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Garbage Removal The population of a city in the Northeast is given by $$ p(t)=130\left(1+12 e^{-0.02 t}\right)^{-1} \text {thousand people } $$ where \(t\) is the number of years since \(2010 .\) The number of garbage trucks needed by the city can be modeled as $$ g(p)=2 p-0.001 p^{3} \text { garbage trucks } $$ where \(p\) is the population of the city in thousands. Evaluate each expression in 2012 . a. \(p(t)\) b. \(g(p)\) $$ \text { c. } \frac{d p}{d t} $$ $$ \text { d. } \frac{d g}{d p} \quad \text { e. } \frac{d g}{d t} $$

Short Answer

Expert verified
a. 10.376k people; b. 19.634 trucks; c. 0.03733; d. 1.677; e. 0.0626 trucks/year.

Step by step solution

01

Evaluate Population Function, p(t)

First, identify the value of \( t \) for the year 2012. Since \( t \) is the number of years since 2010, for 2012, \( t = 2 \). Substitute \( t = 2 \) into the population function:\[ p(2) = 130 \left(1 + 12 e^{-0.02 \times 2}\right)^{-1} \]Calculate the expression within the exponent:\(-0.02 \times 2 = -0.04\)This gives:\[ p(2) = 130 \left(1 + 12 e^{-0.04}\right)^{-1} \]Calculate \( e^{-0.04} \approx 0.9608 \), then:\[ p(2) = 130 \left(1 + 12 \times 0.9608\right)^{-1} \]\( 12 \times 0.9608 = 11.5296 \).Thus, \( p(2) = 130 \left(1 + 11.5296\right)^{-1} \)\[ p(2) = 130 \times \, (12.5296)^{-1} \approx 10.376 \]The population in 2012 is approximately 10.376 thousand people.
02

Evaluate Garbage Trucks Function, g(p)

Substitute \( p = 10.376 \) into the garbage trucks function:\[ g(p) = 2p - 0.001p^3 \]Calculate each term:- \( 2 \times 10.376 = 20.752 \)- \( 0.001 \times (10.376)^3 = 0.001 \times 1117.64 \approx 1.1176 \)Then, substitute these values into the expression:\[ g(p) = 20.752 - 1.1176 \approx 19.6344 \]Approximately 19.6344 garbage trucks are needed.
03

Differentiate the Population Function, dp/dt

Differentiate \( p(t) = 130 \left(1 + 12 e^{-0.02t}\right)^{-1} \) with respect to \( t \):Let \( u = 1 + 12 e^{-0.02t} \), then \( p(t) = \frac{130}{u} \).The derivative \( \frac{du}{dt} = -0.24e^{-0.02t} \).Using the chain rule, \( \frac{dp}{dt} = -130 \left(u^{-2}\right) \frac{du}{dt} \).Thus, \[ \frac{dp}{dt} = -130 \frac{-0.24e^{-0.02t}}{(1 + 12 e^{-0.02t})^2} \]Substitute \( t = 2 \) to find \( \frac{dp}{dt} \):\[ \frac{dp}{dt} = 0.24 \times 130 \frac{e^{-0.04}}{(12.5296)^2} \]\( e^{-0.04} \approx 0.9608 \), resulting in:\[ \frac{dp}{dt} \approx 0.024 \times 15.5526 \approx 0.3733 \]\( \frac{dp}{dt} \approx 0.03733 \), evaluated at \( t=2 \).
04

Differentiate Garbage Truck Function, dg/dp

Differentiate \( g(p) = 2p - 0.001p^3 \) with respect to \( p \):\[ \frac{dg}{dp} = 2 - 0.003p^2 \]Substitute \( p = 10.376 \) into the derivative:\[ \frac{dg}{dp} = 2 - 0.003 \times (10.376)^2 \]\( (10.376)^2 = 107.648 \)Calculate:\[ \frac{dg}{dp} = 2 - 0.003 \times 107.648 \approx 1.677 \]Therefore, \( \frac{dg}{dp} \approx 1.677 \).
05

Evaluate the Rate of Change of Garbage Trucks with Respect to Time, dg/dt

From the chain rule:\[ \frac{dg}{dt} = \frac{dg}{dp} \times \frac{dp}{dt} \]Using the values calculated previously:\( \frac{dg}{dp} \approx 1.677 \) and \( \frac{dp}{dt} \approx 0.03733 \).Calculate:\[ \frac{dg}{dt} = 1.677 \times 0.03733 \approx 0.0626 \]Thus, \( \frac{dg}{dt} \approx 0.0626 \) trucks per year in 2012.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Growth Model
In this problem, the population growth of a city is modeled using an exponential function. The function provided is \( p(t) = 130(1 + 12 e^{-0.02 t})^{-1} \), where \( t \) is the number of years since 2010. This model helps us understand how the population changes over time.
Exponential models in population growth are common because they can predict how populations increase or decrease naturally. Population changes often start quickly and then slow down as resources become limited or as birth and death rates stabilize. By examining this function, we can predict the number of people present at any specific time, which is crucial for planning city resources and facilities.
Garbage Truck Requirement Function
The garbage truck requirement function describes the relationship between the population of the city and the number of garbage trucks needed. This function, \( g(p) = 2p - 0.001p^3 \), shows us how the demand for garbage removal equipment scales with population size.
The linear term \( 2p \) indicates that more people naturally require more service—specifically, more garbage trucks. The cubic term \(-0.001p^3\) represents the idea that as the population grows very large, efficiency improvements or shared services may mean fewer trucks are needed per person.
This function aids city planners in ensuring that resources are efficiently allocated, avoiding either a surplus of trucks or a shortage.
Differentiation
Differentiation is a calculus technique used to determine how a function changes at any given point. It is crucial for understanding rates of change.
For the population function \( p(t) \), differentiation allows us to find \( \frac{dp}{dt} \). This tells us how the population's size is changing per year—either increasing or decreasing. Calculating \( \frac{dp}{dt} \) involves the chain rule because the function is composed of layers, such as exponential and algebraic operations.
Similarly, differentiating the garbage truck function \( g(p) \) with respect to \( p \) helps us determine how the need for trucks changes as population grows, calculated as \( \frac{dg}{dp} \).
Understanding differentiation provides clear insight into dynamics and trends, assisting in making informed decisions.
Population Function
The population function \( p(t) \) is the mathematical expression used to represent the population of a city over time. It accounts for factors such as birth rate, death rate, and migration to predict changes.
For this particular function, \( t \) represents the time in years from 2010, and the formula predicts the population’s size in thousands. For instance, in 2012, two years after 2010, \( t = 2 \). By plugging this into the function, we calculate the population at that specific time.
This function serves as a foundational tool for planning—the basis for understanding demographic changes that affect economic, social, and urban development policies.
Chain Rule
The chain rule is a fundamental differentiation technique used when dealing with composite functions—functions within functions. It provides a way to handle complex expressions like our population function \( p(t) \), where variables are nested.
In our scenario, the chain rule is employed to differentiate \( p(t) \) with respect to \( t \). It involves breaking down the function into separate parts, differentiating each, and then combining the results.
To compute \( \frac{dp}{dt} \), we express \( p(t) \) as \( 130(1 + 12 e^{-0.02t})^{-1} \). Here, \( 1 + 12 e^{-0.02t} \) represents one layer, and its derivative is part of calculating the overall rate of change \( \frac{dp}{dt} \). This rule is equally applied when evaluating the rate of change of garbage truck requirements concerning time, emphasizing its versatility and importance in calculus.

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Most popular questions from this chapter

Personal Consumption The amount spent on food by an average American in his or her \(20 \mathrm{~s}\) with \(x\) thousand dollars net income can be modeled as $$ n(x)=-0.35+2.52 \ln x \text { hundred dollars } $$ and the amount spent on housing can be modeled as $$ h(x)=0.58 x-0.84 \text { thousand dollars } $$ (Source: Based on data from the U.S. Bureau of Labor Statistics) a. Use output values corresponding to \(\$ 2,000\) and \(\$ 12,000\) net income to determine an appropriate model for housing expenditure as a function of net income. b. Write a model giving the amount spent on food as a function of the amount spent on housing. c. How much is spent on food by somebody who spends \(\$ 2,500\) on housing? At what rate is this amount changing? Write a sentence of interpretation for the results.

Explain how to write a composite function giving the output of \(f\) as a function of the output of \(g,\) when \(f\) and \(g\) are both one-to-one functions of the same input variable \(x\).

Politics Two candidates are running for mayor in a small town. The campaign committee for candidate A has been conducting weekly telephone polls to assess the progress of the campaign. Currently, there are 17,000 registered voters, \(48 \%\) of whom are planning to vote. Of those planning to vote, \(57 \%\) will vote for candidate \(A\). Candidate \(\mathrm{B}\) has begun some serious mudslinging, which has resulted in increasing public interest in the election and decreasing support for candidate A. Polls show that the percentage of people who plan to vore is increasing by 7 percentage points per week, and the percentage who will vote for candidate \(A\) is declining by 3 percentage points per week. a. If the election were held today, how many people would vore? b. How many of those would vote for candidate \(A\) ? c. How rapidly is the number of votes that candidate \(A\) will receive changing?

Average Profit The profit from the supply of a certain commodity is modeled as $$ P(q)=30+60 \ln q \text { thousand dollars } $$ where \(q\) is the number of million units produced. a. Write an expression for average profit when \(q\) million units are produced. b. What are the profit and the average profit when 10 million units are produced? c. How rapidly are profit and average profit changing when 10 million units are produced? d. Why should managers consider the rate of change of average profit when making production decisions?

When composing functions, why is it important for the output units of the inside function to match the input units of the outside function?

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