Intersection points are crucial for determining where two functions meet on a graph. To find these points, set the equations equal to each other: \( f(x) = g(x) \). For our functions, \( x^2 - 4x + 10 = 2x^2 - 12x + 14 \). Rearrange this to \( x^2 - 8x + 4 = 0 \).

Quadratic Formula

Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to solve for \( x \). Here, \( a = 1 \), \( b = -8 \), and \( c = 4 \). Calculating gives \( x = 6 \pm 2\sqrt{2} \). Hence, the functions intersect approximately at \( x \approx 3.17 \) and \( x \approx 8.83 \). These points help us understand the interval within which we calculate the area between the curves.
Integral Calculation
The integral helps calculate the area between two curves. Once you identify where the curves intersect, you use these points to set the bounds of the integral. For our problem, despite the intersection, the exercise restricts the calculation between \( x = 1 \) and \( x = 7 \).

Setting Up the Integral

To find the area between \( f(x) \) and \( g(x) \), compute the integral of the difference \( |f(x) - g(x)| \). For the interval \( 1 \) to \( 7 \), \( f(x) - g(x) = -(x^2 - 8x + 4) \). Simplify to get \( x^2 - 8x + 4 \), since this is positive over our interval.Use the calculated integral \( \int_{1}^{7} (x^2 - 8x + 4) \ dx \). For each term inside the integral, apply the power rule: \( \int x^n \ dx = \frac{x^{n+1}}{n+1} \). Thus, \( \frac{x^3}{3} - 4x^2 + 4x \). Evaluate it from 1 to 7 to get the area.
Graph Sketching
Graph sketching involves plotting both functions on the same axes to visualize their interaction. This step is essential for identifying regions of interest and gaining intuitive insight into the problem. Start by choosing several points for each function by substituting values into the equations.

Steps for Graph Sketching

  • Calculate a few values for \( f(x) \) and \( g(x) \) by substituting \( x \) values, especially near suspected intersections or turning points.
  • Plot these points carefully on the graph. The more points you calculate, the more accurate your sketch becomes.
  • Draw smooth curves through these points since both functions are quadratic and exhibit a parabolic shape.
  • Identify and shade the region between the curves from \( x = 1 \) to \( x = 7 \) as specified.
Graph sketching aids in visualizing the complexity of the area being calculated and solidifies understanding of the functions' interactions.

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Most popular questions from this chapter

Star Pulses On December \(15,1995,\) a team of astronomers discovered X-ray pulses being emitted from what they believe to be a neutron star. The speed of the pulses can be modeled as \(p(s)=40.5 \sin (0.01345 s-1.5708)+186.5\) where output is measured in pulses per second and \(s\) is measured in milliseconds. a. Convert \(p(s)\) to pulses per millisecond. There are 1000 milliseconds in 1 second. b. Calculate and interpret the area between the graph of \(p\) and the s-axis for one period of the function, beginning at \(s=0\).

Is it important to know whether where a function has horizontal-axis intercepts before using a definite integral (limit of sums) to determine the area of the region(s) bounded by the function and the horizontal axis? Explain.

Stopping Distance Suppose a person driving down a road at \(88 \mathrm{ft} / \mathrm{sec}\) sees a deer on the road 200 feet in front of him. His car's brakes, once they have been applied, produce a constant deceleration of \(24 \mathrm{ft} / \mathrm{sec}^{2} .\) He applies the brakes \(1 / 2\) second after he sees the deer. Can he stop in time or will he hit the deer? Explain.

New York Temperature (Historic) The rate of change of the average temperature in New York from 1873 through 1923 can be modeled as $$ T^{\prime}(x)=11.4 \cos (0.524 x-2.27)^{\circ} \mathrm{F} \text { per month } $$ where \(x=1\) in January, \(x=2\) in February, and so on. a. Write a model for the average temperature in New York. The average temperature in July is \(73.5^{\circ} \mathrm{F}\). b. What does the model give as the average temperature in December? c. Calculate and interpret the value of \(\int_{2}^{8} T^{\prime}(x) d x\).

Natural Gas Production (Historic) The table shows the estimated production rate of marketed natural gas, in trillion cubic feet per year, in the United States (excluding Alaska). a. Find a model for the data in the table. b. Use the model to estimate the total production of natural gas from 1940 through 1960. c. Write the definite integral notation for the answer to part \(b\) Estimated Production Bate of Marketed Natural Gas $$ \begin{array}{|c|c|} \hline \text { Year } & \begin{array}{c} \text { Estimated production rate } \\ \text { (trillion cubic feet per year) } \end{array} \\ \hline 1900 & 0.1 \\ \hline 1910 & 0.5 \\ \hline 1920 & 0.8 \\ \hline 1930 & 2.0 \\ \hline 1940 & 2.3 \\ \hline 1950 & 6.0 \\ \hline 1960 & 12.7 \\ \hline \end{array} $$

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