/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 For Activities 7 through \(18,\)... [FREE SOLUTION] | 91Ó°ÊÓ

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For Activities 7 through \(18,\) write the first and second derivatives of the function. \(g(x)=e^{3 x}-\ln 3 x\)

Short Answer

Expert verified
First derivative: \( g'(x) = 3e^{3x} - \frac{1}{x} \). Second derivative: \( g''(x) = 9e^{3x} + \frac{1}{x^2} \).

Step by step solution

01

Identify the Function Components

The function given is \( g(x) = e^{3x} - \ln(3x) \). It consists of two components: \( e^{3x} \) and \( \ln(3x) \). We need to find the derivatives of each part separately.
02

Compute the First Derivative of \( e^{3x} \)

The first derivative of \( e^{3x} \) with respect to \( x \) is an application of the chain rule. The derivative of \( e^{u} \) with respect to \( u \) is \( e^{u} \), and the derivative of \( 3x \) with respect to \( x \) is \( 3 \). Thus, \( \frac{d}{dx} e^{3x} = 3e^{3x} \).
03

Compute the First Derivative of \( \ln(3x) \)

The derivative of \( \ln(3x) \) with respect to \( x \) also uses the chain rule. The derivative of \( \ln(u) \) is \( \frac{1}{u} \), so the derivative of \( \ln(3x) \) is \( \frac{1}{3x} \). Additionally, the derivative of \( 3x \) with respect to \( x \) is \( 3 \). Thus, \( \frac{d}{dx} \ln(3x) = \frac{1}{3x} \cdot 3 = \frac{1}{x} \).
04

Combine First Derivatives

Combine the derivatives of both components to find the first derivative of the entire function:\[ g'(x) = \frac{d}{dx} \left(e^{3x}\right) - \frac{d}{dx} \left(\ln(3x)\right) = 3e^{3x} - \frac{1}{x} \].
05

Compute the Second Derivative of \( e^{3x} \)

Applying the chain rule again, the derivative of \( 3e^{3x} \) is \( 3 \) times the derivative of \( e^{3x} \), which we calculated as \( 3e^{3x} \). Hence, the second derivative is \( 9e^{3x} \).
06

Compute the Second Derivative of \( -\frac{1}{x} \)

The derivative of \(-\frac{1}{x}\) is \( \frac{1}{x^2} \). Therefore, the second derivative is \( \frac{d}{dx}\left(-\frac{1}{x}\right) = \frac{1}{x^2} \).
07

Combine Second Derivatives

Combine the second derivatives to find the second derivative of the entire function:\[ g''(x) = \frac{d}{dx}\left(3e^{3x}\right) - \frac{d}{dx}\left(-\frac{1}{x}\right) = 9e^{3x} + \frac{1}{x^2} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental concept in calculus used to differentiate composite functions. A composite function is a function of another function. For example, in our problem, we have the function
  • \( e^{3x} \)
  • \( \ln(3x) \)
Here, both contain inner functions:
  • \( 3x \) inside \( e^{3x} \)
  • \( 3x \) inside \( \ln(3x) \)
To apply the chain rule, first differentiate the outer function, then multiply by the derivative of the inner function.
For \( e^{3x} \), the derivative of \( e^u \) with respect to \( u \) is \( e^u \), while the derivative of the inner function \( 3x \) is \( 3 \). Therefore, the derivative is \( 3e^{3x} \).
Similarly, for \( \ln(3x) \), differentiate \( \ln(u) \) to obtain \( \frac{1}{u} \) and multiply by the derivative of \( 3x \) which is \( 3 \), obtaining \( \frac{3}{3x} = \frac{1}{x} \).
The chain rule simplifies the process of finding derivatives for complex expressions by using this step-by-step approach to tackle both the inner and outer components.
Exponential Functions
Exponential functions are ubiquitous in mathematics and sciences, providing a model for growth processes.
The general form for exponential functions is \( e^{f(x)} \), where \( e \) is the base of the natural logarithm, approximately equal to 2.718.
In calculus, these functions have a particularly straightforward derivative: the derivative of \( e^{u} \) is \( e^{u} \) itself, multiplied by the derivative of the exponent \( u \).
  • For example, \( e^{3x} \) has an exponent \( 3x \). So like we calculated earlier, its derivative is \( 3e^{3x} \).
Exponential functions grow exceptionally fast, and understanding their rates of change, thanks to simple derivatives, is crucial in fields like finance, physics, and biology.
With the chain rule, handling the exponential growth of different functions becomes straightforward.
Logarithmic Functions
Logarithmic functions are the inverse of exponential functions and are vital in scenarios where growth slows down. They are represented by \( \ln(x) \) involving the natural logarithm.
  • The derivative of a logarithmic function like \( \ln(u) \) is \( \frac{1}{u} \), which provides the slope of the function at any point.
However, note that we often encounter composite forms such as \( \ln(3x) \), which requires the chain rule to derive.
Calculating the derivative involves finding \( \frac{1}{3x} \) and multiplying by the inner derivative \( 3 \), resulting in \( \frac{1}{x} \).
The typical way a logarithmic function behaves is that it increases at a decreasing rate, which explains why it becomes integral in understanding scenarios like diminishing returns or measured decay processes.

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