/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 a. Graph \(g, g^{\prime}\), and ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

a. Graph \(g, g^{\prime}\), and \(g^{\prime \prime}\) between \(x=0\) and \(x=15 .\) Indicate the relationships among points on the three graphs that correspond to maxima, minima, and inflection points. b. Calculate the input and output of the inflection point on the graph of \(g .\) Is it a point of most rapid decline or least rapid decline? \(g(x)=0.04 x^{3}-0.88 x^{2}+4.81 x+12.11\)

Short Answer

Expert verified
Inflection point is at approximately \( x = 7.33 \), where the concavity changes.

Step by step solution

01

Understanding the Function and Derivatives

First, identify the given function: \[ g(x) = 0.04x^3 - 0.88x^2 + 4.81x + 12.11 \] Next, find its first and second derivatives:1. The first derivative \( g'(x) \) is obtained by differentiating \( g(x) \): \[ g'(x) = 0.12x^2 - 1.76x + 4.81 \]2. The second derivative \( g''(x) \) is obtained by differentiating \( g'(x) \): \[ g''(x) = 0.24x - 1.76 \]
02

Finding Critical Points

The critical points occur where the first derivative \( g'(x) \) is zero or undefined. Solve \( g'(x) = 0 \):\[ 0.12x^2 - 1.76x + 4.81 = 0 \] This quadratic equation can be solved using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Substitute \( a = 0.12, b = -1.76, c = 4.81 \) and solve.
03

Determining Inflection Points

Inflection points occur where the second derivative \( g''(x) \) changes sign. Solve \( g''(x) = 0 \):\[ 0.24x - 1.76 = 0 \]Solve for \( x \):\[ x = \frac{1.76}{0.24} \approx 7.33 \]
04

Evaluating Function at the Inflection Point

Find the output value of \( g(x) \) at the inflection point (\( x \approx 7.33 \)):\[ g(7.33) = 0.04(7.33)^3 - 0.88(7.33)^2 + 4.81(7.33) + 12.11 \]Calculate this to find the y-coordinate of the inflection point.
05

Graphical Representation and Analysis

Graph the original function \( g(x) \), its first derivative \( g'(x) \), and second derivative \( g''(x) \) on the same axes.1. Identify maxima and minima by locating zeros or changes in sign of \( g'(x) \).2. Identify inflection points by locating zeros or changes in sign of \( g''(x) \).Analyze the inflection point \( (7.33, g(7.33)) \) to determine if it represents the point of most or least rapid decline by observing the behavior of the slope.
06

Conclusion

The inflection point occurs at approximately \( (7.33, g(7.33)) \). Since \( g'(x) \) changes sign at this point and \( g''(x) \) is zero, it's a point where the concavity changes, indicating a change in the slope but not necessarily the most rapid decline.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
In calculus, a derivative represents the rate at which a function changes at any given point on its curve. The derivative is the slope of the tangent line to the curve of the function at that point. Calculating derivatives is essential for understanding the behavior of functions.
For the function \( g(x) = 0.04x^3 - 0.88x^2 + 4.81x + 12.11 \), the first derivative \( g'(x) = 0.12x^2 - 1.76x + 4.81 \) helps us identify the function's rate of change. It gives information about critical points where the function may cover maxima or minima.
The second derivative \( g''(x) = 0.24x - 1.76 \) reveals information about the concavity of the function, necessary for finding inflection points.
Critical Points
Critical points occur where the first derivative of the function, \( g'(x) \), is zero or does not exist. These points indicate where a function's rate of change is either a minimum or maximum—essentially, the points at which the graph of the function changes direction between increasing and decreasing.
For \( g'(x) = 0.12x^2 - 1.76x + 4.81 \), we find the critical points by solving \( g'(x) = 0 \). This is achieved using the quadratic formula or other algebraic methods.
Critical points do not always represent local maxima or minima, as the second derivative test or a graphical analysis might further clarify these points' nature.
Inflection Points
An inflection point on a graph is where the function changes concavity, transitioning from concave up (like a cup) to concave down (like a hill), or vice versa. It occurs where the second derivative \( g''(x) \) equals zero or changes sign.
For our function, solving \( g''(x) = 0 \) gives \( 0.24x - 1.76 = 0 \), resulting in \( x \approx 7.33 \). At this point, the function \( g(x) \) changes concavity, indicating significant changes in the rate of increase or decrease, often correlated with changes in acceleration or deceleration of the function's values.
This change at \( x \approx 7.33 \) might also suggest a shift in the nature of the slopes of tangents at points near this value.
Quadratic Equation
A quadratic equation is a polynomial equation of degree two, with the general form \( ax^2 + bx + c = 0 \). It's pivotal in finding critical points when dealing with a function's first derivative.
For the equation \( 0.12x^2 - 1.76x + 4.81 = 0 \), derived from \( g'(x) \), the quadratic formula helps us find solutions, significant for identifying critical points.
The quadratic formula is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a \), \( b \), and \( c \) are coefficients in the quadratic equation. This allows us to systematically find values of \( x \) where the slope of the function is zero, important for identifying potential maximum, minimum, or inflection points.
Graphical Analysis
Graphical analysis involves plotting a function and its derivatives to visually interpret the behaviors like maxima, minima, and inflection points. By graphing \( g(x) \), \( g'(x) \), and \( g''(x) \), we can see where the first derivative changes sign to locate critical points, and where the second derivative changes sign to find inflection points.
Through graphical analysis:
  • Maxima and minima are indicated where \( g'(x) = 0 \) and the sign changes.
  • Inflection points appear where \( g''(x) = 0 \) and the concavity of the graph changes.
Graphical analysis not only supports algebraic solutions but also provides an intuitive sense of the function's overall behavior.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the indicated related-rates equation. $$ y=9 x^{3}+12 x^{2}+4 x+3 ; \text { relate } \frac{d y}{d t} \text { and } \frac{d x}{d t} $$

Helium gas is being pumped into a spherical balloon at a rate of 5 cubic feet per minute. The pressure in the balloon remains constant. a. What is the volume of the balloon when its diameter is 20 inches? b. At what rate is the radius of the balloon changing when the diameter is 20 inches?

Senior Population (Predicted) The U.S. Bureau of the Census prediction for the percentage of the population 65 years and older can be modeled as $$ p(x)=0.00022 x^{3}+0.014 x^{2}-0.0033 x+12.236 \% $$ where \(x\) is the number of years since 2000 , data from \(0 \leq x \leq 50\) (Source: Based on data from U.S. Census Bureau, National Population Projections, 2008.) a. When do the relative extrema between 2000 and 2050 occur? What are the extreme values? b. What are the absolute maximum and minimum values between 2000 and 2050 and when do they occur?

An auto dealer offers an additional discount to fleet buyers who purchase one or more new cars. To encourage sales, the dealer reduces the price of each car by a percentage equal to the total number of cars purchased. For example, a fleet buyer purchasing 12 cars will receive a \(12 \%\) discount. a. Assuming that the preincentive price of a car is \(\$ 14,400,\) write a model for the after-incentive price of each car as a function of the number of cars purchased. b. Write a model for the auto dealer's revenue as a function of the number of cars purchased by the fleet buyer. c. How many cars should the dealer sell to maximize revenue? What is the maximum possible revenue?

For Activities 7 through \(18,\) write the first and second derivatives of the function. \(f(s)=32 s^{3}-2.1 s^{2}+7 s\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.