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In Exercises 1 through \(22,\) find the derivative. $$ (2 x+1)^{7} $$

Short Answer

Expert verified
The derivative is \(14 (2x + 1)^6\).

Step by step solution

01

Identifying the Formula to Use

To find the derivative of the function \((2x+1)^7\), we recognize that this is a composition of functions where we can apply the chain rule. The chain rule is suitable for functions of the form \((g(x))^n\), where the outer function is \(u^n\) and the inner function is \(g(x)\).
02

Applying the Power Rule

The power rule states that the derivative of \(u^n\) with respect to \(u\) is \(n \cdot u^{n-1}\). Here, we identify \(u = 2x + 1\) and \(n = 7\). Applying the power rule with these values results in \(7 \cdot (2x + 1)^6\).
03

Applying the Chain Rule

The chain rule requires multiplying the result of the power rule by the derivative of the inner function \(g(x)\). For \(g(x) = 2x + 1\), the derivative \(g'(x)\) is 2. Therefore, we multiply the expression from the power rule by 2, resulting in \(7 \cdot (2x + 1)^6 \cdot 2\).
04

Finalizing the Derivative

Combining and simplifying the expression from the previous step, the final derivative of the function \((2x+1)^7\) is \((14 \cdot (2x + 1)^6)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental concept in calculus used for finding the derivative of composite functions. It is especially handy when a function involves another function nested within it. For example, consider a function of the form \(f(g(x))\). Here, \(f\) is the outer function and \(g(x)\) is the inner function.

To apply the chain rule, first find the derivative of the outer function with respect to the inner function, and then multiply it by the derivative of the inner function with respect to \(x\). The formula for the chain rule is expressed as:

  • \(\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)\)

In simple terms, the chain rule helps you "chain" together the derivatives of the respective parts of a composite function. This is crucial in situations like our example, \((2x+1)^7\), where the chain rule allows us to correctly account for both the outer power function and the inner linear function.

Power Rule
The power rule is one of the basic rules in calculus used to find the derivative of a function raised to a power. Specifically, if you have a function of the form \(u^n\), the power rule provides a quick method to find its derivative.

The rule is straightforward: bring down the exponent \(n\), multiply it by \(u^{n-1}\), and you have the derivative.

  • Formula: \(\frac{d}{du}[u^n] = n \cdot u^{n-1}\)

In the context of our example \((2x+1)^7\), applying the power rule means that we take the exponent 7, multiply it by \((2x+1)^6\), which simplifies our expression. This is the first step before applying the chain rule to incorporate the derivative of the inner function \(2x+1\).

Calculus
Calculus is the branch of mathematics that deals with continuous change. It provides tools for understanding changes between related quantities. Derivatives are one of the central concepts in calculus, representing how a function changes as its input changes.

Specifically, derivatives allow you to find the rate at which one quantity changes in relation to another. They are essential in numerous applications such as physics, engineering, economics, and beyond.

  • Expression of change: \(\frac{dy}{dx}\) shows change in \(y\) with respect to \(x\).
  • Used in optimization problems: To find maxima and minima.

In the example of \((2x + 1)^7\), we see calculus in action as it provides the techniques and rules—the chain rule and power rule—to methodically find the derivative. Understanding calculus, especially derivatives, is crucial for solving real-world problems where variables continuously change and interact.

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Most popular questions from this chapter

Biology Miller \(^{19}\) determined that the equation \(y=\) \(0.12\left(L^{2}+0.0026 L^{3}-16.8\right)\) approximated the reproduction rate, measured by the number of eggs per year, of the rock goby versus its length in centimeters. Find the rate of change of reproduction with respect to length.

Recently, Cotterill and Haller \(^{77}\) found that the price \(p\) of the breakfast cereal Grape Nuts was related to the quantity \(x\) sold by the equation \(x=A p^{-2.0711}\), where \(A\) is a constant. Find the elasticity of demand and explain what it means.

Protein in Milk Crocker and coworkers \(^{12}\) studied the northern elephant seal in Ano Nuevo State Reserve, California. They created a mathematical model given by the equation \(W(D)=62.3-2.68 D+0.06 D^{2},\) where \(D\) is days postpartum and \(W\) is the percentage of water in the milk. Find \(W^{\prime}(D)\). Find \(W^{\prime}(10)\). Give units.

Economies of Scale in Food Retailing Using data from the files of the National Commission on Food Retail- ing concerning the operating costs of thousands of stores, Smith \(^{24}\) showed that the sales expense as a percent of sales \(S\) was approximated by the equation \(S(x)=0.4781 x^{2}-\) \(5.4311 x+16.5795,\) where \(x\) is in sales per square foot and \(x \leq 7\) a. Find \(S^{\prime}(x)\) for any \(x\). b. Find \(S^{\prime}(4), S^{\prime}(5), S^{\prime}(6),\) and \(S^{\prime}(7)\). Interpret what is happening. c. Graph the cost function on a screen with dimensions [0,9.4] by \([0,12] .\) Also graph the tangent lines at the points where \(x\) is \(4,5,6,\) and 7 . Observe how the slope of the tangent line is changing, and relate this to the observations made above concerning the rates of change. d. Use the available operations on your computer or graphing calculator to the find where the function attains a minimum.

In Exercises 25 through \(32,\) use the quotient rule to find \(\frac{d y}{d u}\). $$ y=\frac{\sqrt[3]{u}}{u^{3}-e^{u}-1} $$

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