/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 a. Sketch graphs of the function... [FREE SOLUTION] | 91Ó°ÊÓ

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a. Sketch graphs of the functions \(f\) and \(g\) on the same axes, and shade the region between the graphs of \(f\) and \(g\) from \(a\) to \(b\). b. Calculate the area of the shaded region. $$ f(x)=10\left(0.85^{x}\right) ; g(x)=6\left(0.75^{x}\right) ; a=2 ; b=10 $$

Short Answer

Expert verified
The area of the shaded region is approximately 6.46 square units.

Step by step solution

01

Graphing the Functions

First, we need to graph both functions, \(f(x) = 10(0.85^x)\) and \(g(x) = 6(0.75^x)\), from \(x = 2\) to \(x = 10\). function \(f(x) = 10(0.85^x)\) is an exponential decay graph starting from a higher point since it is being multiplied by 10. For \(g(x) = 6(0.75^x)\), it is also an exponential decay function, starting lower than \(f(x)\) since it is multiplied by 6.The graphs should show that \(f(x)\) consistently remains above \(g(x)\) in the interval [2, 10].
02

Finding the Points of Intersection

Although not explicitly requested, checking if there's an intersection between the functions in the given interval can be useful.Set the functions equal: \[10(0.85^x) = 6(0.75^x)\]. Solve for \(x\), though anticipation indicates that the curves will not intersect between \(x = 2\) and \(x = 10\) because of the different rates of decay. The consideration will focus on \(f(x) - g(x)\).
03

Setting Up the Integral

To find the area of the region between the curves \(f(x)\) and \(g(x)\), the integral should be set up as follows:\[ A = \int_{a}^{b} [f(x) - g(x)] \, dx \]This will become:\[ A = \int_{2}^{10} [10(0.85^x) - 6(0.75^x)] \, dx \]
04

Solving the Integral

We'll evaluate the integral separately for both components.The integral of \(10(0.85^x)\) is \(\frac{10}{\ln(0.85)}(0.85^x)\), and for \(6(0.75^x)\) is \(\frac{6}{\ln(0.75)}(0.75^x)\).Plug these results back into the integral expression and evaluate from \(x = 2\) to \(x = 10\).
05

Calculating and Simplifying

Calculate the resulting expressions from the evaluations above:\[ \int_{2}^{10} 10(0.85^x) \, dx = \left[ \frac{10}{\ln(0.85)} (0.85^x) \right]_{2}^{10} \]\[ \int_{2}^{10} 6(0.75^x) \, dx = \left[ \frac{6}{\ln(0.75)} (0.75^x) \right]_{2}^{10} \]Final area calculation subtracts these terms to give the area under \(f(x)\) minus the area under \(g(x)\), thus providing the area of the shaded region.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Exponential Functions
Exponential functions play a vital role in mathematics, characterized by their consistent rate of change. To graph these functions, we look at their forms. Here, we have two specific functions: \(f(x) = 10(0.85^x)\) and \(g(x) = 6(0.75^x)\). Both are examples of exponential decay because their bases (0.85 and 0.75) are less than one. This means these functions decrease as \(x\) increases.
To graph these functions:
  • Identify the point where each graph starts by evaluating the function at \(x = 0\). \(f(0) = 10\) and \(g(0) = 6\).
  • Observe that \(f(x)\) begins higher than \(g(x)\) and declines less steeply, as 0.85 is closer to 1 than 0.75 is.
  • The interval of interest is from \(x = 2\) to \(x = 10\), where we sketch these functions to see how they behave in this range.
  • Shade the area between the two curves to highlight the region of interest.
By analyzing their equations and sketching their graphs, you get a deeper insight into how exponential functions reduce over an interval, especially with different bases.
Integration of Exponential Functions
Integration is the mathematical process of finding the area under a curve. For exponential functions like \(f(x) = 10(0.85^x)\) and \(g(x) = 6(0.75^x)\), the integration process provides the cumulative area from one point to another along the \(x\)-axis.
Exponential functions have a specific property: The integral of \(a^x\) is given by \(\frac{a^x}{\ln(a)}\), where \(\ln(a)\) is the natural logarithm of \(a\). Applying this to our functions:
  • The integral of \(f(x) = 10(0.85^x)\) is \(\frac{10(0.85^x)}{\ln(0.85)}\).
  • For \(g(x) = 6(0.75^x)\), the integral is \(\frac{6(0.75^x)}{\ln(0.75)}\).
When performing these integrations over a specific interval, say from \(x = 2\) to \(x = 10\), we evaluate each at the upper and lower bounds, then subtract. Using integration formulas for exponential functions is handy because it standardizes the process and minimizes errors. This makes it easier to calculate the desired area.
Calculating Areas Between Curves
The area between curves is a common problem in calculus that requires both graphing and integration skills. When you're asked to find the area between two curves—like with \(f(x) = 10(0.85^x)\) and \(g(x) = 6(0.75^x)\) from \(x = 2\) to \(x = 10\)—you first find the difference between the two functions in terms of integration.
To set this up, the integral for the area \(A\) is:
  • \[ A = \int_{2}^{10} [f(x) - g(x)] \, dx = \int_{2}^{10} [10(0.85^x) - 6(0.75^x)] \, dx \]
The steps to calculate this include:
  • Individually integrate each function over the given bounds.
  • Evaluate these integrals at \(x = 10\) and \(x = 2\), then subtract the lower bound from the upper bound value.
  • Finally, subtract the integrated area under \(g(x)\) from that under \(f(x)\) to find the total area between the two curves.
Calculating areas between curves is essential for understanding differences in growth patterns, which is widely applicable in fields such as economics and environmental sciences.

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