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Biology Chan et al. \({ }^{42}\) showed that the pupal weight \(y\) in milligrams of the Mediterranean fruit fly was approximated by \(y=5.5 \sqrt{\ln x},\) where \(x\) is the percent protein level in the diet. Find the rate of change of weight with respect to change in percent protein level.

Short Answer

Expert verified
The rate of change is \(\frac{5.5}{2x \sqrt{\ln x}}\).

Step by step solution

01

Understand the Given Function

The weight of the fruit fly, denoted as \(y\), is given by the function \(y = 5.5 \sqrt{\ln x}\). Here, \(x\) represents the percent protein level in the diet. We need to find the rate of change of \(y\) with respect to \(x\), which requires differentiation.
02

Differentiate the Function

To find the rate of change, we need the derivative of \(y\) with respect to \(x\). Start by rewriting \(y\) as \(5.5 (\ln x)^{1/2}\). The chain rule is used here: \(\frac{dy}{dx} = 5.5 \times \frac{1}{2} (\ln x)^{-1/2} \times \frac{d}{dx}(\ln x)\).
03

Apply the Chain Rule

The derivative of \(\ln x\) is \(\frac{1}{x}\). Substituting, we find \(\frac{dy}{dx} = 5.5 \times \frac{1}{2} (\ln x)^{-1/2} \times \frac{1}{x}\).
04

Simplify the Expression

Simplify the derivative: \(\frac{dy}{dx} = \frac{5.5}{2x \sqrt{\ln x}}\). This expression represents the rate of change of the weight \(y\) with respect to the protein level \(x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation and Its Role in Calculus
Differentiation is a fundamental concept in calculus that involves finding the rate at which a function changes at any given point. This concept is essential in many fields such as physics, engineering, and, in this case, biology. When differentiating a function, we aim to determine its derivative, which represents the slope of the tangent line to the curve at any specific point. For instance, in the exercise provided, we needed to differentiate the function \(y = 5.5 \sqrt{\ln x}\) in order to find how the weight of a Mediterranean fruit fly changes with varying protein levels in its diet. Differentiation is a tool that allows us to analyze how small changes in input \(x\) (percent protein level) affect the output \(y\) (pupal weight). It's particularly useful in mathematical modeling and simulating real-world situations.
Understanding the Chain Rule
The chain rule is a powerful technique in differentiation, particularly when dealing with composite functions. A composite function is a function that is formed by combining two or more functions, such as \(y = 5.5 (\ln x)^{1/2}\) in our exercise. Here, the chain rule helps us to find the derivative of the outer function with respect to the inner function and then multiply it by the derivative of the inner function with respect to its variable. In simpler terms, it allows us to "chain" together derivatives to handle nested or complex functions. For the given exercise, we started with \((\ln x)^{1/2}\) as our inner function. The chain rule enabled us to efficiently manage the complexity of differentiating, ultimately simplifying the process to find the effective rate of change for the problem at hand.
Mathematical Modeling in Problem Solving
Mathematical modeling is a method of representing real-world phenomena through mathematical expressions, equations, or functions. It simplifies complex situations to provide insights and make predictions. In the context of the provided exercise, the model \(y = 5.5 \sqrt{\ln x}\) represents a real biological phenomenon: the relationship between diet protein levels and the weight of a fruit fly. By using this model, we can predict how changes in diet composition impact the fly's development in terms of weight. The process of modeling involves:
  • Identifying known variables and their relationships
  • Forming equations or functions that reflect these relationships
  • Using calculus techniques, such as differentiation, to explore changes and make forecasts
Mathematical modeling is crucial because it helps convert complex biological processes into manageable and calculable problems.
Applications of Calculus in Biology
Biology often involves studying dynamic systems and changes over time, making calculus a valuable tool. In various biological applications, calculus helps model growth patterns, rate of reactions, and other temporal changes. In the given exercise, calculus helps us understand how a biological process—the weight gain of a Mediterranean fruit fly based on its diet—changes depending on different inputs, namely protein levels. By using differentiation, biologists can derive insights into maximum growth rates or identify critical thresholds in diet formulation that lead to optimal development. These applications illustrate why calculus is vital in biology, as it provides precise ways to measure and track changes, thereby aiding in the formulation of data-driven strategies and interventions in research and real-world applications.

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