Chapter 3: Problem 19
Sketch a graph of \(y=f(x)\) to find where \(m_{\tan }(x)\) and thus \(f^{\prime}(x)\) exists. $$ f(x)=-|x-1| $$
Short Answer
Expert verified
The derivative exists for \( x \neq 1 \).
Step by step solution
01
Understanding the Function
The function given is \( f(x) = -|x-1| \), which is the negative of the absolute value function shifted one unit to the right. The absolute value function \( |x-1| \) creates a V-shape graph. The negative sign indicates that this V-shape is flipped upside down.
02
Analyzing the Graph
The graph of \( f(x) = -|x-1| \) has a vertex at \( x = 1 \), which is the point where the graph changes direction. This is a key point because the derivative, \( f'(x) \), will not exist at this point. For any \( x eq 1 \), the graph is a straight line, and the derivative is constant.
03
Calculating the Slopes
Look at the graph to determine the slopes of the different sections. To the left of \( x=1 \) (where \( x < 1 \)), the function is a line with a negative slope. Specifically, it's \( f(x) = -(x-1) = -x+1 \), with a derivative of \( f'(x) = -1 \). To the right of \( x=1 \) (where \( x > 1 \)), the function is \( f(x) = -(x-1) = -x + 1 \), but simplified it remains the same: \( f(x) = -(1-x) = x-1 \), so \( f'(x) = 1 \).
04
Confirming Where Derivative Exists
For \( x < 1 \), the derivative is \( -1 \), and for \( x > 1 \), the derivative is \( 1 \). At \( x = 1 \), the function changes direction, and the slope is undefined at the vertex of the V-shape (the graph of an absolute value function). Therefore, the derivative \( f'(x) \) does not exist at \( x = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Absolute Value Function
An absolute value function, represented as \(|x|\), provides the non-negative value of \(x\).
In simple terms, whether our \(x\) value is positive or negative, the result is always positive. This concept visually translates to a V-shape graph in a 2-dimensional space.
Let's dive deeper into how this looks. For a function like \(f(x) = |x-1|\), the absolute value part \(|x-1|\) moves the vertex of the V-shaped graph to the point \(x=1\), creating two distinct linear parts. Each piece of the function is a line:
In simple terms, whether our \(x\) value is positive or negative, the result is always positive. This concept visually translates to a V-shape graph in a 2-dimensional space.
Let's dive deeper into how this looks. For a function like \(f(x) = |x-1|\), the absolute value part \(|x-1|\) moves the vertex of the V-shaped graph to the point \(x=1\), creating two distinct linear parts. Each piece of the function is a line:
- One line extends infinitely towards the positive x-direction.
- The other extends towards the negative x-direction.
Graph Analysis
Graph analysis involves studying a graph to understand the behavior and properties of the function it represents.
In the case of \(f(x) = -|x-1|\), analyzing the graph helps in determining where the function has specific characteristics like direction change or slope.The vertex of our graph, \(x = 1\), acts as the pivotal point where the function's direction changes. This is where the graph goes from having a negative slope to a positive slope.
Graphically, the inverted V created by \(f(x) = -|x-1|\) demonstrates that:
In the case of \(f(x) = -|x-1|\), analyzing the graph helps in determining where the function has specific characteristics like direction change or slope.The vertex of our graph, \(x = 1\), acts as the pivotal point where the function's direction changes. This is where the graph goes from having a negative slope to a positive slope.
Graphically, the inverted V created by \(f(x) = -|x-1|\) demonstrates that:
- The function slopes downward from the left until it reaches the vertex at \(x = 1\).
- Beyond \(x = 1\), the graph slopes upwards.
Slope of a Line
The slope of a line is essentially the measure of its steepness. When dealing with functions like \(f(x) = -|x-1|\), each linear segment of the graph has its constant slope except at points like vertices.For our given function:
- To the left of the vertex \((x < 1)\), the slope is calculated from the line \(f(x) = -(x-1) = -x+1\), resulting in a slope \(f'(x) = -1\). This negative value indicates the line is slanting downwards.
- To the right of the vertex \((x > 1)\), the slope comes from the line \(f(x) = x-1\), giving us \(f'(x) = 1\). Here, the positive slope signifies the line is slanting upwards.