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College Tuition The tuition \(x\) years from now at a private four-year college is projected to be $$ t(x)=24,072 e^{0.056 x} \text { dollars. } $$ a. Write the rate-of-change formula for tuition. b. What is the rate of change in tuition four years from now?

Short Answer

Expert verified
a. \( t'(x) = 1,348.032 e^{0.056x} \); b. \( t'(4) \approx 1,686.94 \).

Step by step solution

01

Understanding the Function

The given function is \( t(x) = 24,072 e^{0.056x} \), which represents the tuition cost at a private four-year college \( x \) years from now. Our task is to find the rate of change of this function, which involves finding its derivative.
02

Finding the Derivative

The rate-of-change formula is the derivative of \( t(x) \). Since \( t(x) = 24,072 e^{0.056x} \), we apply the derivative rule for exponential functions: if \( f(x) = a e^{bx} \), then \( f'(x) = a b e^{bx} \). Thus, \( t'(x) = 24,072 \times 0.056 e^{0.056x} \). Simplifying gives \( t'(x) = 1,348.032 e^{0.056x} \).
03

Calculating Rate of Change at Four Years

Now, we need to find \( t'(4) \), the rate of change three years from now. Substitute \( x = 4 \) into the derivative \( t'(x) \). Thus, \( t'(4) = 1,348.032 e^{0.056 \times 4} = 1,348.032 e^{0.224} \).
04

Simplifying the Expression

Calculate \( e^{0.224} \) using a calculator, which is approximately 1.251. Therefore, \( t'(4) = 1,348.032 \times 1.251 = 1,686.935 \).
05

Final Result

The rate of change in tuition four years from now is approximately $1,686.94 per year.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Change in Tuition Costs
The rate of change is a concept that shows how quickly something is increasing or decreasing over time. In the context of college tuition, it tells us how fast the tuition fees are expected to rise. For example, in our tuition problem, the rate of change is derived from the function that models the tuition cost over time. The formula for the rate of change is the derivative of the given function. It helps us understand if the tuition is increasing at a steady rate, or if it might be accelerating or slowing down over the years. When the rate of change is calculated, it provides us with a concrete number that indicates how much more (or possibly less) students might expect to pay each year.
Understanding Derivatives
Derivatives are fundamental to calculus and play a crucial role in understanding change of a function. In simple terms, a derivative tells us the slope of the tangent line to the function at any given point, which means it can indicate the rate of change at that point. For exponential functions, like our tuition model, finding the derivative is a key step. The rule we used, which states that the derivative of \(a e^{bx}\) is \(a b e^{bx}\), allows us to quickly determine how tuition is changing with respect to time from our base function \(t(x) = 24,072 e^{0.056x}\). Finding the derivative, in this case, tells us exactly how fast the tuition costs are increasing per year, which helps students and families plan financially for future education expenses.
Modeling College Tuition
Modeling with exponential functions is a common approach to project future tuition costs. The initial tuition cost is set at a base value that becomes the coefficient in the exponential function. The exponent generally reflects a growth rate or rate of change over time. In our case, the tuition function \(t(x) = 24,072 e^{0.056x}\) models how the tuition will rise over \(x\) years. This model accounts for compounded growth, which means the tuition not only goes up each year but increases based on its current value. Using such models helps colleges predict future financial needs and can inform budgeting decisions both for institutions and students planning their educational pursuits. As tuition costs continue to rise, having accurate models is crucial for making informed decisions.

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