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Find the limits graphically. Then confirm algebraically. $$ \lim _{h \rightarrow 0} \frac{(2+h)^{2}-4}{h} $$

Short Answer

Expert verified
The limit is 4.

Step by step solution

01

Understand the Expression

First, recognize that the limit expression is in the form of a difference quotient. It resembles the derivative of the function at a particular point. Here, we have \[\lim _{h \rightarrow 0} \frac{(2+h)^{2}-4}{h}.\] This can be interpreted as the derivative of a function at the point where its base is 2. The term \((2 + h)^2 - 4\) suggests differentiating \(x^2\) at \(x = 2\).
02

Graphical Analysis

Plot the function \(y = \frac{(2+h)^2 - 4}{h}\) for values of \(h \) approaching 0, both from the positive and negative sides. You can use a graphing calculator or software. Observe how the function behaves and approaches a particular value as \(h\) gets closer to zero from both sides. The graph will show that as \(h\) approaches zero, the function approaches a specific value, which hints at the limit value.
03

Algebraic Expansion

Expand \((2+h)^2\). This gives:\[(2+h)^2 = 4 + 4h + h^2.\] Substitute this back into the expression:\[\frac{(4 + 4h + h^2) - 4}{h} = \frac{4h + h^2}{h}.\]
04

Simplify the Expression

Factor out \( h \) from the numerator:\[\frac{h(4+h)}{h}.\] Since \( h eq 0 \) when considering limits, cancel the \( h \) from the numerator and denominator, leaving:\[4 + h.\]
05

Evaluate the Limit

Now that the expression is simplified, evaluate the limit as \( h \) approaches 0:\[\lim_{h \to 0} (4 + h) = 4.\] As \(h\) approaches 0, the expression approaches 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference Quotient
The difference quotient is a fundamental concept in calculus, playing a significant role in understanding how functions change. It serves as a tool to approximate the derivative of a function around a specific point. The expression \[ \frac{(2+h)^2 - 4}{h} \] is a classic example of a difference quotient. In this case, it helps us find how the function \( f(x) = x^2 \) changes near \( x=2 \).

Think of the difference quotient as the average rate of change of the function over the interval from \( x = 2 \) to \( x = 2 + h \). As \( h \) approaches zero, this average rate becomes the instantaneous rate of change, or the derivative, at \( x = 2 \).

This form is pivotal because it lays the groundwork for understanding derivatives more deeply and is widely used in calculus to transition from a basic algebraic understanding of functions to their continuous analysis. By examining this expression, students can grasp not only how the function transforms as \( h \) gets infinitesimally small, but also why this transformation is crucial for finding derivatives.
Derivative
The derivative is the cornerstone of calculus, describing how a function changes at any point. It's the limit of the difference quotient as \( h \) approaches zero. By evaluating\[ \lim _{h \to 0} \frac{(2+h)^2 - 4}{h} \]we are essentially finding the derivative of the function\( f(x) = x^2 \)at \( x = 2 \).

When the difference quotient simplifies to \( 4 + h \)and taking the limit results in 4, we conclude that the derivative at \( x = 2 \)is 4. This means the slope of the tangent line to the curve \( y = x^2 \)at\( x = 2 \)is 4.

Understanding derivatives is essential not only for solving mathematical problems but also for practical applications such as calculating velocities, accelerating, predicting trends, and modeling changes. A derivative tells us precisely how a quantity changes, providing insights that are central to physics, engineering, economics, and beyond.
Graphical Analysis
Graphical analysis can make the abstract concept of limits and derivatives more tangible. By plotting the function\[ y = \frac{(2+h)^2 - 4}{h} \]for values of \( h \)approaching zero, one can visually explore how the function behaves. Using graphing software, observe the function as \( h \)gets closer to zero from both sides. This visual representation aids in understanding what the limit signifies.

As \( h \)nears zero from either the positive or negative direction, the graph will approach the same value, 4, reinforcing the algebraic limit calculation. Such visual reinforcement strengthens comprehension by showing that even as tiny changes in \( h \)occur, the function settles towards the same limit.

Graphical methods, therefore, bridge the gap between theoretical calculations and practical visualization, providing a fuller picture of why limits and derivatives function the way they do. They are a powerful tool to validate algebraic solutions and offer intuitive insights into mathematical behavior.
Algebraic Simplification
Algebraic simplification is a crucial step in solving limit problems, ensuring that expressions can be neatly managed and evaluated. In the given limit problem, the expression\[ (2+h)^2 \]is expanded using basic algebraic principles to\[ 4 + 4h + h^2. \]

Inserting it back into the difference quotient yields\[ \frac{4h + h^2}{h}, \]which can be further simplified by factoring \( h \)from the numerator. This leads to\[ \frac{h(4 + h)}{h}, \]allowing the \( h \)terms to cancel out since \( h eq 0. \)

The result is the expression \( 4 + h \),which can now be directly evaluated as \( h \to 0 \).

Simplifying the algebra allows for an easy determination of the limit, removing indeterminate forms that typically complicate direct substitution. Mastering algebraic techniques is essential, not only in calculus but across multiple mathematical contexts, to streamline processes and solve problems effectively.

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Most popular questions from this chapter

Find, without graphing, where each of the given functions is continuous. $$ f(x)=\left\\{\begin{array}{ll} \frac{x^{2}+x+2}{x-1} & \text { if } x<0 \\ x^{5}+x^{3}+2 x-2 & \text { if } x \geq 0 \end{array}\right. $$

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