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Write derivative formulas for the functions. $$ f(x)=(x+5) e^{x} $$

Short Answer

Expert verified
The derivative is \( f'(x) = e^x(x + 6) \).

Step by step solution

01

Identify the Function Structure

The given function is a product of two functions: \( u(x) = x+5 \) and \( v(x) = e^x \). This classification indicates the use of the product rule for differentiation.
02

Recall the Product Rule Formula

The product rule for differentiation states that if \( h(x) = u(x) \cdot v(x) \), then \( h'(x) = u'(x) \cdot v(x) + u(x) \cdot v'(x) \). We'll apply this rule to our function by differentiating each part.
03

Differentiate Each Component

First, differentiate \( u(x) = x + 5 \). Since \( u(x) = x + 5 \) is a simple linear function, its derivative is \( u'(x) = 1 \).Next, differentiate \( v(x) = e^x \). The derivative of \( e^x \) is \( v'(x) = e^x \).
04

Apply the Product Rule

Using the product rule, substitute the derivatives into the formula: \[ h'(x) = u'(x)v(x) + u(x)v'(x) \]Substitute the values we found: \[ h'(x) = (1) imes e^x + (x+5) imes e^x \]
05

Simplify the Expression

Combine the terms:\[ h'(x) = e^x + (x+5)e^x = e^x(1 + x + 5) = e^x(x + 6) \]
06

Conclusion

The derivative of the function \( f(x) = (x+5) e^x \) is \( f'(x) = e^x(x + 6) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus that involves finding the rate at which a function changes with respect to a variable. In simple terms, it is used to calculate the derivative of a function. In this exercise, we are differentiating a function provided in a product form, specifically \(f(x) = (x+5)e^x\). This represents two functions multiplied together, where differentiation needs to be applied using specific rules.

Differentiating functions allow us to identify the slope of a curve at any given point, which can be particularly useful for understanding how quantities change.
  • Gives insight into the behavior of functions
  • Enables curve sketching and understanding function dynamics
  • Essential in fields like physics and engineering for analyzing motion and growth
Grasping differentiation helps in mastering the process of finding derivatives, as seen in mathematical problems like this one.
Derivative Formulas
Derivative formulas provide a structured method to find the derivative of functions. These formulas involve specific rules, like the product rule, which is crucial for functions composed of multiple sub-functions.

For a function like \( h(x) = u(x) \, v(x) \), the product rule states that the derivative is \( h'(x) = u'(x) \, v(x) + u(x) \, v'(x) \). This rule is applicable when differentiating products of two separate entities, guiding us through the process of how to handle each component correctly.

Understanding derivative formulas is vital for solving complex differentiation problems.
  • Product Rule: applies when differentiating products of functions
  • Chain Rule: useful for nested functions differentiation
  • Quotient Rule: applies to ratios of functions
The proper application of these formulas ensures accurate results and functionality in resolving calculus problems.
Exponential Functions
Exponential functions, such as \( e^x \), play a major role in calculus due to their unique properties. The function \( e^x \) is especially noteworthy, as its derivative is the same as the original function itself. This makes calculations involving exponential functions both intriguing and slightly more straightforward.

In the problem presented, we examine how the exponential function interacts with linear functions through multiplication, forming the composite function \( (x+5)e^x \). By understanding how differentiation impacts each part, students learn to manage more complex equations that incorporate exponential elements.
  • Recognized for constant rates of growth or decay
  • Essential in calculations regarding natural logarithms
  • Integral in various scientific and financial models
Exponential functions remain a key concept in calculus for their easing attention in differentiation and other advanced mathematical discussions.

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