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In Exercises 1 through \(34,\) find the derivative. $$ f(x)=4 x^{6 / 5}+5 x^{2 / 5}+3 $$

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{24}{5}x^{1/5} + 2x^{-3/5} \).

Step by step solution

01

Understand the Problem

The function given is \( f(x) = 4x^{6/5} + 5x^{2/5} + 3 \). We need to find \( f'(x) \), the derivative of the function with respect to \( x \).
02

Apply the Power Rule for Derivatives

The power rule states that the derivative of \( x^n \) is \( nx^{n-1} \). We will apply this rule to each term in the function.
03

Derivative of the First Term

The first term is \( 4x^{6/5} \). Apply the power rule: \( \frac{d}{dx}[4x^{6/5}] = 4 \cdot \frac{6}{5} x^{(6/5)-1} = \frac{24}{5}x^{1/5} \).
04

Derivative of the Second Term

The second term is \( 5x^{2/5} \). Apply the power rule: \( \frac{d}{dx}[5x^{2/5}] = 5 \cdot \frac{2}{5} x^{(2/5)-1} = 2x^{-3/5} \).
05

Derivative of the Constant Term

The last term is \( 3 \) and since the derivative of a constant is zero, \( \frac{d}{dx}[3] = 0 \).
06

Combine the Derivatives

Combine the derivatives of each term to get the overall derivative: \[ f'(x) = \frac{24}{5}x^{1/5} + 2x^{-3/5} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a simple yet powerful tool in calculus for finding derivatives. It's primarily used to differentiate polynomial terms like \(x^n\), where \(n\) is any real number. The power rule states: whenever you take the derivative of \(x^n\), you multiply \(n\) by \(x\) and subtract one from the exponent. The formula is:
  • \( \frac{d}{dx}[x^n] = nx^{n-1} \)
For example, if your function is \(x^3\), applying the power rule gives a derivative of \(3x^{2}\). It's critical to remember this rule applies to every term individually. So, a term like \(4x^{6/5}\) needs to be treated as \(4\) (the constant) multiplied by \(x^{6/5}\). By using the power rule, you start by differentiating \(x^{6/5}\), resulting in \(\frac{6}{5}x^{1/5}\), and then multiplying by \(4\), yielding \(\frac{24}{5}x^{1/5}\). This rule simplifies differentiation significantly and is a fundamental tool for calculus students.
Derivative Calculation
Calculating derivatives using the power rule begins with identifying each term in your function and noting their exponents. Let's break down the derivative calculation for \(f(x)=4x^{6/5}+5x^{2/5}+3\):
  • Identify each term: \(4x^{6/5}\), \(5x^{2/5}\), and \(3\).
  • Apply the power rule, adjusting the exponent and coefficient for each term.
  • Combine results to find the complete derivative.
For the first term, \(4x^{6/5}\), the derivative is \(\frac{24}{5}x^{1/5}\). The second term, \(5x^{2/5}\), differentiates to \(2x^{-3/5}\). And the constant, \(3\), becomes zero since the derivative of a constant is always zero.
Combining these results gives you the overall derivative: \(f'(x) = \frac{24}{5}x^{1/5} + 2x^{-3/5}\). This process highlights how derivatives simplify expressions, critical in finding how functions change at any point.
Functions and Derivatives
Understanding the relationship between functions and derivatives is crucial in calculus. A function represents a mathematical relationship, where each input corresponds to an output. Derivatives, on the other hand, provide a snapshot of how a function changes at any given point.
When you take the derivative of a function, you're finding its rate of change, or slope, at any point along its curve. For instance, consider the function \(f(x)=4x^{6/5}+5x^{2/5}+3\). Its derivative \(f'(x) = \frac{24}{5}x^{1/5} + 2x^{-3/5}\) tells us how fast or slow the function is rising or falling at any \(x\).
  • If \(f'(x)\) is positive, the function is increasing.
  • If \(f'(x)\) is negative, the function is decreasing.
  • When \(f'(x) = 0\), there is no change -- this might indicate a local maximum or minimum.
Derivatives are a core component of calculus, allowing us to analyze trends and make predictions based on mathematical models.

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Most popular questions from this chapter

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