/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Find the derivative. \(\frac{\... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the derivative. \(\frac{\ln \left(x^{2}\right)}{x+1}\)

Short Answer

Expert verified
The derivative is \( \frac{2 + \frac{2}{x} - 2\ln(x)}{(x+1)^2} \).

Step by step solution

01

Identify the Derivative Structure

The expression \( \frac{\ln(x^2)}{x+1} \) is a quotient, suggesting the use of the quotient rule. Recall that the quotient rule states: if we have \( \frac{f(x)}{g(x)} \), then the derivative is \( \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} \). Here, \( f(x) = \ln(x^2) \) and \( g(x) = x+1 \).
02

Differentiate the Numerator

Start by finding \( f'(x) \). We know \( f(x) = \ln(x^2) \). Apply the chain rule: the derivative of \( \ln(u) \) is \( \frac{1}{u} \cdot \frac{du}{dx} \). Here, \( u = x^2 \) and \( \frac{du}{dx} = 2x \). So, \( f'(x) = \frac{1}{x^2} \cdot 2x = \frac{2}{x} \).
03

Differentiate the Denominator

Next, find \( g'(x) \). Given \( g(x) = x+1 \), the derivative \( g'(x) = 1 \), because the derivative of \( x \) is 1 and the derivative of a constant is 0.
04

Apply the Quotient Rule

Substitute \( f(x), f'(x), g(x), \) and \( g'(x) \) into the quotient rule formula. We find:\[\frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} = \frac{\left(\frac{2}{x}\right)(x+1) - \ln(x^2)(1)}{(x+1)^2}\]Simplifying the numerator, we get:\[\frac{2(x+1)}{x} - \ln(x^2) = \frac{2x + 2}{x} - \ln(x^2)\]Thus, the derivative simplifies to:\[\frac{2 + \frac{2}{x} - \ln(x^2)}{(x+1)^2}\]
05

Simplify the Derivative Expression

Rewrite the term \( \ln(x^2) \) using the property \( \ln(x^2) = 2\ln(x) \):\[\frac{2 + \frac{2}{x} - 2\ln(x)}{(x+1)^2}\]This is the simplified form of the derivative of the given function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
When dealing with derivatives that involve one function divided by another, the **quotient rule** is the go-to method. It's specifically used for expressions of the form \( \frac{f(x)}{g(x)} \). The quotient rule formula states: the derivative of \( \frac{f(x)}{g(x)} \) is given by \( \frac{f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} \).
  • **Numerator Derivative**: Find the derivative of the top function, \( f(x) \), denoted as \( f'(x) \).
  • **Denominator Derivative**: Differentiate the bottom function, \( g(x) \), to get \( g'(x) \).
  • **Apply Formula**: Plug \( f(x), f'(x), g(x), \) and \( g'(x) \) into the quotient rule formula.
For the given expression \( \frac{\ln(x^2)}{x+1} \), we determined:
  • \( f(x) = \ln(x^2) \)
  • \( g(x) = x+1 \)
  • \( f'(x) = \frac{2}{x} \)
  • \( g'(x) = 1 \)
Use these to calculate the derivative using the quotient rule as outlined.
Chain Rule
The **chain rule** is a powerful technique for finding the derivative of composite functions. These are functions within other functions, such as \( \ln(x^2) \). The rule states that if you have a composite function \( h(x) = f(g(x)) \), then its derivative \( h'(x) \) is \( f'(g(x)) \cdot g'(x) \).
In this case:- Identify the inner function \( u(x) = x^2 \) and its derivative \( \frac{du}{dx} = 2x \).- The outer function is the natural logarithm \( \ln(u) \) with the derivative \( \frac{1}{u} \).Together, the derivative of \( \ln(x^2) \) becomes \( \frac{1}{x^2} \cdot 2x = \frac{2}{x} \).
By using the chain rule, we simplify complex functions and make differentiation more manageable. This is especially useful in calculus, where nested functions are frequent.
Logarithmic Differentiation
Sometimes direct differentiation is cumbersome, especially when dealing with complex logarithmic expressions. **Logarithmic differentiation** offers an alternative by using the properties of logarithms to simplify the differentiation process.
Key steps include:
  • Rewrite complicated expressions using logarithm properties, such as \( \ln(x^2) = 2\ln(x) \), which makes derivative calculation simpler.
  • Differentiate the simpler logarithmic expression.
  • Use the derivation from simpler forms to substitute back into the original context.
This method is particularly effective when handling logarithms of powers because it immediately reduces complexity, allowing focus on applying the chain and quotient rules without getting bogged in algebraic manipulations. As seen in the expression \( \ln(x^2) \), we simplified \( \ln(x^2) \) to \( 2\ln(x) \), which streamlined the derivative calculation to \( \frac{2}{x} \). Logarithms can be handy not only for powers but also for products and quotients, making this an indispensable technique in calculus.

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