/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Sketch the graph of a function \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch the graph of a function \(f\) such that all of the following statements are true. \- \(f^{\prime}(x)>0\) for \(x<-1\) \- \(f^{\prime}(x)<0\) for \(x>-1\) \- \(f^{\prime}(-1)=0\)

Short Answer

Expert verified
The graph is an upside-down "V" with a peak at \(x = -1\).

Step by step solution

01

Determine the Nature of the Function

Given that \(f'(x) > 0\) for \(x < -1\), the function is increasing on the interval \((-\infty, -1)\). For \(x > -1\), since \(f'(x) < 0\), the function is decreasing on the interval \((-1, \infty)\). These changes suggest that the function has a relative maximum at \(x = -1\) because the derivative changes from positive to negative, and \(f'(-1) = 0\).
02

Identify the Critical Point

The critical point occurs where the derivative is zero or undefined. Since \(f'(-1) = 0\) and there is a change from increasing to decreasing, \(x = -1\) is a critical point, specifically a relative maximum of the function.
03

Sketch the Function

With the information that the function increases before \(x = -1\) and decreases after, sketch the graph. Start by drawing an increasing section that peaks at \(x = -1\) before proceeding to a decreasing section after \(x = -1\). The shape resembles an upside-down \"V\" or a \"mountain peak\" centered at \(x = -1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Point
In the context of graph sketching, a critical point is a point on the graph of a function where the derivative is either zero or undefined. Critical points are important because they indicate potential turning points in the graph, such as maxima, minima, or inflection points.
In our exercise, the function's derivative, denoted as \(f'(x)\), equals zero at \(x = -1\). This marks \(x = -1\) as a critical point.
To identify whether this critical point is a maximum, minimum, or inflection involves further analysis, such as using the first derivative test. In this case, given the information that the function's derivative changes from positive to negative at \(x = -1\), this critical point is determined to be a local maximum.
Recognizing these points is crucial when sketching graphs because they give vital information about the behavior of the function and help in interpreting the function's graph accurately.
Remember:
  • Critical points occur where \( f'(x) = 0\) or \( f'(x)\) is undefined.
  • They help to identify potential turning points on a graph.
Increasing and Decreasing Functions
When sketching a graph, understanding where a function is increasing or decreasing is key. A function is said to be increasing on an interval if its derivative is positive over that interval. Conversely, it is decreasing if the derivative is negative.
From the problem scenario:
  • For \(x < -1\), \(f'(x) > 0\) indicates the function is increasing.
  • For \(x > -1\), \(f'(x) < 0\) implies the function is decreasing.
This change highlights how the function behaves before and after the critical point at \(x = -1\). Graphically, this translates to the function rising towards \(x = -1\) and then falling after passing \(x = -1\).
Recognizing intervals of increase and decrease allows us to construct the graph's overall shape and predict where it might peak or valley. In this exercise, the function creates a peak at \(x = -1\).
Key points to keep in mind:
  • A positive derivative signifies an increasing function.
  • A negative derivative denotes a decreasing function.
First Derivative Test
The first derivative test is a useful method for determining the nature of critical points on a graph of a function. It is commonly used to decide whether a critical point is a local maximum, local minimum, or neither.
In our specific case, we used the first derivative test to examine the function around \(x = -1\). Since:
  • The function transitions from increasing (\(f'(x) > 0\)) to decreasing (\(f'(x) < 0\)) across the point \(x = -1\).
  • We can conclude that there is a local maximum at \(x = -1\).
This result is consistent with the rules of the first derivative test:
  • If \(f'(x)\) changes from positive to negative, the function has a local maximum at that point.
  • If it changes from negative to positive, it indicates a local minimum.
  • If there is no sign change, the critical point may not be a maximum or minimum.
The first derivative test is a powerful tool to add clarity when sketching the overall shape of functions by identifying where peaks and valleys might occur.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the indicated related-rates equation. $$ g=e^{15 x^{2}} ; \text { relate } \frac{d g}{d t} \text { and } \frac{d x}{d t} $$

Natural Gas Price The average price (per 1000 cubic feet) of natural gas for residential use can be modeled as $$ p(x)=0.0987 x^{4}-2.1729 x^{3}+17.027 x^{2}-55.023 x $$ +72.133 dollars where \(x\) is the number of years since 2000 , data from \(3 \leq x \leq 8\) (Source: Based on data from Energy Information Administration's Natural Gas Monthly, October 2008 and August 2009\()\) a. Locate the two inflection points on the interval \(4

Senior Population (Projected) The U.S. Bureau of the Census prediction for the percentage of the population 65 years and older can be modeled as $$ \begin{aligned} p(x)=&-0.00022 x^{3}+0.014 x^{2} \\ &-0.0033 x+12.236 \text { percent } \end{aligned} $$ where \(x\) is the number of years since \(2000,\) data from \(0 \leq x \leq 50\) (Source: Based on data from U.S. Census Bureau, National Population Projections, \(2008 .)\) a. Determine the year between 2000 and 2050 in which the percentage is predicted to be increasing most rapidly, the percentage at that time, and the rate of change of the percentage at that time. b. Repeat part \(a\) for the most rapid decrease.

A leaking container of salt is sitting on a shelf in a kitchen cupboard. As salt leaks out of a hole in the side of the container, it forms a conical pile on the counter below. As the salt falls onto the pile, it slides down the sides of the pile so that the pile's radius is always equal to its height. The height of the pile is increasing at a rate of 0.2 inch per day. a. How quickly is the salt leaking out of the container when the pile is 2 inches tall? b. How much salt has leaked out of the container by this time?

A cable company needs to run a cable line from its main line ending at point \(P\) to point \(H\) at the corner of a house. See below. The county owns the roads marked with dotted lines in the figure, and it costs the cable company 25 per foot to run the line on poles along the county roads. The area bounded by the house and roads is a privately owned field, and the cable company must pay for an easement to run lines underground in the field. It is also more costly for the company to run lines underground than to run them on poles. The total cost to run the lines underground across the field is 52 per foot. The cable company has the choice of running the line along the roads ( 100 feet north and 125 feet west) or cutting across the field. a. Calculate the cost to run the line along the roads from P to H b. Calculate the cost to run the line directly across the field from P to H. c. Set up an equation for the cost to run the line along the road a distance of \(x\) feet from point \(P\) and then cut across the field. d. Determine whether it is less costly for the company to cut across the field. If so, at what distance from point \(P\) should the company begin laying the line through the field?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.