/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Scuba Diving The maximum no-comp... [FREE SOLUTION] | 91Ó°ÊÓ

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Scuba Diving The maximum no-compression dive times for open-water scuba diving with air-filled tanks can be modeled as $$ t(x)=286.93\left(0.9738^{x}\right) \text { minutes } $$ of dive time where \(x\) feet is the depth of the dive, \(50 \leq x \leq 120\) (Source: Based on data available at www.divetechhouston.com/ RESOURCE FILES/nitrox_info_sheet.pdf) a. What is the maximum length of time for a dive at a depth of 75 feet? 95 feet? b. What is the maximum depth possible in a dive of 20 minutes?

Short Answer

Expert verified
75 feet: ~15.18 minutes; 95 feet: ~5.08 minutes; max depth for 20 min: ~73 feet.

Step by step solution

01

Evaluate Dive Time for 75 Feet

Use the function \( t(x) = 286.93 \times (0.9738)^{x} \) to find the maximum dive time at 75 feet. Substitute \( x = 75 \):\[t(75) = 286.93 \times (0.9738)^{75}\]Calculate:\[t(75) = 286.93 \times 0.0529 \approx 15.18 \text{ minutes}\]
02

Evaluate Dive Time for 95 Feet

Again, use the function \( t(x) = 286.93 \times (0.9738)^{x} \) to determine the dive time at 95 feet. Substitute \( x = 95 \):\[t(95) = 286.93 \times (0.9738)^{95}\]Calculate:\[t(95) = 286.93 \times 0.0177 \approx 5.08 \text{ minutes}\]
03

Solve for Maximum Depth in 20 Minutes

To find the maximum depth \( x \) for a dive time of 20 minutes, set the function equal to 20 and solve for \( x \):\[20 = 286.93 \times (0.9738)^{x}\]First, isolate \( (0.9738)^{x} \):\[(0.9738)^{x} = \frac{20}{286.93} \approx 0.0697\]Take the natural logarithm of both sides to solve for \( x \):\[\ln((0.9738)^{x}) = \ln(0.0697)\]\[x \cdot \ln(0.9738) = \ln(0.0697)\]\[x = \frac{\ln(0.0697)}{\ln(0.9738)} \approx 72.54\]Thus, the maximum depth for a 20-minute dive is approximately 73 feet.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are fascinating mathematical expressions used to model a variety of real-world situations, like the one found in the scuba diving exercise. In these functions, a constant base is raised to a variable exponent, forming an expression like this: \( a \, (b)^{x} \). Here, \( a \) represents a scaling factor, \( b \) is the base, and \( x \) is the variable exponent.

In our scuba diving example, the function \( t(x) = 286.93 \times (0.9738)^{x} \) models the no-compression dive time. This means that as the depth \( x \) increases, the maximum dive time decreases. This is because the base (\( 0.9738 \)) is between 0 and 1. Such characteristics make exponential functions powerful in modeling decay processes like radioactive decay, population dynamics, or cooling temperatures.

Key properties of exponential functions include:
  • Rapid change over small domains – they can grow or decay quickly.
  • Constant percentage change – makes them suitable for financial and biological growth models.
  • Sensitivity to initial conditions – small differences can lead to vastly different outcomes over time.
Problem Solving
Problem solving involving exponential functions typically requires a systematic approach. This involves understanding what the function represents, performing substitutions to evaluate the function, and sometimes algebraic manipulations to solve for unknowns.

To tackle the scuba diving challenge, begin by substituting different depths into the given function to find the dive times, as shown in the exercise's Step 1 and Step 2. Use of a calculator to handle the exponent computation ensures precision, particularly for these types of calculations.

When asked to find the maximum allowable depth for a specified dive time (as in Step 3), algebraic manipulation is needed. Here, isolating the exponential part by dividing both sides by the coefficient, and then using logarithms to solve for the exponent, is crucial. Logarithms are inverse operations to exponentials, making them perfect tools for unraveling exponential equations.

Some tips for solving exponential equations include:
  • Check units and make sure input values match the model requirements.
  • Use logarithms to convert exponential forms to linear, simplifying the solving process.
  • Double-check calculations at each step to avoid small, cumulative errors that can affect the result.
Real-world Applications
Exponential functions extend far beyond mathematical exercises, playing a crucial role in various real-world scenarios. Their application ranges from natural sciences and engineering to finance and technology.

In scuba diving, exponential models estimate safe dive durations by considering how pressure at different depths affects gas absorption. Such models help divers avoid complications like decompression sickness, ensuring safety.

Other examples of exponential functions in everyday life include:
  • Population Growth: Populations can grow rapidly in environments with abundant resources, often modeled with exponential functions.
  • Compound Interest: Financial investments use exponential growth formulas to calculate the future value of deposits and loans.
  • Radioactive Decay: The rate at which radioactive elements decay follows an exponential trend, vital for carbon dating and medical treatments.
Understanding exponential functions allows us to predict and control these processes, making informed decisions, and contributing to advancements in science and technology. Their pervasiveness and versatility make them indispensable in both theory and practice.

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