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Jobbagy and colleagues \(^{51}\) determined a mathematical model given by the equation \(G(T)=\) \(278-7.1 T-1.1 T^{2},\) where \(G\) is the start of the growing season in the Patagonian steppe in Julian days (day \(1=\) January 1) and \(T\) is the mean July temperature in degrees Celsius. Graph this equation on the interval \([-3,5] .\) Find the instantaneous rate of change of the day of the start of the growing season with respect to the mean July temperature for any \(T\). Give units and interpret your answer.

Short Answer

Expert verified
The instantaneous rate of change of \( G(T) \) with respect to \( T \) is \( -7.1 - 2.2T \) days per degree Celsius.

Step by step solution

01

Understand the Problem

We have a function \( G(T) = 278 - 7.1T - 1.1T^2 \) that models the start of the growing season in the Patagonian steppe based on the mean July temperature \( T \) in degrees Celsius. We need to graph this for \( T \) in the interval \([-3, 5]\) and find the instantaneous rate of change of \( G(T) \) with respect to \( T \), which involves finding the derivative \( G'(T) \).
02

Find the Derivative

The derivative \( G'(T) \) of the function \( G(T) = 278 - 7.1T - 1.1T^2 \) is calculated using basic differentiation rules. Differentiating, we get \( G'(T) = -7.1 - 2.2T \). This represents the rate of change of \( G \) with respect to \( T \).
03

Interpret the Derivative

The derivative \( G'(T) = -7.1 - 2.2T \) indicates how the starting day of the growing season changes per degree change in the July temperature. Since both terms are negative, as \( T \) increases, \( G(T) \) decreases. Specifically, for every 1 degree Celsius increase in temperature, the start of the growing season occurs earlier by the value of \( -7.1 - 2.2T \) days. Units: days per degree Celsius.
04

Graph the Function

To graph \( G(T) = 278 - 7.1T - 1.1T^2 \) over the interval \([-3, 5]\), plot it on a graph using a software tool or graphing calculator. At \( T = -3 \), \( G(-3) = 258.8 \), and at \( T = 5 \), \( G(5) = 215.5 \). The curve is a downward-opening parabola.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
In differential calculus, derivatives are fundamental in understanding how functions change. A derivative represents the instantaneous rate of change of a function at any given point. For our exercise, the function is \( G(T) = 278 - 7.1T - 1.1T^2 \). Here, the derivative tells us how the start of the growing season changes as the mean July temperature, \( T \), shifts.
To find the derivative, we apply basic differentiation rules:
  • The derivative of a constant like \( 278 \) is zero since constants do not change.
  • For the term \( -7.1T \), we use the power rule which gives us \( -7.1 \).
  • For \( -1.1T^2 \), we again use the power rule. Multiplying the coefficient \( -1.1 \) by the exponent \( 2 \), we get \( -2.2T \).
Putting it all together, the derivative \( G'(T) = -7.1 - 2.2T \) tells how quickly \( G(T) \) is changing at any specific temperature \( T \). This is measured in days per degree Celsius, providing insight into how seasonal changes are affected by temperature conditions in the Patagonian steppe.
Graphing Functions
Graphing functions is essential for visualizing mathematical models. It helps us understand the relationship between variables, such as temperature \( T \) and the start of the growing season \( G(T) \). For the function \( G(T) = 278 - 7.1T - 1.1T^2 \), we're asked to graph it over the interval \([-3, 5]\).
To create the graph:
  • Use a graphing software or calculator to easily plot the equation. This gives a clear view of the function's behavior over the given range.
  • Identify key points: At \( T = -3 \), calculate \( G(-3) \) to find it equals 258.8. Similarly, at \( T = 5 \), \( G(5) \) is 215.5.
  • Recognize that this is a quadratic function, indicated by the \( T^2 \) term, so it forms a parabolic curve. Since the coefficient of \( T^2 \) is negative, the parabola opens downward.
This method of graphing not only shows the direction of the curve but also underlines the decrease in \( G(T) \) as \( T \) increases, aligning with our derivative's findings.
Mathematical Modeling
Mathematical modeling uses equations to represent real-world scenarios. In our exercise, the model \( G(T) = 278 - 7.1T - 1.1T^2 \) takes into account how the mean July temperature (\( T \)) influences the start of the growing season in the Patagonian steppe. Such models are invaluable in fields like environmental science to predict seasonal changes based on climate variables.
The process involves:
  • Identifying the variables: In this case, temperature \( T \) is the independent variable, and \( G(T) \), representing the growing season's start, is the dependent variable.
  • Creating the function based on observed data: The coefficients and structure of the function are derived from empirical research done by Jobbagy and colleagues.
  • Using derivatives to predict changes: As expressed by \( G'(T) \), future conditions can be anticipated by evaluating how much earlier the growing season could start with temperature shifts.
This model illustrates both the power and necessity of mathematical equations in capturing and predicting dynamic environmental processes, demonstrating how predictions are not arbitrary but grounded in quantitative data and relationships.

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Most popular questions from this chapter

Cost Curve Dean \(^{43}\) made a statistical estimation of the average cost- output relationship for a shoe chain for \(1937 .\) The data for the firm is given in the following table. $$ \begin{array}{l|cccccccccc} x & 4 & 7 & 9 & 12 & 14 & 17 & 22 & 27 & 33 & 40 \\ \hline y & 110 & 90 & 75 & 65 & 60 & 65 & 60 & 45 & 52 & 35 \end{array} $$ Here \(x\) is the output in thousands of pairs of shoes, and \(y\) is the average cost in dollars. a. Use quadratic regression to find the best-fitting quadratic polynomial using least squares. b. Graph on your graphing calculator or computer using a screen with dimensions [0,56.4] by \([0,120] .\) Have your grapher draw tangent lines to the curve when \(x\) is \(18,27,36,42,\) and \(48 .\) Note the slope, and relate this to the rate of change. On the basis of this model, describe what happens to the rate of change of average cost as output increases.

On your computer or graphing calculator, graph \(y=\) \(f(x)=\cos x\) in radian mode, using a window with dimensions [-6.14,6.14] by [-1,1] to familiarize yourself with this function. As you see, this function moves back and forth between -1 and \(1 .\) We wish to estimate \(f^{\prime}(\pi / 2)\) where \(\pi / 2 \approx 1.57\). For this purpose, graph using a window with dimensions [1.07,2.07] by \([-0.5,0.5] .\) From the graph, estimate \(f^{\prime}(1.57)\).

Finance A study of Dutch manufacturers \(^{38}\) found that the total cost \(C\) in thousands of guilders incurred by a company for hiring (or firing) \(x\) workers was approximated by \(C=0.0071 x^{2} .\) Find the rate of change of costs with respect to workers hired when 100 workers are hired. Give units and interpret your answer.

Elliott \(^{62}\) studied the temperature affects on the alder fly. He collected in his laboratory in 1969 the data shown in the following table relating the temperature in degrees Celsius to the number of pupae successfully completing pupation. $$ \begin{array}{|l|cccccc|} \hline t & 8 & 10 & 12 & 16 & 20 & 22 \\ \hline y & 15 & 29 & 41 & 40 & 31 & 6 \\ \hline \end{array} $$ Here \(t\) is the temperature in degrees Celsius, and \(y\) is the number of pupae successfully completing pupation. a. Use quadratic regression to find \(y\) as a function of \(T\). Graph using a window with dimensions [6,24.8] by [0,60] b. Have your computer or graphing calculator find the numerical derivative when \(x\) is \(10,12,15,18,\) and \(20 .\) Relate this number to the slope of the tangent line to the curve and to the rate of change. Interpret what each of these numbers means. On the basis of this model, describe what happens to the rate of change of number of pupae completing pupation as temperature increases.

Use the rules of limits to find the indicated limits if they exist. Support your answer using a computer or graphing calculator. $$ \lim _{x \rightarrow 2} \sqrt{x^{2}-3} $$

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