/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Find the limits. $$ \lim _{x... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the limits. $$ \lim _{x \rightarrow-\infty}\left(x^{2}+1\right) $$

Short Answer

Expert verified
The limit is \( \infty \).

Step by step solution

01

Understanding the Problem

We are required to find the limit of the function \( x^2 + 1 \) as \( x \) approaches \(-\infty\). This means we need to understand how the function behaves when \( x \) gets very large in the negative direction.
02

Analyze the Function's Components

The function given is \( x^2 + 1 \). When \( x \) is a large negative number, \( x^2 \) will become a large positive number, since squaring a negative number results in a positive number.
03

Simplify the Limit Expression

As \( x \) approaches \(-\infty\), the dominant term in the expression \( x^2 + 1 \) is \( x^2 \), since \( x^2 \) grows at a much faster rate than the constant 1. Thus, \( x^2 + 1 \) will also grow very large without bound.
04

Evaluate the Limit

Since \( x^2 \rightarrow \, \infty \) as \( x \rightarrow -\infty \), it follows that \( x^2 + 1 \rightarrow \, \infty \) as well. Therefore, the limit of \( x^2 + 1 \) as \( x \) approaches \(-\infty\) is \( \infty \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Limits
Infinite limits occur when a function grows without bound as the input approaches certain values or infinity. In this situation, we're looking at how the function \( x^2 + 1 \) behaves as \( x \) approaches \(-\infty\). Essentially, an infinite limit helps us analyze what happens to a function when \( x \) becomes extremely large or small, in our case, very large in a negative sense.

In the given exercise, as \( x \rightarrow -\infty \), we see that \( x^2 + 1 \) tends toward infinity. This is because no matter how large the negative \( x \) is, squaring it results in a positive value that's very large, and adding 1 only slightly increases an already huge number. Infinite limits are crucial in calculus because they help us understand functions' end behavior and predict their tendencies at extreme values.
Function Behavior
Understanding a function's behavior is about observing how it acts across its domain, especially as the input reaches extreme values or approaches critical points. In the exercise, the behavior of the function \( x^2 + 1 \) is assessed as \( x \rightarrow -\infty \). As part of understanding function behavior, you should look at:

  • Dominant terms: Identify which component of the function grows fastest. For \( x^2 + 1 \), \( x^2 \) clearly dominates because it exponentially increases as \( x \) gets large, while 1 remains constant.
  • Growth rate: Since \( x^2 \) grows rapidly, \( x^2 + 1 \) will take on very large values.
  • Tendencies: When the most significant part of the expression tends towards infinity, added constants become insignificant.
By understanding these aspects, we see why \( x^2 + 1 \) has an infinite limit as \( x \rightarrow -\infty \). The function's primary term dictates how the entire function behaves in extremes.
Squaring Negative Numbers
Squaring negative numbers is a fundamental concept that emerges in various calculus applications. If \( x \) is negative, \( x^2 \) will always produce a positive value. Here's why:

  • Multiplication of two negative numbers results in a positive number, because negative times negative equals positive.
  • This rule applies universally, so \( x^2 \) is positive regardless of whether \( x \) is positive or negative.
  • In terms of magnitude, \( x^2 \) captures both positive and negative \( x \) values, turning them to the same positive reflection.
Understanding this concept can help with determining limits because it shows that as \( x \rightarrow -\infty \), squaring \( x \) will continue to provide large positive values, influencing the overall limit of the expression positively towards infinity. This principle of squaring provides clarity when dealing with polynomial functions like \( x^2 + 1 \).

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