Chapter 8: Problem 23
Show that \(f(x, y)=x^{3} y^{3}\) has a saddle point at (0,0) and that \(\Delta(0,0)=0 .\)
Short Answer
Expert verified
The function has a saddle point at \((0,0)\), with \(\Delta(0,0) = 0\).
Step by step solution
01
Find the First Partial Derivatives
Calculate the partial derivatives of the function to find the critical points. For \( f(x, y) = x^3 y^3 \), the first partial derivatives are:\[ \frac{\partial f}{\partial x} = 3x^2 y^3 \]\[ \frac{\partial f}{\partial y} = 3x^3 y^2 \]
02
Solve for Critical Points
Set the first partial derivatives to zero to find the critical points:\[ 3x^2 y^3 = 0 \] \[ 3x^3 y^2 = 0 \] Solving these equations gives \( x = 0 \) and \( y = 0 \). Thus, the critical point is \( (0, 0) \).
03
Compute the Second Partial Derivatives
Find the second partial derivatives to use in the second derivative test:\[ \frac{\partial^2 f}{\partial x^2} = 6xy^3 \] \[ \frac{\partial^2 f}{\partial y^2} = 6x^3y \] \[ \frac{\partial^2 f}{\partial x \partial y} = 9x^2y^2 \]
04
Evaluate Second Derivatives at Critical Point
Evaluate the second partial derivatives at \( (0,0) \):\[ \frac{\partial^2 f}{\partial x^2} (0,0) = 0 \] \[ \frac{\partial^2 f}{\partial y^2} (0,0) = 0 \] \[ \frac{\partial^2 f}{\partial x \partial y} (0,0) = 0 \]
05
Calculate the Hessian Determinant
The Hessian determinant \( \Delta (x, y) \) is given by:\[ \Delta(x, y) = \frac{\partial^2 f}{\partial x^2} \frac{\partial^2 f}{\partial y^2} - \left( \frac{\partial^2 f}{\partial x \partial y} \right)^2 \] Thus, at \( (0,0) \):\[ \Delta(0,0) = (0)(0) - (0)^2 = 0 \]
06
Interpret Result Using Theorem
Since the Hessian determinant \( \Delta(0,0) = 0 \), the second derivative test is inconclusive at \( (0, 0) \). However, examining the nature of the function shows mixed signs near \( (0,0) \), indicating a saddle point.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hessian Determinant
The Hessian determinant is a crucial concept in multivariable calculus, particularly when analyzing critical points of functions with more than one variable. It is a determinant of a matrix called the Hessian matrix, which consists of the second partial derivatives of a function. This matrix gives insight into the curvature of the function at a given point.
More specifically:
The Hessian determinant at a point \((x_0, y_0)\) is then:\[\Delta(x_0, y_0) = \frac{\partial^2 f}{\partial x^2} \frac{\partial^2 f}{\partial y^2} - \left( \frac{\partial^2 f}{\partial x \partial y} \right)^2\]
The determinant helps determine the nature of a critical point:
More specifically:
- For a function of two variables, such as \( f(x, y) \), the Hessian matrix is a 2x2 matrix, given by:
The Hessian determinant at a point \((x_0, y_0)\) is then:\[\Delta(x_0, y_0) = \frac{\partial^2 f}{\partial x^2} \frac{\partial^2 f}{\partial y^2} - \left( \frac{\partial^2 f}{\partial x \partial y} \right)^2\]
The determinant helps determine the nature of a critical point:
- If \( \Delta > 0 \), and \( \frac{\partial^2 f}{\partial x^2} > 0 \), the point is a local minimum.
- If \( \Delta > 0 \), and \( \frac{\partial^2 f}{\partial x^2} < 0 \), the point is a local maximum.
- If \( \Delta < 0 \), the point is a saddle point, indicating a change in concavity.
- If \( \Delta = 0 \), the test is inconclusive, and further analysis is required.
Partial Derivatives
Partial derivatives are foundational in studying functions of multiple variables. They represent the rate of change of a function in relation to one of the variables, while keeping others constant.
For a function \( f(x, y) \):
A higher-order partial derivative is simply a derivative of a partial derivative. In the context of analyzing critical points:
For a function \( f(x, y) \):
- The partial derivative with respect to \( x \), \( \frac{\partial f}{\partial x} \), measures how the function changes as \( x \) changes, keeping \( y \) constant.
- The partial derivative with respect to \( y \), \( \frac{\partial f}{\partial y} \), measures the change of the function as \( y \) varies, with \( x \) held fixed.
A higher-order partial derivative is simply a derivative of a partial derivative. In the context of analyzing critical points:
- The first-order partial derivatives are set to zero to find critical points.
- The second-order partial derivatives are used to decipher the nature of these critical points using Hessian Determinant analysis.
Critical Points
Critical points are specific locations in the domain of a function where the first partial derivatives equal zero. These points are essential as they potentially indicate local maxima, minima, or saddle points.
To find critical points for \( f(x, y) = x^3 y^3 \):
Once identified, the nature of the critical point must be determined. This is often done using the second derivative test, which involves:
To find critical points for \( f(x, y) = x^3 y^3 \):
- Calculate the first-order partial derivatives \( \frac{\partial f}{\partial x} = 3x^2 y^3 \) and \( \frac{\partial f}{\partial y} = 3x^3 y^2 \).
- Set each derivative to zero and solve for \( x \) and \( y \).
- In this function, \( x = 0 \) and \( y = 0 \) satisfy both conditions. Thus, a critical point is found at \((0,0)\).
Once identified, the nature of the critical point must be determined. This is often done using the second derivative test, which involves:
- Calculating the Hessian determinant to infer local behavior around the point.
- Analyzing the results in context—in this case, \( \Delta(0,0) = 0 \), indicating a saddle point by further functional investigation.