/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Find \(f^{\prime \prime}(x)\). ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(f^{\prime \prime}(x)\). $$ f(x)=1 /(x+1) $$

Short Answer

Expert verified
The second derivative is \(f''(x) = \frac{2}{(x+1)^3}\).

Step by step solution

01

Identify the Function and Apply the First Derivative

The given function is \(f(x) = \frac{1}{x+1}\). Recognize that this is a rational function. To find the derivative, apply the power rule and rewrite the function as \(f(x) = (x+1)^{-1}\). Then, apply the power rule for derivatives: if \(f(x) = x^n\), then \(f'(x) = n \cdot x^{n-1}\).
02

Calculate the First Derivative

Now apply the derivative rule: \(f'(x) = -1 \cdot (x+1)^{-2}\). Simplifying this expression, we get \(f'(x) = -\frac{1}{(x+1)^2}\). This is the first derivative of the function.
03

Differentiate Again to Find the Second Derivative

From the first derivative \(f'(x) = -\frac{1}{(x+1)^2}\), apply the quotient rule for derivatives, which is \(\left(\frac{g(x)}{h(x)}\right)' = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\). Here, \(g(x) = -1\) and \(h(x) = (x+1)^2\).
04

Apply the Quotient Rule

Calculate \(g'(x) = 0\) and \(h'(x) = 2(x+1)\) using the chain rule. Substitute in the quotient rule: \(f''(x) = \frac{0 \cdot (x+1)^2 - (-1) \cdot 2(x+1)}{((x+1)^2)^2}\).
05

Simplify the Expression

This simplifies to \(f''(x) = \frac{2(x+1)}{(x+1)^4}\) or, more simply, \(f''(x) = \frac{2}{(x+1)^3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
In calculus, the concept of a derivative represents the instantaneous rate of change of a function. You can think of it as how a function's output changes as its input changes, which is analogous to finding the slope of the tangent line to the graph of the function at a particular point. In more practical terms:
  • The derivative tells us how fast a quantity is changing at any point in time.
  • It is denoted by \( f'(x) \) or \( \frac{df}{dx} \) if \( f(x) \) is the function.
  • For a simple power function, such as \( f(x) = x^n \), the derivative is obtained using the power rule: \( f'(x) = n \cdot x^{n-1} \).
To get the first derivative of the function \( f(x) = \frac{1}{x+1} \), it helps to rewrite it as \( (x+1)^{-1} \). Applying the power rule, the derivative becomes \( -1 \cdot (x+1)^{-2} \), which simplifies to \( -\frac{1}{(x+1)^2} \). This tells us how the function behaves as \( x \) changes.
Second Derivative
The second derivative of a function is the derivative of its first derivative. It provides information on the concavity of the function, telling us whether the graph of the function is curving upwards or downwards at any given point. For practical understanding:
  • If the second derivative is positive, the function is concave up (forming a 'U' shape).
  • If the second derivative is negative, the function is concave down (forming an 'n' shape).
  • If the second derivative is zero, it could indicate an inflection point where the concavity changes.
For the function \( f(x) = \frac{1}{x+1} \), using its first derivative \( f'(x) = -\frac{1}{(x+1)^2} \), the second derivative \( f''(x) \) gives further insights into the nature of the curve. To find it, additional techniques like the quotient rule might be necessary since the first derivative is itself a fraction.
Quotient Rule
The quotient rule is a technique for differentiating functions that are divided by each other. It is especially useful when dealing with rational functions or fractions.If you have two functions, \( g(x) \) and \( h(x) \), and you need to find the derivative of their quotient, \( \frac{g(x)}{h(x)} \), you use:\[\left(\frac{g(x)}{h(x)}\right)' = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\]Steps to apply the quotient rule:
  • Differentiate the numerator, \( g(x) \), to obtain \( g'(x) \).
  • Differentiate the denominator, \( h(x) \), to find \( h'(x) \).
  • Substitute into the quotient rule formula.
  • Simplify the resulting expression as needed.
In our example with \( f(x) = \frac{1}{x+1} \), and its first derivative \( f'(x) = -\frac{1}{(x+1)^2} \), the quotient rule helps find the second derivative. By differentiating \( g(x) = -1 \) and \( h(x) = (x+1)^2 \), we derive \( f''(x) = \frac{2}{(x+1)^3} \), showing how quickly the slope of the tangent lines is changing, giving us deeper insights into the shape of the curve.

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Most popular questions from this chapter

Biology Webb and colleagues \(^{24}\) created a mathematical model that showed that the population \(y\) of gypsy moths was approximated by \(y=f(x)=10^{3.8811-0.1798 \sqrt{x}},\) where \(x\) was the dose in grams per hectare of the insecticide racemic disparlure. Find \(f^{\prime}(x),\) and determine whether this function is decreasing. Sketch a graph. What happens if the dose \(x\) becomes very large?

Biology The formula \(w=w_{0} N^{-a}\) is a mathematical model used by plant biologists (see Shainsky and Radosevich \(^{23}\) ), where \(w\) is the plant size, \(w_{0}\) is the maximum plant size in absence of competitors, \(N\) is plant density, and \(a\) is a positive constant. According to this formula, for what values of \(N\) is plant size decreasing? Sketch a possible graph.

Assume that \(f^{\prime}(x)\) is continuous everywhere and that \(f(x)\) has one and only one critical value at \(x=0\). Use the additional given information to determine whether \(y=f(x)\) attains a relative minimum, a relative maximum, or neither at \(x=0 .\) Explain your reasoning. Sketch a possible graph in each case. \(f(0)=1, f(5)=5,\) and \(f(-5)=0\)

Cost Function Dean \(^{10}\) found that the cost function for direct materials in a furniture factory was approximated by \(y=C(x)=0.667 x-0.00467 x^{2}+0.000151 x^{3}\) for \(0 \leq\) \(x \leq 50,\) where \(x\) is output in thousands of dollars. Use calculus to find where marginal cost is maximized.

Assume that \(f^{\prime}(x)\) is continuous everywhere and that \(f(x)\) has one and only one critical value at \(x=0\). Use the additional given information to determine whether \(y=f(x)\) attains a relative minimum, a relative maximum, or neither at \(x=0 .\) Explain your reasoning. Sketch a possible graph in each case. \(f(-1)=3, f(0)=10, f(2)=4\)

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