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Algebraically determine the limits. $$ \begin{array}{l} \lim _{x \rightarrow 0.1} \frac{f(x)}{g(x)} \text { when } \\ \qquad \lim _{x \rightarrow 0.1} f(x)=6 \text { and } \lim _{x \rightarrow 0.1} g(x)=3 \end{array} $$

Short Answer

Expert verified
The limit is 2.

Step by step solution

01

Understand the Limit Notation

The limit notation \( \lim_{x \rightarrow 0.1} \frac{f(x)}{g(x)} \) asks us to find the value that \( \frac{f(x)}{g(x)} \) approaches as \( x \) gets very close to 0.1. We are given that \( \lim_{x \rightarrow 0.1} f(x) = 6 \) and \( \lim_{x \rightarrow 0.1} g(x) = 3 \).
02

Apply Limit Laws

Using limit laws, particularly the law that states \( \lim_{x \rightarrow c} \frac{f(x)}{g(x)} = \frac{\lim_{x \rightarrow c} f(x)}{\lim_{x \rightarrow c} g(x)} \) provided that \( \lim_{x \rightarrow c} g(x) eq 0 \), we can simplify our problem. In this case, since \( \lim_{x \rightarrow 0.1} f(x) = 6 \) and \( \lim_{x \rightarrow 0.1} g(x) = 3 \), we can write:
03

Perform the Calculation

Plug the known limits into the formula: \[ \lim_{x \rightarrow 0.1} \frac{f(x)}{g(x)} = \frac{\lim_{x \rightarrow 0.1} f(x)}{\lim_{x \rightarrow 0.1} g(x)} = \frac{6}{3} \] Simplifying \( \frac{6}{3} \) gives us 2.
04

Conclusion

Now, we conclude that the value \( \frac{f(x)}{g(x)} \) approaches as \( x \) approaches 0.1 is 2, since both \( f(x) \) and \( g(x) \) have defined limits at \( x = 0.1 \) and \( g(x) \) is not approaching zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit laws
Limit laws are fundamental rules in calculus that guide how to evaluate limits effectively. They simplify complex limit problems and allow us to solve them step-by-step. One crucial law is the Quotient Law, which is used when dealing with ratios of two functions. This law states that:
  • If \( \lim_{x \to c} f(x) = L \) and \( \lim_{x \to c} g(x) = M \), then \( \lim_{x \to c} \frac{f(x)}{g(x)} = \frac{L}{M} \) provided \( M eq 0 \).
This rule allows us to calculate the limit of a fraction by evaluating the limits of the numerator and the denominator separately. The key condition here is that the limit of the denominator \( g(x) \) must not be zero, otherwise, the quotient would be undefined. By using limit laws, we streamline the process of limit evaluation, which is essential for tackling more advanced calculus problems.
Fraction limits
Fraction limits occur frequently in calculus, and understanding how to evaluate them is crucial for mastering the subject. In the problem we're considering, we have a fraction \( \frac{f(x)}{g(x)} \), and we need to find its limit as \( x \) approaches a specific value.

To evaluate these limits, we apply the Quotient Law from the limit laws. It's important to note that:
  • The limit of the numerator \( f(x) \) should lead to a finite value.
  • The limit of the denominator \( g(x) \) should be non-zero to avoid division by zero.
In our example, since \( \lim_{x \to 0.1} f(x) = 6 \) and \( \lim_{x \to 0.1} g(x) = 3 \), we can straightforwardly compute the limit of the fraction as \( \frac{6}{3} = 2 \). This confirms that doing fraction limits often boils down to applying the correct limit laws and ensuring each part of the fraction has defined and acceptable limits.
Algebraic manipulation
Sometimes, before applying limit laws to find the limit, algebraic manipulation is necessary. This involves rearranging or simplifying expressions to make limit calculation easier. However, in our particular problem, since we already have specific limit values, no complex manipulation is needed.

In more complex scenarios, you might need to:
  • Factor expressions to cancel out terms causing indeterminate forms like \( \frac{0}{0} \).
  • Use conjugates to rationalize components of a fraction.
  • Expand polynomials or perform long division, especially in polynomial fractions.
These techniques help reveal a clearer path to applying limit laws. While our example did not require extensive algebraic manipulation, knowing these methods becomes essential in different or more complicated limit problems, where direct substitution or simple calculations are not enough to determine a limit correctly.

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