/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 For Activities 1 through \(20,\)... [FREE SOLUTION] | 91Ó°ÊÓ

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For Activities 1 through \(20,\) give the derivative formula for each function. \(\quad h(x)=3-7 e^{x}\)

Short Answer

Expert verified
The derivative is \(-7e^x\).

Step by step solution

01

Identify the Components

The given function is \(h(x) = 3 - 7e^x\). It consists of a constant term \(3\) and an exponential term \(-7e^x\).
02

Derive the Constant

The derivative of a constant, \(3\), is \(0\). So, \(\frac{d}{dx}(3) = 0\).
03

Derive the Exponential Function

The derivative of \(-7e^x\) with respect to \(x\) is calculated by applying the derivative of \(ae^x\), which is itself. Therefore, \(\frac{d}{dx}(-7e^x) = -7e^x\).
04

Combine the Derivatives

Combine the derivatives of the constant and the exponential function: \(h'(x) = 0 - 7e^x = -7e^x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Derivative Rules
Derivative rules are fundamental tools in calculus used to find the rate at which a function is changing at any point.
These rules provide a systematic way to calculate derivatives, ensuring consistency and efficiency when working with functions.

Here are some commonly used derivative rules:
  • **Constant Rule**: The derivative of any constant is always zero. For instance, if the function is just a number like 3, its derivative is 0.
  • **Power Rule**: If you have a function like \(x^n\), where \(n\) is any real number, its derivative is \(nx^{n-1}\).
  • **Exponential Rule**: The derivative of an exponential function \(ae^x\) is \(ae^x\). This is because the rate of change of exponential functions is proportional to their current value.
  • **Sum Rule**: The derivative of a sum of functions is the sum of their derivatives, such as \( (f(x) + g(x))' = f'(x) + g'(x) \).
These rules make it easier to decompose complex functions into simpler parts we can easily differentiate.
Understanding and applying these rules allows for efficient problem solving in calculus.
Exploring Exponential Functions
Exponential functions are a class of functions where the variable, typically denoted as \(x\), is an exponent.
This makes them quite unique compared to polynomial functions where the variable is the base.

Characteristics of exponential functions include:
  • **Form**: Generally expressed as \(f(x) = ae^{bx}\), where \(a\) and \(b\) are constants.
  • **Rapid Growth or Decay**: When \(b > 0\), the function grows rapidly as \(x\) increases. Conversely, if \(b < 0\), the function decays towards zero.
  • **Derivative**: As noted in derivative rules, the derivative of \(e^x\) is remarkable in that it remains \(e^x\). Multiplying by a constant creates a simple scaling effect, such as in \(-7e^x\) where its derivative remains \(-7e^x\).
Exponential functions are commonly used in modeling natural processes, financial growth, and decay scenarios due to their inherent properties of doubling or halving within consistent distances.
Steps in Calculus Problem Solving
Calculus problem solving can be boiled down to a structured process that involves clear steps to make complex math more manageable.
Here’s how you can approach solving a problem like finding a derivative:

**Step 1: Understand the Function**
Begin by breaking down the function into its components. Identify constants, variable terms, and specific operations such as exponentials.

**Step 2: Apply Derivative Rules**
  • Use the constant rule for constants, resulting in a derivative of zero.
  • Apply the exponential rule for exponential terms to find their derivatives effectively.
**Step 3: Simplify the Expression**
Once derivative rules are applied, combine the results into a single simplified expression.
For instance, combining the derived parts from \(h(x) = 3 - 7e^x\) yields \(-7e^x\).

**Step 4: Verify and Interpret**
Review the entire process to ensure no mistakes were made. Understand what the derivative tells you about the function’s behavior at any given point.
These steps provide a roadmap for navigating calculus problems, offering a systematic framework that develops critical thinking and analytical skills.

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Most popular questions from this chapter

In Activities 1 through \(30,\) for each of the composite functions, identify an inside function and an outside function and write the derivative with respect to \(x\) of the composite function. $$ f(x)=\frac{37.5}{1+8.9 e^{-1.2 x}} $$

Airline Load Capacity The capacity of commercial large aircraft to generate revenue is measured in ton-miles. The capacity taken up by paying passengers on U.S. carriers can be modeled as $$ g(x)=16.2\left(1.009^{2.18 x+3.41}\right) \text { trillion ton-miles } $$ when a total of \(x\) trillion passenger ton-miles are flown, $$ \text { data from } 20 \leq x \leq 85 . $$ (Source: Based on data from Bureau of Transportation Statistics; applies to large certified aircraft only) a. Write a model for the rate of change of the capacity taken up by paying passengers. b. What are the capacity, the rate of change of capacity, and the percentage rate of change of capacity when 80 trillion passenger ton-miles are flown?

In Activities 1 through \(30,\) for each of the composite functions, identify an inside function and an outside function and write the derivative with respect to \(x\) of the composite function. $$ f(x)=\sqrt{x^{2}-3 x} $$

High School Dropouts (Historic) The table shows the number of students enrolled in the ninth through twelfth grades and the number of dropouts from those same grades in South Carolina for each school year from \(1980-1981\) through \(1989-1990\) $$ \begin{aligned} &\text { South Carolina High School Enrollment and Dropouts }\\\ &\begin{array}{|c|c|c|} \hline \text { School year } & \text { Enrollment } & \text { Dropouts } \\ \hline 1980-81 & 194,072 & 11,651 \\ \hline 1981-82 & 190,372 & 10,599 \\ \hline 1982-83 & 185,248 & 9314 \\ \hline 1983-84 & 182,661 & 9659 \\ \hline 1984-85 & 181,949 & 8605 \\ \hline 1985-86 & 182,787 & 8048 \\ \hline 1986-87 & 185,131 & 7466 \\ \hline 1987-88 & 183,930 & 7740 \\ \hline 1988-89 & 178,094 & 7466 \\ \hline 1989-90 & 172,372 & 5768 \\ \hline \end{array} \end{aligned} $$ a. Find cubic models for enrollment and the number of dropouts. Align both models to the number of years since \(1980-81\) b. Use the two models found in part \(a\) to construct an equation for the percentage of high school students who dropped out each year. c. Find the rate-of-change formula of the percentage of high school students who dropped out each year. d. Look at the rate of change for each school year from \(1980-81\) through \(1989-90 .\) In which school year was the rate of change smallest? When was it greatest?

For Activities 11 through 28 a. write the product function. b. write the rate-of-change function.] $$ g(x)=3 x^{-0.7} ; h(x)=5^{x} $$

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