/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Find \(\frac{d y}{d x}\) $$ ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(\frac{d y}{d x}\) $$ y=3 x^{-3 / 5}-6 x^{-5 / 2} $$

Short Answer

Expert verified
\( \frac{dy}{dx} = -\frac{9}{5}x^{-8/5} + \frac{15}{2}x^{-7/2} \)

Step by step solution

01

Understand the Derivative Notation

You need to find \( \frac{dy}{dx} \) for the function \( y = 3x^{-3/5} - 6x^{-5/2} \). This means you have to differentiate \( y \) with respect to \( x \).
02

Differentiate Each Term Separately

Find the derivative of each term of \( y \):- For \( 3x^{-3/5} \), use the power rule \( \frac{d}{dx}[x^n] = nx^{n-1} \).- For \( -6x^{-5/2} \), use the same power rule.
03

Apply the Power Rule to the First Term

Differentiate \( 3x^{-3/5} \):The power rule states \( \frac{d}{dx}[x^n] = nx^{n-1} \). Thus, \( \frac{d}{dx}[3x^{-3/5}] = 3(-3/5)x^{-3/5 - 1} = -9/5x^{-8/5} \).
04

Apply the Power Rule to the Second Term

Differentiate \( -6x^{-5/2} \):Using the power rule, \( \frac{d}{dx}[-6x^{-5/2}] = -6(-5/2)x^{-5/2 - 1} = 15/2 x^{-7/2} \).
05

Combine the Derivatives

Combine the results from Steps 3 and 4:\( \frac{dy}{dx} = -\frac{9}{5}x^{-8/5} + \frac{15}{2}x^{-7/2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Power Rule: A Key Tool in Calculus
The power rule is a fundamental principle in calculus used for finding the derivative of functions involving powers of variables. It provides a straightforward method to differentiate terms of the form \(x^n\). Understanding this rule simplifies many differentiation tasks.

Here's how the power rule works: take a function \(x^n\). The power rule states that the derivative of this function is \(nx^{n-1}\). In other words, multiply the exponent \(n\) by the coefficient, and then subtract one from the exponent.

This rule is particularly useful because it's quick and easy to apply:
  • Identify the exponent \(n\) of your term.
  • Multiply this exponent by the coefficient in front of \(x\).
  • Reduce the exponent by 1.
This simplicity is what makes the power rule an essential tool for differentiating polynomial functions and more complex expressions alike.
Understanding Differentiation
Differentiation is the process of finding the derivative of a function, and it lies at the heart of calculus. A derivative represents the rate of change of a function with respect to a variable. So, when you differentiate a function, you're essentially calculating how fast it's changing at any point.

The process itself involves several techniques, with the power rule being one of the most common. Differentiation can be applied to polynomials, trigonometric functions, exponential functions, and more, each with its own set of rules. Here are some key aspects to keep in mind:
  • The derivative provides insights into the behavior of a function, such as increasing or decreasing trends, and can even help locate local maxima and minima.
  • The notation \( \frac{d}{dx} \) is used to denote the derivative of a function. In the context of our example, \( \frac{dy}{dx} \) tells us we're finding the derivative of \(y\) with respect to \(x\).
  • Being systematic in your method, like breaking down the terms and applying rules to each, helps in obtaining the correct derivative.
By understanding and mastering differentiation, you gain a powerful insight into the dynamics of changing quantities.
Exploring the World of Calculus
Calculus is a major branch of mathematics that deals with change and motion. It provides tools to analyze and model dynamics in a myriad of fields, from physics to economics. The two main branches of calculus are differentiation and integration.

In essence, calculus reveals patterns and trends by considering the limits and behavior of functions. Here's how it connects to real-world problems:
  • Differentiation allows you to determine instantaneous rates of change, like velocity in physics.
  • Integration, conversely, is about finding the total accumulation of a quantity, such as area under a curve.
  • The concepts in calculus build upon the fundamental concepts of limits and continuity, which establish how functions behave as they approach specific points.
Understanding calculus gives you the ability to tackle complex problems involving changing systems. It equips you with the analytical tools needed to break down intricate scenarios in science and engineering, making it an indispensable asset in today's technologically driven world.

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