/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Solve the equation for \(x\). ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the equation for \(x\). \(e^{\sqrt{x}}=4\)

Short Answer

Expert verified
\(x = (\ln(4))^2\)

Step by step solution

01

Understand the Problem

We need to solve the equation \(e^{\sqrt{x}} = 4\) for the variable \(x\). This equation involves an exponential function where the base is Euler's number \(e\) and the exponent is \(\sqrt{x}\).
02

Apply the Natural Logarithm

To isolate \(\sqrt{x}\), we take the natural logarithm of both sides of the equation. Recall that the natural logarithm, denoted as \(\ln\), is the inverse of the exponential function. This gives us: \(\ln(e^{\sqrt{x}}) = \ln(4)\).
03

Simplify using Logarithmic Identity

Use the logarithmic identity \(\ln(e^a) = a\) to simplify the left side. This results in \(\sqrt{x} = \ln(4)\).
04

Solve for x

Square both sides to solve for \(x\). This gives us \(x = (\ln(4))^2\).
05

Calculate the Value

Calculate \(\ln(4)\) using a calculator to find its approximate value, and then square that result. Thus, \(x \approx (1.386)^2 \approx 1.922\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, often written as \( \ln \), is a fundamental mathematical function used to simplify and solve exponential equations. It is the inverse of the exponential function whose base is Euler's number \( e \), where \( e \approx 2.718 \). This means that if you take the natural log of a number that is an exponential function of \( e \), the exponent is revealed. For example, \( \ln(e^a) \) simplifies directly to \( a \).

Using the natural logarithm allows us to transform equations in ways that make solving for unknown variables more straightforward. By introducing the natural logarithm onto both sides of an equation such as \( e^{\sqrt{x}} = 4 \), we effectively balance the equation so we can solve for the variable inside the exponent. This step moves us closer to isolating and identifying the unknown variable, which is often the key aim in solving equations.
Euler's Number
Euler's number, denoted commonly as \( e \), is a mathematical constant approximately equal to 2.71828. It is the base of the natural logarithm and is named after the Swiss mathematician Leonhard Euler. This number holds great significance in many areas of mathematics and science, particularly in growth processes, such as populations and economies, and in solving differential equations.

One fascinating characteristic of Euler's number is that it is irrational, which means it cannot be expressed fully as a simple fraction. Its value is derived from various formulas and sequences but commonly introduced through the exponential function \( e^x \). In contexts like our problem, Euler’s number serves as the base for the exponential expression \( e^{\sqrt{x}} \). Such expressions often represent natural growth processes or, in our case, need natural logarithms to be simplified.
Solving Equations
Solving equations involving exponential functions usually requires several strategic simplification steps. In our problem, \( e^{\sqrt{x}} = 4 \), we aim to find the value of \( x \). Here’s a brief walkthrough:
  • Apply the natural logarithm to both sides to remove the exponent of \( e \). This is the first simplification step and helps us solve for the variable within the exponential expression.
  • This leads us to \( \ln(e^{\sqrt{x}}) = \ln(4) \). Using the logarithmic identity \( \ln(e^a) = a \), the equation simplifies to \( \sqrt{x} = \ln(4) \).
  • Finally, to isolate \( x \), square both sides of the equation, resulting in \( x = (\ln(4))^2 \).
  • Complete the calculation by finding \( \ln(4) \), approximately equal to 1.386, and squaring it to get the final result \( x \approx 1.922 \).
Understanding each step of the simplification process is important for solving more complex equations, as it illustrates how to manipulate and transform equations flexibly.

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Most popular questions from this chapter

Potts and Manooch \(^{70}\) studied the growth habits of graysby groupers. These groupers are important components of the commercial fishery in the Caribbean. The mathematical model that they created was given by the equation \(L(t)=446\left(1-e^{-0.13[t+1.51]}\right),\) where \(t\) is age in years and \(L\) is length in millimeters. Graph this equation. What seems to be happening to the length as the graysby become older? Potts and Manooch also created a mathematical model that connected length with weight and was given by the equation \(W(L)=8.81 \times 10^{-6} \cdot L^{3.12},\) where \(L\) is length in millimeters and \(W\) is weight in grams. Find the length of a 10 -year old graysby. Find the weight of a 10 -year old graysby.

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Let \(f(x)=x^{2} .\) Find \(x\) such that \(f(x+1)=f(x+2)\).

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