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Use the limit definition of the derivative (algebraic method) to confirm the statements. The derivative of \(f(x)=-3 x^{2}-5 x\) is \(f^{\prime}(x)=-6 x-5\).

Short Answer

Expert verified
The derivative \(f'(x) = -6x - 5\) is correct.

Step by step solution

01

Recall the Limit Definition of a Derivative

The limit definition of a derivative of a function \(f(x)\) is given by \[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \]. This formula will be used to verify the given derivative of the function \(f(x) = -3x^2 - 5x\).
02

Find the Expression for \(f(x + h)\)

Substitute \(x + h\) into the function \(f(x) = -3x^2 - 5x\) to get \[ f(x + h) = -3(x + h)^2 - 5(x + h) \].Expanding \( (x + h)^2 \) gives \( x^2 + 2xh + h^2 \).So, \[ f(x + h) = -3(x^2 + 2xh + h^2) - 5x - 5h \].
03

Simplify \(f(x + h)\)

Distribute the coefficients:\[-3(x^2 + 2xh + h^2) = -3x^2 - 6xh - 3h^2\]Thus, \[ f(x + h) = -3x^2 - 6xh - 3h^2 - 5x - 5h \].
04

Calculate \(f(x + h) - f(x)\)

Substitute \(f(x) = -3x^2 - 5x\) and the expression for \(f(x + h)\):\[ f(x + h) - f(x) = (-3x^2 - 6xh - 3h^2 - 5x - 5h) - (-3x^2 - 5x) \].Simplifying this gives:\[ -6xh - 3h^2 - 5h \].
05

Divide by \(h\) and Simplify

Using the result from Step 4, divide by \(h\):\[ \frac{-6xh - 3h^2 - 5h}{h} = -6x - 3h - 5 \].
06

Apply the Limit as \(h \to 0\)

Finally, apply the limit:\[ f'(x) = \lim_{h \to 0} (-6x - 3h - 5) = -6x - 5 \].As \(h\) approaches 0, the term \(-3h\) vanishes, confirming the derivative as \(-6x - 5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
The derivative of a function is a fundamental concept in calculus that describes how a function changes as its input changes. It essentially gives the rate of change or the slope of the function at any given point. Derivatives allow us to measure how sensitive a function is to changes in its input values. For any function, we denote the derivative with a prime symbol like this: if the function is \( f(x) \), then its derivative is \( f'(x) \).
To find the derivative of a function, we can use the limit definition of a derivative. This technique involves taking the limit of the difference quotient \( \frac{f(x+h) - f(x)}{h} \) as \( h \) approaches zero. By applying this definition, we evaluate how the function behaves infinitesimally close to a given point, comprehensively understanding its rate of change. Derivatives have a wide array of applications, from calculating velocity in physics to finding maxima and minima in optimization problems.
Polynomial Functions
Polynomial functions are expressions made up of variables, coefficients, and non-negative integer exponents. A typical polynomial would take the form \( ax^n + bx^{n-1} + cx^{n-2} + \, ... \, + d \), where \( a, b, c, \) and \( d \) are coefficients. These functions are widely used in algebra and calculus for modeling natural phenomena, economics, and many other fields.
The polynomial function in the given exercise is \( f(x) = -3x^2 - 5x \). Each term of this polynomial contains a variable raised to a power, with corresponding coefficients. The highest power of the variable in this expression determines the degree of the polynomial, which in this case is 2, making it a quadratic polynomial. Polynomial functions are continuous and differentiable across their domains, making it easy to calculate their derivatives using basic calculus tools. Understanding polynomial functions is crucial as they serve as building blocks for more complex functions and can often be simplified and solved using algebraic techniques.
Limit Calculation
Limits are a fundamental tool in calculus, used to define derivatives and integrals. In simple terms, a limit helps us understand the behavior of a function as its input approaches a certain value. The concept of a limit expresses how a function's output can get arbitrarily close to a particular value by getting sufficiently close to some input value. This is formally written as \( \lim_{x \to a}f(x) = L \), meaning as \( x \) approaches \( a \), \( f(x) \) approaches \( L \).
In the context of derivatives, the limit definition comes into play quite directly. It allows us to rigorously find the derivative by considering the function's behavior as the change in \( x \)—denoted as \( h \)—approaches zero. For this exercise, calculating the derivative of the polynomial \( f(x) = -3x^2 - 5x \) involves applying the limit to our expression \( \frac{f(x+h) - f(x)}{h} \) and letting \( h \) tend towards zero. This iterative limit process ensures that the derivative found is the precise, instantaneous rate of change at any point.
Calculus
Calculus is the branch of mathematics that deals with finding properties of derivatives and integrals of functions. Its two main branches are differentiation and integration. Differentiation focuses on how functions change, which involves calculating derivatives. Integration, on the other hand, is about finding areas under curves, essentially summing up tiny bits to understand the whole.
Derivatives are central in calculus because they give us the first glance into the behavior of functions with respect to change. They help us in understanding how functions increase or decrease, assist in finding tangent lines, and tackle problems involving motion and growth. Calculus is essential not only in theoretical mathematics, but also in practical applications across science and engineering.
In this exercise, we dive into the derivative using the limit definition, a key tool in calculus. By applying this process to a polynomial function, we unravel the changes step-by-step, unveiling the precise derivative. This illustrates how calculus concepts might initially seem abstract, yet they provide extremely powerful techniques for analyzing real-world situations.

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Most popular questions from this chapter

Fuel Efficiency The function \(g\) gives the fuel efficiency, in miles per gallon, of a car traveling \(v\) miles per hour. Write a sentence of interpretation for each of the following statements. a. \(g(55)=32.5\) and \(g^{\prime}(55)=-0.25\) b. \(g^{\prime}(45)=0.15\) and \(g^{\prime}(51)=0\) c. Sketch a possible graph of \(g\).

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