/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 In Exercises 25 through \(38,\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises 25 through \(38,\) solve for \(x\). $$ 3^{x}=\frac{1}{3} $$

Short Answer

Expert verified
x = -1

Step by step solution

01

Understand the Equation

The given equation is \(3^x = \frac{1}{3}\). We suspect we'll need to use properties of exponents to solve for \(x\).
02

Express Right Side with Base 3

Recognize that \(\frac{1}{3}\) is the same as \(3^{-1}\). So, rewrite the equation as \(3^x = 3^{-1}\).
03

Set the Exponents Equal

Since both sides of the equation have the same base, set the exponents equal to each other: \(x = -1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Properties of Exponents
Understanding the properties of exponents is key when working with exponential equations. Exponents are a shorthand way to denote repeated multiplication. For example, if we have an expression like \(3^x\), it represents the number 3 multiplied by itself \(x\) times. When solving exponential equations, such as \(3^x = \frac{1}{3}\), we often need to manipulate the exponents to simplify the equation.Here are a few essential properties of exponents:
  • Same Base Equality: If \(a^m = a^n\), then \(m = n\). This means that if you have the same base on both sides, you can just set the exponents equal.
  • Negative Exponents: An expression like \(a^{-m}\) translates to \(\frac{1}{a^m}\). This is crucial in the given exercise where \(\frac{1}{3}\) equals \(3^{-1}\).
  • Product of Powers: The expression \(a^m \cdot a^n = a^{m+n}\) allows you to combine exponents.
Having a good grip on these properties makes solving exponent problems much simpler.
Solving for Variables
When tackling an exponential equation, the ultimate goal is to solve for the unknown variable, which in this case is \(x\). With the equation \(3^x = \frac{1}{3}\), our first task is to express both sides with the same base. This allows us to make direct comparisons and solve for \(x\).Once we rewrite the equation such that both sides have the same base, as in \(3^x = 3^{-1}\), we can utilize the property of equality for exponents. This instructs us to set the exponents equal to each other, making \(x = -1\).Having determined the value of \(x\), it's always a good practice to substitute it back into the original equation to verify correctness. This ensures that our solution accurately satisfies the initial problem condition.
Algebraic Manipulation
Algebraic manipulation refers to the use of mathematical operations to rearrange and simplify equations. In our problem, we started with the equation \(3^x = \frac{1}{3}\). To solve it, we needed to express both sides using the same base, which is a form of algebraic manipulation.Here are the steps of manipulation used in this problem:
  • Recognize reciprocal expressions: Realize that \(\frac{1}{3}\) can be rewritten as \(3^{-1}\). This changes the structure of the equation, but not its value.
  • Equalizing bases: By converting both sides to the base of 3, the exponent \(x\) and \(-1\) on the right can be compared directly.
Such algebraic techniques are fundamental tools in solving equations, enabling us to transform complex expressions into simpler forms that are easier to analyze and solve.

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Most popular questions from this chapter

Kaakeh and colleagues \(^{50}\) showed that the amount of photosynthesis in apple leaves in appropriate units was approximated by \(y=19.8+0.28 x-0.004 x^{2},\) where \(x\) is the number of days from an aphid infestation. Determine the number of days after the infestation until photosynthesis peaked.

A farmer wishes to enclose a rectangular field of an area of 200 square feet using an existing wall as one of the sides. The cost of the fencing for the other three sides is \(\$ 1\) per foot. Find the dimensions of the rectangular field that minimizes the cost of the fence.

If you use the quadratic function \(C(x)=\) \(a x^{2}+b x+c\) to model costs on a very large interval, what sign should the coefficient \(a\) have? Explain carefully.

Crafton \(^{61}\) created a mathematical model of demand for northern cod and formulated the demand equation $$ p(x)=\frac{173213+0.2 x}{138570+x} $$ where \(p\) is the price in dollars and \(x\) is in kilograms. Graph this equation. Does the graph have the characteristics of a demand equation? Explain. Find \(p(0),\) and explain what the significance of this is.

Potts and Manooch \(^{71}\) studied the growth habits of coney groupers. These groupers are important components of the commercial fishery in the Caribbean. The mathematical model that they created was given by the equation \(L(t)=385(1-\) \(e^{-0.32[t-0.49]}\), where \(t\) is age in years and \(L\) is length in millimeters. Graph this equation. What seems to be happening to the length as the coneys become older? Potts and Manooch also created a mathematical model that connected length with weight and was given by the equation \(W(L)=2.59 \times 10^{-5} \cdot L^{2.94},\) where \(L\) is length in millimeters and \(W\) is weight in grams. Find the length of a 10 -year old coney. Find the weight of a 10 -year old coney.

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