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Potts and Manooch \(^{86}\) studied the growth habits of graysby groupers. These groupers are important components of the commercial fishery in the Caribbean. The mathematical model they created was given by the equation \(L(t)=446(1-\) \(e^{-0.13[t+1.51]}\), where \(t\) is age in years and \(L\) is length in millimeters. Graph this equation. Find the age at which graysby groupers reach \(200 \mathrm{~mm}\).

Short Answer

Expert verified
Graysby groupers reach 200 mm at approximately 3.05 years old.

Step by step solution

01

Rewrite the Model Equation

The problem provides the equation \( L(t) = 446(1 - e^{-0.13(t + 1.51)}) \). Before graphing or calculating, ensure you understand the components: \( L(t) \) represents length in millimeters, and \( t \) is age in years.
02

Graph the Equation

To graph the equation, plot \( L(t) = 446(1 - e^{-0.13(t + 1.51)}) \) with \( t \) on the x-axis and \( L(t) \) on the y-axis. This will show the relationship between age and length for graysby groupers. Use a computational tool or graphing calculator to plot it across a reasonable age range (e.g., 0 to 20 years).
03

Set Equation for 200 mm

To find the age \( t \) where the length \( L(t) \) is 200 mm, set the equation equal to 200: \( 200 = 446(1 - e^{-0.13(t + 1.51)}) \).
04

Isolate the Exponential Component

Solve the equation \( 200 = 446(1 - e^{-0.13(t + 1.51)}) \) for the exponential part: divide both sides by 446 to get \( 1 - e^{-0.13(t + 1.51)} = \frac{200}{446} \).
05

Solve for Exponential Term

Rearrange to find the exponential component: \( e^{-0.13(t + 1.51)} = 1 - \frac{200}{446} \). Calculate \( 1 - \frac{200}{446} \) to find \( e^{-0.13(t + 1.51)} = 0.5524 \).
06

Apply Natural Logarithms

Take the natural logarithm of both sides to isolate \( t \): \( \ln(e^{-0.13(t + 1.51)}) = \ln(0.5524) \). This simplifies to \(-0.13(t + 1.51) = \ln(0.5524) \).
07

Solve for t

Divide both sides by -0.13 to solve for \( t \): \( t + 1.51 = \frac{\ln(0.5524)}{-0.13} \). Calculate \( \ln(0.5524) \approx -0.5932 \) and \( \frac{-0.5932}{-0.13} \approx 4.56 \).
08

Find Specific Age

Subtract 1.51 from 4.56 to find \( t \, \), which is \( t = 4.56 - 1.51 = 3.05 \). The graysby groupers reach 200 mm at approximately 3.05 years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Growth
Population growth is a fascinating concept that applies not only to communities of people but also to all living organisms, like our graysby groupers. In the context of the groupers, we're looking at how they increase in size as they age. This type of growth is commonly modeled using exponential functions because many living organisms grow rapidly during certain life stages and then plateau. Exponential growth can be observed when the rate of growth is proportional to the current size, meaning the larger they get, the more they grow each year. Although the graysby group's growth rate eventually slows, the early stages follow such a pattern. Understanding population growth models helps fisheries manage and sustain populations effectively. By knowing the age at which groupers reach a certain size, decisions about fishing regulations and conservation efforts can be better informed.
Mathematical Modeling
Mathematical modeling involves representing real-world phenomena with mathematical formulas. In our exercise, the growth of graysby groupers is represented by the function: \[ L(t) = 446\left(1 - e^{-0.13(t + 1.51)}\right) \] This model provides a mathematical framework to predict the growth pattern of the fish over time. Here:
  • \( L(t) \) is the length of the fish at a given age.
  • \( t \) is the age in years.
  • The constant \( 446 \) indicates the maximum length the fish can attain.
  • The term \( e^{-0.13(t + 1.51)} \) constrains the growth rate.
Mathematical modeling allows for predictions about unseen situations, such as determining when the grouper will reach a certain length. It also aids in visualizing potential outcomes and adjusting models if real-world data changes, making it incredibly valuable for scientific research and practical applications.
Graphing Functions
Graphing functions is a powerful way to visualize the relationship between variables. In the context of population growth seen with graysby groupers, graphing the equation \( L(t) = 446\left(1 - e^{-0.13(t + 1.51)}\right) \) allows us to observe how the groupers grow over time.When we plot this graph with age \( t \) on the x-axis and length \( L(t) \) on the y-axis:
  • We see how quickly the fish grow in their early years.
  • The curve gradually levels off as it approaches the maximum length.
  • This shape helps us understand the dynamics of the growth process.
Using graphing tools, such as graphing calculators or software programs, makes this process easier, offering clear insights by showing exactly at what point certain lengths are achieved. Graphing not only aids in understanding the current scenario but also emphasizes the importance of analyzing mathematical models to track and predict behavior in natural settings.

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