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Find the domain of each function. $$ \frac{x-1}{x^{2}-5 x+6} $$

Short Answer

Expert verified
The domain is \((-\infty, 2) \cup (2, 3) \cup (3, \infty)\).

Step by step solution

01

Identify the Denominator

The given function is \( \frac{x-1}{x^{2}-5x+6} \). To find the domain, we need to ensure that the denominator is not equal to zero. Start by identifying the denominator: \( x^2 - 5x + 6 \).
02

Set the Denominator to Zero

To find the values of \( x \) that make the denominator zero, set the equation \( x^2 - 5x + 6 = 0 \). This will help us find the points to exclude from the domain.
03

Factor the Quadratic Equation

The quadratic \( x^2 - 5x + 6 \) can be factored into \( (x-2)(x-3) = 0 \). These factors give us the potential values of \( x \) that could make the denominator zero.
04

Solve for Zeroes

Set each factor equal to zero: \( x-2 = 0 \) and \( x-3 = 0 \). Solving these gives \( x = 2 \) and \( x = 3 \), respectively. These are the values that make the denominator zero.
05

Write the Domain in Interval Notation

Since the function is undefined at \( x = 2 \) and \( x = 3 \), these values are excluded from the domain. Therefore, the domain in interval notation is \( (-\infty, 2) \cup (2, 3) \cup (3, \infty) \). The function is defined for all other real numbers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
A rational function is defined as the quotient of two polynomials. In simpler terms, it's a fraction where the numerator and the denominator are both polynomials. For example, the function \( \frac{x-1}{x^{2}-5x+6} \) is a rational function. Here, \( x-1 \) is the numerator and \( x^2-5x+6 \) is the denominator.

One key aspect of rational functions is that they are not defined everywhere in the set of real numbers. The function becomes undefined at any value of \( x \) that makes the denominator zero. This is an important part of determining the function's domain.

To find where a rational function is undefined, you need to solve the equation where the denominator equals zero. This process identifies the values of \( x \) that are not in the domain. Once these values are known, they can be excluded from the set of real numbers to form the domain of the function. Understanding these exclusions is crucial whenever you're working with rational functions.
Quadratic Equations
Quadratic equations are polynomial equations of the second degree. They are usually in the form of \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. The solutions to these equations are known as the 'roots'.

To solve a quadratic equation, one common method is factoring. This involves rewriting the quadratic in a form where it can be split into two binomials. In the example \( x^2 - 5x + 6 \), it factors into \( (x-2)(x-3) \).
  • Setting each factor equal to zero, \( x-2 = 0 \) and \( x-3 = 0 \), provides the solutions or roots.
  • Solving these gives the values \( x = 2 \) and \( x = 3 \).
These solutions are particularly significant when they appear in the denominator of a rational function because they mark the points where the function is undefined. Therefore, including or excluding these solutions from the domain in subsequent steps is vital for accurately determining the domain.
Interval Notation
Interval notation is a mathematical notation used to represent subsets of real numbers. It provides a clear visual format to express the domain or range of a function.

In interval notation, brackets and parentheses are used to denote the inclusion or exclusion of endpoints.
  • '(' or ')' means that the endpoint is not included, also known as open interval.
  • '[' or ']' indicates that the endpoint is included, known as closed interval.
In the exercise example, the function \( \frac{x-1}{x^{2}-5x+6} \) is undefined at \( x = 2 \) and \( x = 3 \). Thus, the domain excludes these points and is written in interval notation as \( (-\infty, 2) \cup (2, 3) \cup (3, \infty) \).

Using interval notation helps to succinctly communicate which values are included in the domain of a function, providing an efficient way to express complex restrictions on input values.

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Most popular questions from this chapter

Using your grapher, graph on the same screen \(y_{1}=\) \(f(x)=|x|\) and \(y_{2}=g(x)=\sqrt{x^{2}} .\) How many graphs do you see? What does this say about the two functions?

Suppose the demand equation for a commodity is of the form \(p=m x+b\), where \(m<0\) and \(b>0\). Suppose the cost function is of the form \(C=d x+e\), where \(d>0\) and \(e<0 .\) Show that profit peaks before revenue peaks.

Pine and Allen \(^{89}\) studied the growth habits of sturgeon in the Suwannee River, Florida. The sturgeon fishery was once an important commercial fishery but, because of overfishing, was closed down in \(1984,\) and the sturgeon is now both state and federally protected. The mathematical model that Pine and Allen created was given by the equation \(L(t)=222.273(1-\) \(\left.e^{-0.08042[t+2.181}\right),\) where \(t\) is age in years and \(L\) is length in centimeters. Graph this equation. Find the expected age of a 100 -cm-long sturgeon algebraically.

Revenue Suppose that a firm's annual revenue function is given by \(R(x)=20 x+0.01 x^{2},\) where \(x\) is the number of items sold and \(R\) is in dollars. The firm sells 1000 items now and anticipates that its sales will increase by 100 in each of the next several years. If \(t\) is the number of years from now, write the number of sales as a function of \(t\) and also write the revenue as a function of \(t\).

Potts and Manooch \(^{71}\) studied the growth habits of coney groupers. These groupers are important components of the commercial fishery in the Caribbean. The mathematical model that they created was given by the equation \(L(t)=385(1-\) \(e^{-0.32[t-0.49]}\), where \(t\) is age in years and \(L\) is length in millimeters. Graph this equation. What seems to be happening to the length as the coneys become older? Potts and Manooch also created a mathematical model that connected length with weight and was given by the equation \(W(L)=2.59 \times 10^{-5} \cdot L^{2.94},\) where \(L\) is length in millimeters and \(W\) is weight in grams. Find the length of a 10 -year old coney. Find the weight of a 10 -year old coney.

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