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Let \(f(x)=3^{x}\). Show that \(3 f(x)=f(x+1)\) and that \(f(a+b)=f(a) \cdot f(b)\).

Short Answer

Expert verified
\(3f(x) = f(x+1)\) and \(f(a+b) = f(a) \cdot f(b)\) are proven using the properties of exponents.

Step by step solution

01

Substitution into the Equation

To show that \(3f(x) = f(x+1)\), we start by substituting the given function \(f(x) = 3^x\) into the left-hand side of the equation. Multiply \(f(x)\) by 3: \[3f(x) = 3 \cdot 3^x = 3^{x+1}.\]
02

Analyze the Right-hand Side

The right-hand side of \(3f(x) = f(x+1)\) is \(f(x+1)\). Substitute \(x+1\) into the function \(f(x)\): \[f(x+1) = 3^{x+1}.\]
03

Equality Confirmation

Compare the expressions from Step 1 and Step 2: both sides of \(3f(x) = f(x+1)\) equal \(3^{x+1}\). Thus, \(3f(x) = f(x+1)\) is confirmed to be true.
04

Express f(a+b) Using Function Definition

To show that \(f(a+b) = f(a) \cdot f(b)\), start by substituting \(a+b\) into \(f(x)\): \[f(a+b) = 3^{a+b}.\]
05

Apply Exponent Rule

Apply the exponent rule, \(3^{a+b} = 3^a \cdot 3^b\), to express \(3^{a+b}\) in terms of \(3^a\) and \(3^b\): \[3^{a+b} = 3^a \cdot 3^b.\]
06

Substitute to Confirm Equality

Recognize that \(3^a = f(a)\) and \(3^b = f(b)\). Hence, \(f(a+b) = 3^a \cdot 3^b = f(a) \cdot f(b)\), confirming \(f(a+b) = f(a) \cdot f(b)\) holds true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponent Rules
Exponent rules are fundamental for dealing with powers and are essential to the manipulation of exponential functions. When working with exponential terms, like base 3 in our function, these rules help us simplify and solve equations.
Consider the exponent rule: \(3^{a+b} = 3^a \cdot 3^b\). This rule is called the "Product of Powers" rule. It states that if you have the same base, you can add the exponents when multiplying.
This rule is very powerful because it allows us to break one exponential expression into two separate, often easier to handle, expressions.
  • For instance, if \(a = 2\) and \(b = 3\), then \(3^{a+b} = 3^{5}\) and also \(3^2 \cdot 3^3 = 3^5\).
  • It's a useful way to verify solutions and ensure exponential expressions are equivalent.
Mastering exponent rules is crucial for solving problems involving exponential functions effectively.
Function Equality
Understanding function equality is important to verify the equivalence of two expressions derived from functions. In our example, proving that \(3f(x) = f(x+1)\) shows function equality in action.
The claim \(3f(x) = f(x+1)\) implies that if you take the output of the function, multiply it by 3, it should be the same as shifting the input by one unit and then using the function.
This can also be seen through substitution and exponent rules since:
  • Inserting \(f(x) = 3^x\) into \(3f(x)\), results in \(3 \times 3^x = 3^{x+1}\).
  • Similarly, \(f(x+1) = 3^{x+1}\).
Since both sides are equivalent, we affirm the function equality. Ensuring equivalence on both sides of the equation confirms that transformations or operations on the inputs yield the same output.
Substitution in Functions
Substitution is a technique used in mathematics to check the behavior or properties of functions by replacing variables with specific values or expressions. This method is particularly helpful in demonstrating properties like the equality or relationships between different function forms.
In the given problem, substitution was used to verify function characteristics:
1. For proving \(3f(x) = f(x+1)\), substituting \(x \) into the functions maintains equivalence on both sides of the equation.
2. To verify \(f(a+b) = f(a) \cdot f(b)\), substitute \(a+b\) directly into the function to unlock an exponent rule \(3^{a+b} \). Then substitute individual terms, recognizing that \(3^a = f(a)\) and \(3^b = f(b)\), which reconfirms the equation.
Substitution allows us to simplify complex expressions and validate their truth. By breaking down expressions into manageable parts, substitution helps refine our understanding of function properties.

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