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Rate Hartman \(^{83}\) created a mathematical model of the gastric evacuation rate of striped bass and gave the equation \(P(t)=100 e^{-0.12 t},\) where \(t\) is time in hours and \(P\) is the percentage of full stomach. How many hours until the stomach is half full?

Short Answer

Expert verified
The stomach is half full after approximately 5.77 hours.

Step by step solution

01

Understand the Problem

We want to find the time \( t \) when the stomach is half full, meaning \( P(t) = 50 \). The given equation is \( P(t) = 100e^{-0.12t} \).
02

Setting Up the Equation

Substitute \( P(t) = 50 \) into the equation to get \( 50 = 100e^{-0.12t} \).
03

Simplifying the Equation

Divide both sides by 100 resulting in \( 0.5 = e^{-0.12t} \).
04

Taking the Natural Logarithm

Take the natural logarithm (ln) of both sides to get \( \ln(0.5) = -0.12t \).
05

Solve for \( t \)

Divide both sides by -0.12 to isolate \( t \): \( t = \frac{\ln(0.5)}{-0.12} \).
06

Calculating \( t \)

Use a calculator to find \( \ln(0.5) \approx -0.6931 \), and then compute \( t = \frac{-0.6931}{-0.12} \approx 5.77 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Modeling
Mathematical modeling is the process of creating a mathematical representation of a real-world phenomenon to predict and understand its behavior. In our case, Rate Hartman developed a model to describe the gastric evacuation rate of striped bass. This is achieved by using mathematical equations to describe the relationship between different variables—in this case, time and the percentage of full stomach.

Mathematical models can be beneficial in various fields, as they help us make informed decisions by simulating potential outcomes. These models allow for understanding the dynamics of complex systems in an easy-to-digest way. For instance, they can help us estimate how long it takes for a fish to digest half its stomach content, which is central to our problem here.
Exponential Decay
Exponential decay refers to the process of reducing an amount by a consistent percentage rate over a period of time. The formula often used is of the form: \[ N(t) = N_0 \, e^{-kt} \] where:
  • \( N(t) \) is the quantity that remains at time \( t \).
  • \( N_0 \) is the initial quantity.
  • \( k \) is the decay constant.
  • \( t \) is time.

In our equation, \( P(t) = 100e^{-0.12t} \), the initial quantity \( N_0 \) is 100%, and the decay constant \( k \) is 0.12.

Exponential decay illustrates how quickly a quantity decreases over time. This is crucial to understand as it directly applies to how the striped bass consumes and utilizes its gastric contents. By knowing this decay process, predictions on digestion patterns can be accurately made.
Natural Logarithms
Natural logarithms, denoted as \( \ln \), are logarithms to the base \( e \), where \( e \approx 2.71828 \). These logarithms are particularly useful in continuous growth or decay processes, such as our current model of gastric evacuation.

When solving problems involving exponential decay, we often take the natural logarithm of both sides to simplify and solve equations. For instance, after establishing the equation \( 0.5 = e^{-0.12t} \), taking the natural logarithm allows us to isolate \( t \): \[ \ln(0.5) = -0.12t \]This helps in precisely determining the time it takes for the stomach to be half-full by solving for \( t \).
Striped Bass Gastric Evacuation
Striped bass gastric evacuation refers to the process by which striped bass competes their digestion, leading to a decrease in stomach contents over time. This process is often modeled mathematically due to its significance in understanding fish behavior, consumption rates, and ecological impacts.

By studying the gastric evacuation rate, one can estimate how long it takes for the striped bass's stomach to be half full after feeding. Understanding these rates can inform fishery management decisions and ecological research. The use of mathematical models allows researchers to predict and monitor these natural processes, providing valuable insights without constant physical observation.

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