/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 In Exercises 1 through \(34,\) f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 1 through \(34,\) find the derivative. $$ f(x)=(\sqrt{x})\left(x^{4}-2 x^{2}+3\right) $$

Short Answer

Expert verified
The derivative is \( f'(x) = \frac{x^4 - 2x^2 + 3}{2\sqrt{x}} + 4x^{3.5} - 4x^{1.5} \).

Step by step solution

01

Identify the functions to apply the product rule

The function given is a product of two functions: \( u(x) = \sqrt{x} \) and \( v(x) = x^4 - 2x^2 + 3 \). We will apply the product rule: if \( f(x) = u(x) \cdot v(x) \), then \( f'(x) = u'(x) \cdot v(x) + u(x) \cdot v'(x) \).
02

Differentiate the first function

The first function is \( u(x) = \sqrt{x} \), which is the same as \( x^{1/2} \). Its derivative is found using the power rule: \( u'(x) = \frac{1}{2}x^{-1/2} = \frac{1}{2\sqrt{x}} \).
03

Differentiate the second function

The second function is \( v(x) = x^4 - 2x^2 + 3 \). Differentiating term by term using the power rule, its derivative is \( v'(x) = 4x^3 - 4x \).
04

Apply the product rule

Substitute the derivatives back into the product rule formula: \( f'(x) = u'(x) \cdot v(x) + u(x) \cdot v'(x) \). This becomes \[ f'(x) = \frac{1}{2\sqrt{x}} (x^4 - 2x^2 + 3) + \sqrt{x} (4x^3 - 4x) \].
05

Simplify the expression

Distribute and combine terms. Simplifying the expression: \[ f'(x) = \frac{x^4 - 2x^2 + 3}{2\sqrt{x}} + 4x^{3.5} - 4x^{1.5} \]. You may optionally combine further into a common denominator, or expand terms further as needed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Product Rule
When we need to differentiate interactions between two functions multiplied together, the product rule is our tool of choice. It's quite helpful when dealing with expressions like \( f(x) = (u(x))(v(x)) \), where each component is a function of \( x \).

The product rule is written as \[ f'(x) = u'(x) v(x) + u(x) v'(x) \]. This means that, to find the derivative of the product of two functions, we take the derivative of the first function, and multiply it by the second function. Then, we do the reverse: take the derivative of the second function and multiply it by the first function. Finally, we sum these two results together.

Using the product rule ensures that you account for the changes in both functions as \( x \) changes. This is crucial when both functions contribute differently to the overall rate of change of \( f \).
Differentiation Techniques
When differentiating, we need various techniques to handle different types of functions. Differentiation is all about understanding how a function changes as its input changes, and various techniques allow us to deal with diverse functional forms.

  • **Chain Rule**: Used when dealing with compositions of functions.
  • **Quotient Rule**: Perfect for quotients of functions.
  • **Product Rule**: Comes into play with products of two or more functions, as discussed earlier.
  • **Implicit Differentiation**: Useful when it’s hard or impossible to solve for one variable in terms of another directly.
By mastering these techniques, we can tackle virtually any function, ensuring we can compute derivatives efficiently. Knowing when and how to apply each method allows for better control and understanding of calculus problems.

Practice is essential to gain familiarity with these methods, as each technique has its own scenarios and nuances.
Power Rule
The power rule is one of the simplest and most commonly used rules in differentiation. It feels like an old friend's comfort, especially when dealing with polynomial functions.

If you have a function of the form \( f(x) = x^n \), where \( n \) is any real number, the power rule says this: \[ f'(x) = nx^{n-1} \].

In essence, you bring the exponent in front as a coefficient, then decrease the exponent by one. This rule is magical because it significantly simplifies the process of differentials.

For example, in the function \( v(x) = x^4 - 2x^2 + 3 \), applying the power rule to each term, we get:
  • Derivative of \( x^4 \): Move 4 in front to get \( 4x^3 \).
  • Derivative of \( -2x^2 \): Move -2 in front and multiply, resulting in \( -4x \).
  • Derivative of constant \( 3 \): Constants always differentiate to zero.
Understanding and practicing the power rule hones your ability to simplify and handle polynomial derivatives with ease. It forms the groundwork for many other derivative operations in calculus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Biology Talekar and coworkers \(^{91}\) showed that the number \(y\) of the eggs of \(O\). furnacalis per mung bean plant was approximated by \(y=f(x)=-57.40+63.77 x-\) \(20.83 x^{2}+2.36 x^{3},\) where \(x\) is the age of the mung bean plant and \(2 \leq x \leq 7\). Find \(f^{\prime}(x),\) and explain what this means. Use the quadratic formula to show that \(f^{\prime}(x)>0\) for \(2 \leq x \leq 7\). What does this say about the preference of O. furnacalis to laying eggs on older plants?

Economies of Scale in Food Retailing Using data from the files of the National Commission on Food Retail- ing concerning the operating costs of thousands of stores, Smith \(^{24}\) showed that the sales expense as a percent of sales \(S\) was approximated by the equation \(S(x)=0.4781 x^{2}-\) \(5.4311 x+16.5795,\) where \(x\) is in sales per square foot and \(x \leq 7\) a. Find \(S^{\prime}(x)\) for any \(x\). b. Find \(S^{\prime}(4), S^{\prime}(5), S^{\prime}(6),\) and \(S^{\prime}(7)\). Interpret what is happening. c. Graph the cost function on a screen with dimensions [0,9.4] by \([0,12] .\) Also graph the tangent lines at the points where \(x\) is \(4,5,6,\) and 7 . Observe how the slope of the tangent line is changing, and relate this to the observations made above concerning the rates of change. d. Use the available operations on your computer or graphing calculator to the find where the function attains a minimum.

Fishery Revenue Grafton \(^{30}\) created a mathematical model of demand for northern cod and formulated the demand equation $$ p(x)=\frac{173213+0.2 x}{138570+x} $$ where \(p\) is the price in dollars and \(x\) is in kilograms. Find marginal revenue. What is the sign of the derivative for \(x \leq 400,000 ?\) Is the sign consistent with how a revenue curve should behave? Explain.

Velocity A particle moves according to the law \(s(t)=\) \(-2 t^{4}+64 t+15,\) where \(s\) is in feet and \(t\) in seconds. Find the instantaneous velocity at \(t=1,2,3\). Interpret your answers.

Cost It is estimated that the cost, \(C(x)\), in millions of dollars, of maintaining the toxic emissions of a certain chemical plant \(x \%\) free of the toxins is given by $$ C(x)=\frac{4}{100-x} $$ Find the marginal cost.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.