/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Find \(f^{\prime}(x)\) $$ f(... [FREE SOLUTION] | 91Ó°ÊÓ

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Find \(f^{\prime}(x)\) $$ f(x)=\frac{e^{x}+x^{2}-2 x+4}{6} $$

Short Answer

Expert verified
The derivative is \( f^{\prime}(x) = \frac{e^{x}}{6} + \frac{x}{3} - \frac{1}{3} \).

Step by step solution

01

Identify the Function and its Components

The function provided is \( f(x) = \frac{e^{x} + x^{2} - 2x + 4}{6} \). It is composed of multiple terms in the numerator, including exponential, polynomial, and constant terms, all divided by 6.
02

Apply the Constant Multiple Rule

The function has a constant multiplier \( \frac{1}{6} \). According to the Constant Multiple Rule, the derivative of a constant multiplied by a function is the constant multiplied by the derivative of the function: \( f^{\prime}(x) = \frac{1}{6} \cdot (e^{x} + x^{2} - 2x + 4)^{\prime} \).
03

Differentiate Each Term Separately

Differentiate each term inside the parentheses. The derivative of \( e^{x} \) is \( e^{x} \), the derivative of \( x^{2} \) is \( 2x \), the derivative of \(-2x \) is \(-2 \), and the derivative of the constant 4 is 0. Thus, \((e^{x} + x^{2} - 2x + 4)^{\prime} = e^{x} + 2x - 2\).
04

Combine Results to Find \( f^{\prime}(x) \)

Multiply the result from Step 3 by \( \frac{1}{6} \): \( f^{\prime}(x) = \frac{1}{6} \cdot (e^{x} + 2x - 2) \). Simplifying further gives \( f^{\prime}(x) = \frac{e^{x}}{6} + \frac{2x}{6} - \frac{2}{6} \), which simplifies to \( f^{\prime}(x) = \frac{e^{x}}{6} + \frac{x}{3} - \frac{1}{3} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Function
An exponential function is a mathematical expression where the variable appears as an exponent. The most common base for exponentials is the number \( e \), approximately equal to 2.71828. This number is considered a fundamental mathematical constant. The function \( e^{x} \) is unique because its rate of change—its derivative—is the same as its value. In simpler terms, the slope of the tangent line at any point on the graph of \( e^{x} \) is equal to \( e^{x} \) itself.
Understanding exponential functions is crucial in calculus because they model growth and decay processes. Examples include population growth and radioactive decay. When you see \( e^{x} \) in a function, remember its behavior under differentiation:
  • The derivative of \( e^{x} \) is \( e^{x} \).
Use this knowledge to calculate the derivative of complex functions like the one in the exercise.
Polynomial Terms
Polynomial terms are algebraic expressions that consist of variables and coefficients combined using addition, subtraction, multiplication, and non-negative integer exponents. In the exercise provided, terms like \( x^{2} \), \(-2x\), and even the constant 4 are part of the polynomial structure.
Polynomials are classified by degree, which is the highest exponent of the variable. For example, \( x^{2} \) is a second-degree term. Each term's derivative in a polynomial can be calculated using basic differentiation rules:
  • The derivative of \( x^{n} \) is \( nx^{n-1} \).
  • For constants, the derivative is 0.
Understanding how to differentiate polynomial terms is essential for solving calculus problems that involve complex functions comprised of various types of terms.
Constant Multiple Rule
The constant multiple rule is a key concept in differentiation. It states that if you have a constant multiplied by a function, you can differentiate by simply differentiating the function and then multiplying by the constant. This simplifies the process and makes calculations easier.
In the context of the provided exercise, we have a constant \( \frac{1}{6} \) applied to the entire function \( \left(e^{x} + x^{2} - 2x + 4\right) \). According to the constant multiple rule, the derivative is:
  • \( f'(x) = \frac{1}{6} \times \left(e^{x} + x^{2} - 2x + 4\right)' \)
This rule ensures clarity and efficiency, allowing you to focus on differentiating the expression inside the parentheses before addressing the multiplier.
Differentiation
Differentiation is the calculus process of finding the derivative of a function. The derivative represents the rate at which a function's output value changes with respect to changes in the input value. Essentially, it answers the question, "How does \( y \) change as \( x \) changes?"
In calculus, differentiation is used to find the slope of a function at any given point, investigate the function's behavior, and solve complex mathematical models. For the function in the exercise, you differentiate each term individually:
  • The derivative of \( e^{x} \) is \( e^{x} \).
  • The derivative of \( x^{2} \) is \( 2x \).
  • The derivative of \(-2x\) is \(-2\).
  • The derivative of a constant like 4 is 0.
After differentiating, combine the results, apply any constants, and simplify to obtain the final derivative, effectively unlocking the function's behavior with respect to its variables.

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Most popular questions from this chapter

Economies of Scale in Food Retailing Using data from the files of the National Commission on Food Retail- ing concerning the operating costs of thousands of stores, Smith \(^{24}\) showed that the sales expense as a percent of sales \(S\) was approximated by the equation \(S(x)=0.4781 x^{2}-\) \(5.4311 x+16.5795,\) where \(x\) is in sales per square foot and \(x \leq 7\) a. Find \(S^{\prime}(x)\) for any \(x\). b. Find \(S^{\prime}(4), S^{\prime}(5), S^{\prime}(6),\) and \(S^{\prime}(7)\). Interpret what is happening. c. Graph the cost function on a screen with dimensions [0,9.4] by \([0,12] .\) Also graph the tangent lines at the points where \(x\) is \(4,5,6,\) and 7 . Observe how the slope of the tangent line is changing, and relate this to the observations made above concerning the rates of change. d. Use the available operations on your computer or graphing calculator to the find where the function attains a minimum.

Costs The weekly total cost function for a company in dollars is \(C(x)\). If \(C^{\prime}(100)=25,\) what is the approximate cost of the 101 st item?

Take \(x>0\) and find the derivatives. \((\ln x)^{11}\)

In this section we considered demand \(x\) as a function \(x=f(p)\) of price and then defined the elasticity as \(E=-\frac{p}{x} \frac{d x}{d p} .\) But demand is also a function of other variables. For example, Cotterill and Haller \({ }^{79}\) recently found that the demand \(x\) for the breakfast cereal Shredded Wheat was approximately related to the amount \(a\) of coupons issued by \(x=B a^{0.0229}\), where \(B\) is a constant. Define an elasticity with respect to coupons in a way analogous to what was done for demand with respect to price. Find the elasticity with respect to couponing in this case, and explain in words what it means.

Find the equation of the tangent line of the given function at the indicated point. Support your answer using a computer or graphing calculator. $$ y=f(x)=x^{-1}+x^{-2}+\ln x, x_{0}=1 $$

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